Title: Motion in Two and Three Dimensions
1Chapter-4
- Motion in Two and Three Dimensions
2Ch 4-2 Position and Displacement in Two and
Three Dimensions
- Position vector r in three dimension
- r xi yj zk
- x -3 m, y 2m and z5m
3Ch 4-2 Position and Displacement in Three
Dimensions
- Displacement ?r
- ?r r2-r1
- where r1 x1iy1jz1k
- r2 x2iy2jz2k
- ?r (x2- x1) i (y2- y1) j (z2 z1) k
- ?r (?x) i (?y) j (?z)
- ?x x2- x1 ?y y2- y1 ?z z2- z1
4Checkpoint 4-1
- ?r (?x)i (?y)j (?z)k
- ?x 6-(-2)8
- ?y -2-4 -6
- ?z -3-(-3)0
- ?r 8i - 6j
- (b) The displacement vector ?r is parallel to xy
plane
- (a) If a wily bat flies from xyz coordinates (
-2m, 4 m, -3 m) to coordinates ( 6 m, -2 m, -3
m), what is its displacement ?r in unit vector
notation? - (b) Is ?r paralell to one of the three
coordinates planes? If so, which one?
5Ch 4-3 Average and Instantaneous Velocity
- Average velocity vavg
- vavg displacement/time interval
- vavg ?r /?t
- ?r/?t (?x/?t) i (?y/?t) j (?z/?t)k
- Instantaneous velocity v
- v dr/dt
- v (dx/dt) i (dy/dt) j (dz/dt) k
- vvxivyjvzk
- Direction of v always tangent to the particle
path at the particle position
6Checkpoint 4-1(new book)
- The figure shows a circular path taken by a
particle. If the instantaneous velocity of the
paticle is v (2 m/s) i- (2 m/s) j - , through which quadrant is the particle moving
at that instant if it is traveling - (a) clockwise
- (b) counterclockwise around the circle?
- Ans v (2 m/s) i- (2 m/s) j
- (a) clockwise motion
- vx ve and vy -ve only in
- First quadrant
- (b) counterclockwise motion
- vx ve and vy -ve only in
- Third quadrant
7Ch 4-4 Average and Instantaneous Acceleration
- Average acceleration aavg
- aavg change in velocity/time
- aavg ?v/?t (v2-v1)/ ?t
- Instantaneous acceleration a
- a dv/dt
- a (dvx/dt)i (dvy/dt)j (dvz/dt)k
- aaxiayjazk
8Checkpoint 4-2
- (1) d2x/dt2 -6 , d2y/dt212
- (2) d2x/dt2 -18 t ,d2y/dt2-10
- (3) d2r/dt2 4 i ,
- (4) d2r/dt2 24 t i ,
- ax is constant for 1 and 3,ay is constant for
both ay is so a is constant - ax is not constant for 2 and 4 while ay is
constant. Hence a is not constant for case 2 and 4
- Here are four description of the positions of a
puck as it moves in the XY plane - (1) X -3t24t-2 and y 6t2 4t
- (2) X -3t3 -4t and Y -5t2 6
- (3) r 2t2 i (4t 3) j
- (4) r (4t3 -2)i 3 j
9Checkpoint 4-4
- r(4t3-2t)i3j
- 4t3i-2ti3j
- Since units of 4t3-2t and 3 has to be meter then
- Unit of 4 is m/s2
- Unit of -2 is m/s
- Unit of 3 is m
- If the position of a hobos marble is given by
- r(4t3-2t)i3j, with r in meters and t in
seconds, what must be the units of coefficients
4, -2 and 3?
10Ch 4-5 Projectile Motion
- Motion in two dimension
- Horizontal motion (along x-axis ) with constant
velocity, ax0 - Vertical motion (along y-axis) with constant
acceleration ay g - Horizontal motion and the vertical motion
independent of each other - v0v0xiv0yj
- v0xv0 cos? v0yv0 sin?
11Ch 4-5 Projectile Motion
- Horizontal motion
- x-x0v0xt v0cos?t
- Horizontal Range R
- R is the horizontal distance traveled by the
projectile when it has returned to its initial
launch height - R v0 cos? t (v02sin2?)/g
- Rmaxv02/g (?45?)
12Ch 4-6 Projectile Motion Analyzed
- Vertical motion
- y-y0v0yt gt2/2
- v0 sin?t gt2/2
- vy v0y t gt v0 sin?t gt
- Max. height h v0y2 /2?g ?
- Projectile path equation
-
- Projectile path is a parabola given by
- y(tan?) x - gx2/2vx2
13Formule Summary for Projectile Motion
Equation of motion Horizontal Motion (ax0) Vertical Motion (ay g)
vavg (vivf)/2 vavg v0x v0 cos? Vavg (v0yvy)/2 v0y v0 sin?
vf vi at vx v0x v0 cos? vy v0 sin? -gt
(vf)2 (vi)2 2ax (vx)2 (v0 cos?)2 (vy)2 (v0 sin?)2 -2gy
x vitat2/2 x v0 cos? t y v0 sin? t- (gt2)/2
Max. Distance R 2 v0 cos? tup (v0)2 sin2? /2g Rmax (v0)2 /2g h (v0 sin? )2 / 2g
14Checkpoint 4-4
- A fly ball is hit to the outfield. During its
flight (ignore the effect of the air), what
happens to its (a) horizontal and (b)vertical
components of velocity - What are its (c) horizontal and (d) vertical
components of its acceleration during ascent,
during descent, and at the topmost point of its
flight?
- vxconstant
- vy initially positive and then decreases to zero
and finally it increases in negative value. - ax 0
- ay -g
- throughout the entire projectile path
15Ch 4-7 Uniform Circular Motion
- Uniform Circular Motion
- Motion with constant speed v in a circle of
radius r but changing speed direction - Change in direction of v causes radial or
centripetal acceleration aR - aR v2/r
- Period of motion T
- T (2?r)/v
16Checkpoint 4-6
- Object has counterclockwise motion
- Then at y2 m , its velocity is v (4m/s)i
- and centripetal acceleration magnitude aRv2/R
(4)2/2 - 8 m/s2
- aR(-8m/s2)j
An object moves at constant speed along a
circular path in a horizontal xy plane, with the
center at the origin. When the object is at
x-2m, its velocity is (4m/s)j. Give the object
(a) velocity and (b) acceleration when it is at
y 2m
17Ch 4-8 Relative Motion in One Dimension
- Relative position
- xPAxPBxBA
- Relative Velocities
- d/dt(xPA)d/dt(xPB)d/dt (xBA)
- vPA vPB vBA
- Relative Acceleration
- d/dt(vPA)d/dt(vPB)d/dt (vBA)
- aPAaPB (vBA is constant)
18Ch 4-8 Relative Motion in Two Dimensions
- Two observers watching particle P from origins of
frames A and B, while B moves with constant
velocity vbA with respect to A - Position vector of particle P relative to origins
of frame A and B are rPA and rPB. If rBA is
position vector of the origin of B relative to
the origin of A then - rPA rPB. rBA and
- vPA vPB. vBA
- aPA aPB. Because vBA constant