Title: Everyday Forces
1Everyday Forces
2Weight
- Weight the magnitude of the force of gravity
acting on an object.
3Normal Force
- Normal Force (FN) a force exerted by one object
on another in a direction perpendicular to the
surface of contact.
4Normal Force
- To calculate FN, multiply the weight of the
object with cosine ?, where ? is the angle
between the normal force and a vertical line, and
also the angle between the contact force and a
horizontal line.
5Normal Force
- If the surface is horizontal, then ? is 0º, and
cos 0º 1, and
6Friction
- Friction opposes the applied force.
- Friction can be categorized as being either
static or kinetic.
7Friction
- Static Friction the resistive force that
opposes the relative motion of two contacting
surfaces that are at rest with respect to one
another. - The force needed to start movement is Fs max.
8Friction
- Kinetic Friction the resistive force that
opposes the relative motion of two contacting
surfaces that are moving past one another. - The force needed to keep the object moving is Fk.
9Friction
- Fk lt Fs max
- The force of friction is proportional to the
normal force. - Friction depends on the surfaces in contact.
10Friction
- Coefficient of Friction the ratio of the force
of friction to the normal force acting between
two objects.
11Coefficients of Friction
Fs max 75 N
m 24 kg
Sample Problem 4CA 24 kg crate initially at rest
on a horizontal floor requires a 75 N horizontal
force to set it in motion. Find the coefficient
of static friction between the crate and the
floor.
12Coefficients of Friction
Given m 24 kg Fs max 75
N Unknown µs ?
13Overcoming Friction
Sample Problem 4DA student moves a box of books
by attaching a rope to the box and pulling with a
force of 90.0 N at an angle of 30.0?, as shown in
the picture. The box of books has a mass of 20.0
kg, and the coefficient of kinetic friction
between the bottom of the box and the sidewalk is
0.50. Find the acceleration of the box.
14Overcoming Friction
Given m 20.0 kg F applied
90.0 N ? 30.0? µk 0.50 Unknown a ?
15Overcoming Friction
Given m 20.0 kg F applied
90.0 N ? 30.0? µk 0.50 Unknown a ?
16Overcoming Friction
F applied y F applied sin? F applied y (90.0
N) sin30.0? F applied y 45.0 N
F applied 90.0 N
? 30.0? F applied x F applied cos? F applied
x (90.0 N) cos30.0? F applied x 77.9 N
17Overcoming Friction
F g mg F g 20.0 kg x 9.81m/s2 F g 196 N
(downward)
18Overcoming Friction
The box does not fly in the air!
19Overcoming Friction
Solving for kinetic friction
20Overcoming Friction
The box is moving horizontally.
21Section 4 - 4Everyday Forces
- Assignment
- Practice 4C p 145 1-3
- Practice 4D p 147 1-4
- Section Review p 149 1-5