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GES 255

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3. t Distribution. Parameter is degrees of freedom, denoted by df or ... The rv: has a t distribution with = (n - 1) degrees of freedom (df). 6. A Confidence Interval ... – PowerPoint PPT presentation

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Title: GES 255


1
GES 255
  • Engineering Statistics I

2
Material
  • Chapter 7 Statistical Intervals Based on a
    Single Sample.
  • Section 7.3 Intervals Based on a Normal
    Population Distribution.

3
t Distribution
  • Parameter is degrees of freedom, denoted by df or
    ?.
  • ? n 1, where n is the sample size.
  • Properties of t Distributions and Figure 7.6,
    p.300 (transparency).
  • Notation for t critical value ta,?.
  • Figure 7.7, p.301 (transparency).

4
Example
  • Determine t0.05,15 and the percentile for
  • t 3.610 when ? 18.
  • Appendix Tables A.5 and A.8.
  • Excel Insert / Function / Statistical / TDIST
    or TINV.
  • Minitab Calc / Probability Distributions / t
    (Cumulative probability or Inverse cumulative
    probability).

5
A Confidence Intervalfor ?, ? Unknown, n Small
  • Assumptions The population is Normally
    distributed, ? is unknown, and n is small (n
    40).
  • The rv
  • has a t distribution with ? (n - 1) degrees of
    freedom (df).

6
A Confidence Intervalfor ?, ? Unknown, n Small
  • This means that the following holds
  • We use the part in parentheses to derive the
    100(1 - ?) CI.

7
A Confidence Intervalfor ?, ? Unknown, n Small
  • A 100(1 - ?) CI for the mean ? of a
  • Normal population when the value of ? is
  • unknown and n is small

8
Example
  • Example 7.11, p.302.
  • Transparency problem statement.
  • EX14 Sec.7.3 (Minitab).
  • Normal probability plot (NPP).
  • Two steps.
  • 1. Determine the 95 CI.
  • 2. Interpret the CI within the context of the
    problem.

9
Example (continued)
  • Minitab.
  • Need sample data.
  • Stat / Basic Statistics / Display Descriptive
    Statistics
  • Stat / Basic Statistics / 1-Sample t

10
The End!
  • That is it for
  • Section 7.3 Intervals Based on
  • a Normal Population Distribution
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