Title: Chapter 7: Deadlocks
1Chapter 7 Deadlocks
2Chapter 7 Deadlocks
- The Deadlock Problem
- System Model
- Deadlock Characterization
- Methods for Handling Deadlocks
- Deadlock Prevention
- Deadlock Avoidance
- Deadlock Detection
- Recovery from Deadlock
3Chapter Objectives
- To develop a description of deadlocks, which
prevent sets of concurrent processes from
completing their tasks - To present a number of different methods for
preventing or avoiding deadlocks in a computer
system.
4The Deadlock Problem
- A set of blocked processes each holding a
resource and waiting to acquire a resource held
by another process in the set. - Example
- System has 2 tape drives.
- P1 and P2 each hold one tape drive and each needs
another one. - Example
- semaphores A and B, initialized to 1
- P0 P1
- wait (A) wait(B)
- wait (B) wait(A)
5Bridge Crossing Example
- Traffic possible in only one direction in center
of bridge. - Each section of a bridge can be viewed as a
resource. - If a deadlock occurs, it can be resolved if one
car backs up (preempt resources and rollback). - Several cars may have to be backed up if a
deadlock occurs. - Starvation is possible.
6System Model
- A system is made up of resources (hard and soft)
- e.g., CPU cycles, memory space, I/O devices
- Each resource type has a finite number of
instances - e.g., there are a finite number of printers
on the system, there is only so much memory,
there is only one copy of shared data, etc. - Each process utilizes a resource as follows
- Requests resource
- Uses resource (in Critical Section)
- Releases resource
- Conflict / deadlock is possible, just like on
bridge
7Deadlock Characterization
Deadlock can arise if four conditions exist
simultaneously.
- Mutual exclusion only one process at a time can
use a resource (e.g., a printer, tape drive, DB
file/record). - Hold and wait a process that is holding at
least one resource is waiting to acquire
additional resources held by other processes
(think of 2 processes wanting to copy tapes). - No preemption a resource can be released only
voluntarily by the process holding it, after that
process has completed its task (e.g., cannot be
interrupted when only half done printing a job). - Circular wait there exists a set P0, P1, ,
Pn of waiting processes such that P0 is waiting
for a resource that is held by P1, P1 is waiting
for a resource that is held by P2, , Pn1 is
waiting for a resource that is held by Pn, and Pn
is waiting for a resource that is held by P0. - (think of the Dining Philosophers each
holding one chopstick)
8Example of Deadlock Situation
Mutual Exclusion, Hold and Wait, No Preemption,
Circular Wait
9Methods for Handling Deadlocks
- Ensure that the system will never enter a
deadlock state. - Prevention algorithms
- Avoidance algorithms
- Allow the system to enter a deadlock state and
then recover. - Detection algorithms
- Recovery algorithms
- Ignore the problem and pretend that deadlocks
never occur in the system - Used by most operating systems, including UNIX.
- Not as bad an option as it seems, provided the
user / administrator can find a way to recover
when occur
10Deadlock Prevention
To prevent deadlocks, must insure that one of the
four required conditions cannot exist Must
control / constrain the ways requests can be made.
- Mutual Exclusion not required for shareable
resources but must be required for non shareable
resources. - So, cannot always prevent, since some resources
are by their nature non-shareable (e.g.,
printers) - Hold and Wait must guarantee that whenever a
process requests a resource, it does not hold any
other resources. - Require a process to request and be allocated all
its resources before it begins execution, or
allow a process to request resources only when
the process owns none. - Problem Low resource utilization possible
starvation. - Also, sometimes processes must hold multiple
resources in order to be able to do their work
11Deadlock Prevention (Cont.)
- No Preemption cannot always prevent (e.g.
printers, tapes), but can sometimes use the
following - If a process that is holding some resources
requests another resource that cannot be
immediately allocated to it, then all resources
currently being held are released. - Preempted resources are added to the list of
resources for which the process is waiting. - Process will be restarted only when it can regain
its old resources, as well as the new ones that
it is requesting. - Circular Wait impose a total ordering of all
resource types, hierarchy and require that each
process requests resources in an increasing order
of enumeration. - For handling each of these four conditions
potential problems - Resource utilization low, decreased throughput,
starvation - Small number of resources can only hold a short
time
12Deadlock Avoidance
Develop protocol to insure deadlock will never
occur Requires that the system has some
additional a priori information available (i.e.,
must know some information ahead of time).
- Simplest and most useful model requires that each
process declare the maximum number of resources
of each type that it may need before process
starts to run. - Process is only allowed to start to run if all
resources it needs are available and could be
allocated to it - System keeps track of where resources are
currently allocated and where they will be
allocated in the future - Resource-allocation state is defined by the
number of available and allocated resources, and
the maximum demands of the processes. - Again, problem of low resource utilization
- Since some resources and processes may sit idle
and wait until other resources are available
13Safe State
- When a process requests an available resource,
system must decide if immediate allocation leaves
the system in a safe state. - System is in safe state if there exists some
sequence in which all the processes can run, and
each can get all the resources it needs to be
able to complete. For example - Sequence ltP1, P2, , Pngt is safe if for each Pi,
the resources that Pi can still request can be
satisfied by currently available resources
resources held by all the Pj, with jltI. - If Pi resource needs are not immediately
available, then Pi can wait until all Pj have
finished. - When Pj is finished, Pi can obtain needed
resources, execute, return allocated resources,
and terminate. - When Pi terminates, Pi1 can obtain its needed
resources, and so on. - Such an algorithm is relatively simple to
construct if processing is single-threaded - Complexity increases dramatically in a
multiprogramming environment
14Basic Facts
- If a system is in safe state gt no deadlocks.
