Title: Mesh Analysis
1Mesh Analysis
2Example 1
3Using Mathcad
4Using PSpice
I1 -1818 A
I2 -6.364 A
5Example 2 By Inspection
6Using Mathcad By Inspection
7Using PSpice
8Example 3
9Using Mathcad
Mesh 1
10Using PSpice
I1 250 mA
11Example 4 Supermesh
Mesh 1 and mesh 2 form supermesh
I2 4.4 A
I1 -1.6 A
Ans
12Using Mathcad
13Using PSpice
I1 -1.6 A
I2 4.4 A
Ans
14Example 5 Supermesh
15Example 5 Supermesh
I3 -1.81A
I2 -3.621A
I1 5.431A
Ans
16Using Mathcad equations
17Using Mathcad Results
18Using PSpice
I3 -1.81A
I2 -3.621A
I1 5.431A
Ans
19Problem 1
Find Va and Ix
20Using Mathcad
21To Find Ix
Ix -I1 -3.474 A
22To Find Va
V2
V4
-
-
V1
-
V8
-
Mesh 1 -6(I1-I3)?2(1 ? 3)Va 0
Mesh 2 -(1 ? 3) (I2-I3)48I2-Va 0
or
Va -1.737V
23Problem 2
2Ia
10
-
I3
Ia
x
y
40
8
Ib
-
5A
I2
80
I1
Vc
20V
5A
2.5Ib
Find Vxy, Vc, and the power absorbed by all
elements.
24Using Mathcad Equations
25Using Mathcad Results
26To Find Vxy
2Ia
10
-
I3
Vxy
x
y
-
Ib
-
5A
I2
80
I1
Vc
20V
5A
2.5Ib
-Vxy-2Ia10I3 0
Vxy, Vc
Vxy -2Ia10I3
27To Find Vc
2Ia
10
-
I3
x
y
40
-
V40
Ib
-
5A
I2
80
I1
Vc
20V
5A
2.5Ib
Vc(I2-I3)40-20 0
Vc -(I2-I3)4020
28Power absorbed by active elements
2Ia
10
-
I3
Ia
x
y
40
8
-
Ib
-
5A
V5A
I2
80
I1
Vc
20V
5A
2.5Ib
For the active elements, we have to follow PSC to
calculate the power absorbed.
29Power absorbed by passive elements
2Ia
-
I3
10
Ia
x
40
8
-
Ib
-
5A
V5A
I2
80
I1
Vc
20V
5A
2.5Ib
The power absorbed by the resistor is always
positive we can always use P I2R
30Power absorbed by all elements