Title: Horizontal Diaphragms
1Horizontal Diaphragms
- by Bart Quimby, P.E., Ph.D
- UAA Civil Engineering
- CE 434 - Timber Design
2Lateral Forces
- Lateral forces result from either wind loading or
seismic motion. - In either case, the diaphragms are generally
loaded with distributed loads. - The example here is more closely associated with
wind loading.
3The Building
4Tributary Areas
5Loadings for Roof Diaphragm
- The upper beam diagram is for loading in the
2 direction. - The lower beam diagram is for loading in the
1 direction. - The distributed loads equal the pressure times
the tributary height of the exposed area. - The unit shears equal the beam reaction divided
by the length of the edge.
6Loadings for Floor Diaphragm
- Note that the unit shears at the ends of the
diaphragm are the result of the interaction with
the shear walls that are providing lateral
support for the diaphragm. - These forces are transferred to the shear walls.
7Elements for Direction 1
8Idealized Diagram for Dir. 1
- Green arrows are unit shears at edge of roof
diaphragm. - Yellow arrows are unit shears at edge of floor
diaphragm. - Shear in upper part of shear wall is from roof
diaphragm only. - Shear (red arrows )in lower part of shear wall
includes both horizontal diaphragms.
9Shear Wall Free Body Diagram
10Elements for Direction 2
11Idealized Diagram for Dir. 2
- Green arrows are unit shears at edge of roof
diaphragm. - Yellow arrows are unit shears at edge of floor
diaphragm. - Shear in upper part of shear wall is from roof
diaphragm only. - Shear (red arrows )in lower part of shear wall
includes both horizontal diaphragms.
12Shear Wall Free Body Diagram
13Another View
Amrhein, James E Reinforced Masonry Engineering
Handbook, 4th edition
14Diaphragms are Beams
- Like beams, diaphragms carry loads in bending.
- Wood diaphragms are considered to be simply
supported. - This results in both internal bending moment and
shear. - The diaphragm can be considered to be similar to
a wide flange beam where the flanges (diaphragm
chords) take all the bending and the web (the
plywood sheathing) takes all the shear. - In diaphragms, the shear force is expressed in
terms of unit shear.
15Beam Behavior of Diaphragms
Amrhein, James E Reinforced Masonry Engineering
Handbook, 4th edition
16Diaphragm Forces in Dir. 1
C M / L1
M w(L2)2/8
v w(L2)/(2L1)
T M / L1
- Unit shear, v, equals the shear force, V, at a
location along the span divided by the depth of
the diaphragm at that location. - Moment is taken by chord forces whose magnitudes
equal the Moment at a particular location
divided by the diaphragm depth at the same
location.
17Diaphragm Forces in Dir. 2
v w(L2)/(2L1)
- The diaphragm must be analyzed and designed to
handle the forces in both principle directions.
M
C M / L2
T M / L2
18Maximum Diaphragm Ratios2003 IBC
- IBC Table 2305.2.3 (text pg C.42) - Rules of
Thumb used to control diaphragm deflections. - If the span to width ratios are too large, then
the diaphragm is not stiff enough to transfer the
forces without significant deflection. - Deflection is a function of beam bending, shear
deflection, nail slip in diaphragm and slip in
chord connections.
19Shear Capacity of Horizontal Wood Diaphragms2003
IBC
- UBC Table 2306.3.1 (pgs C.45-C.47)
- Also see Special Design Provisions for Wind
Seismic Table A.4.2A - Shear capacity depends on the following design
variables - supporting member species
- plywood grade
- nail size (and penetration)
- plywood thickness (normally selected for vert.
loads) - support widths
- nail spacing
- blocking
- layup
20Footnote a
- Use of supporting lumber species other than
Douglas Fir or Southern Pine - (1) find specific gravity of supporting framing
(see NDS Table 11.3.2A, NDS pg 74) - For Staples Use Structural I values multiplied
by either 0.82 or 0.65 depending on specific
gravity of supporting members. - For Nails Use values from table for actual
grade of plywood used multiplied by
min(.5S.G),1
21Footnote b
- Field nailing requirement
- Spacing of fasteners along intermediate framing
to be 12 O.C. unless supporting member spacing
equals 48 or more, then use 6 O.C. nail spacing.
22Use With Wind Loads
- IBC-03 2306.3.1 states
- The allowable shear capacities in Table 2306.3.1
for horizontal wood structural panel diaphragms
shall be increased 40 percent for wind design
23Some Definitions
- Nailing
- Boundary nailing Nailing at all intersections
with shear walls. (parallel to direction of
force.) - Edge nailing nailing along any other supported
plywood edge. - Field nailing nailing along supports but not at
a plywood edge. - Layup cases (See IBC Table 2306.3.1)
24Nailing Definitions
25Chord Design
- The chords are axial force members that generally
have full lateral support in both principle
directions. - The top plates of the supporting walls are
generally used as the chord members. - Due to the reversing nature of the loads being
resisted, the chord forces are considered to be
both tension and compression. - Design as an axial force member.
26Typical Chord
27Example
- Consider the building introduced in the lecture
on structural behavior
We spent some time determining forces in the
horizontal and vertical diaphragms (shear walls)
in an earlier lecture.
28Applied Forces Wind
Direction 1 Roof 12,000 200 plf 2nd flr
6,300 105 plf
Direction 2 Roof 5,200 60 plf to 200
plf 2nd flr 4,200 105 plf
29Roof Diaphragm Direction 1
- Parameters
- ½ C-DX plywood
- 2x Hem Fir Framing
- Vmax 150 plf
- Case I layup
- Design nailing for the diaphragm (IBC)
- Unblocked, 8d nails
- Vallow 1.4240 (1-(.5-.43))
- Vallow 313 plf gt Vmax
30Roof Diaphragm Direction 2
- Parameters
- ½ C-DX plywood
- 2x Hem Fir Framing
- Vmax 43.3 plf
- Case 3 layup
- Design nailing for the diaphragm
- Unblocked, 8d nails
- Vallow 1.4180(1-(.5-.43))
- Vallow 234 plf gt Vmax
31Roof Diaphragm Sheathing Summary
- After determining the needs in each direction the
design of the roof can be specified.
- Result
- ½ C-DX plywood
- Unblocked
- 8d _at_ 6 O.C. Edge and Boundary nailing
- 8d _at_ 12 O.C. Field nailing
32Roof Diaphragm Chords Direction 1
- Moment 90 ft-k
- Depth 40 ft
- Chord Force 2.25 k
33Roof Diaphragm Chords Direction 2
- Moment 82.7 ft-k
- Depth 60 ft
- Chord Force 1.38 k
34Chord DesignHem Fir 2
- Try (1) 2x4
- Check Tension
- Ft (525 psi)(1.6)(1.5)
- Ft 1260 psi
- ft 2250 / 5.25 in2
- ft 429 psi lt Ft
- Try (1) 2x4
- Check Compression
- Fc (1300 psi)(1.6)(1.15)
- Fc 2392 psi
- fc 2250 / 5.25 in2
- fc 429 psi lt Fc
(1) 2x4 is adequate in both directions