- If a system is in unsafe state gt possibility of
deadlock. - Avoidance gt ensure that a system will never
enter an unsafe state. - Potential problems
- Reduced resource utilization
- Reduced throughput
- Reduced performance
- Will describe and try to solve problem using
resource-allocation graphs
15Safe, Unsafe , Deadlock State
16Resource-Allocation Graph Concepts
- Processes and resources are represented by nodes
- Relationships between them are represented by
edges - Resources must be claimed a priori before
process can run. - Claim edge Pi ? Rj indicates that process Pj may
request resource Rj (a claim is like a
reservation) - Represented by a dashed line from the process to
the resource. - Claim edge converts to request edge when a
process actually requests a resource - Represented by a solid line from the process to
the resource. - A request edge changes to an assignment edge when
the resource is allocated to the process - Represented by solid line from the resource to
the process. - When a resource is released by a process, the
assignment edge reverts back to a claim edge.
17Resource-Allocation Graph For Deadlock Avoidance
When resource is assigned, process can use it
Resource is requested when running process needs
to use it
Assigned
Requested (but not yet assigned)
Claimed (but not yet requested)
Resource is claimed before process starts to run
When process is done using it, resource
returns to claimed state
18 Unsafe State In Resource-Allocation Graph
If no cycles, system is in a safe
state (guarantee system not deadlocked)
If cycles exist, system is in an unsafe state
(may be deadlocked)
Cycle
19Bankers Algorithm
DEADLOCK AVOIDANCE ALGORITHM
- Assume there are multiple instances of
resources. - Each process must make an a priori claim of
maximum number of resources of each type it will
use (ahead of time) - System determines whether allocating all the
resources will leave the system in a safe state
(i.e., some sequence exists in which all
processes can run and still get all resources
they need) - If so, resources are allocated and process can
continue - If not, process must wait (important!)
- When a process gets all its resources, it must
return them in a finite amount of time. - System must maintain data structures to keep
track of state of resources
20Data Structures for the Bankers Algorithm
Let n number of processes, and m number of
resources types.
- Available Vector of length m. If available j
k, there are k instances of resource type Rj
available. - Max n x m matrix. If Max i,j k, then
process Pi may request at most k instances of
resource type Rj. - Allocation n x m matrix. If Allocationi,j
k then Pi is currently allocated k instances of
Rj. - Need n x m matrix. If Needi,j k, then Pi
may need k more instances of Rj to complete its
task. - Need i,j Maxi,j Allocation i,j.
21Resource-Request Algorithm for Process Pi
- Request request vector for process Pi. If
Requesti j k then process Pi wants k
instances of resource type Rj. - 1. If Requesti lt Needi go to step 2. Otherwise,
raise error condition, since process has exceeded
its maximum claim. - 2. If Requesti lt Available, go to step 3.
Otherwise Pi must wait, since resources are not
available. - 3. Pretend to allocate requested resources to Pi
by modifying the state as follows to see if
allocating the resources would leave the system
in a safe state - Availablei Availablei -
Requesti - Allocationi Allocationi
Requesti - Needi Needi Requesti
- If safe -- the resources are allocated to Pi.
- If unsafe Pi must wait, and the old
resource-allocation state is restored
22Bankers Algorithm Example
- Five processes -- P0 through P4
- 3 resource types A (10 instances), B (5
instances), and C (7 instances). - Snapshot in time T0 is system in a safe state ?
- Need is defined to be Max Allocation.
- Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 - P1 2 0 0 3 2 2
1 2 2 - P2 3 0 2 9 0 2
6 0 0 - P3 2 1 1 2 2 2
0 1 1 - P4 0 0 2 4 3 3
4 3 1
23Bankers Algorithm Example (Cont.)
- Five processes -- P0 through P4
- 3 resource types A (10 instances), B (5
instances), and C (7 instances). - Snapshot in time T0 is system in a safe state ?
- Need is defined to be Max Allocation.
- Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 10 5 7 - P1 2 0 0 3 2 2
1 2 2 5 3 2 - P2 3 0 2 9 0 2
6 0 0 10 4 7 - P3 2 1 1 2 2 2
0 1 1 7 4 3 - P4 0 0 2 4 3 3
4 3 1 7 4 5 - Yes, the system is in a safe state, since the
sequence lt P1, P3, P4, P2, P0gt satisfies safety
criteria. - Other sequences possible
24Example -- P1 Requests (1,0,2) Additional
- Check that Request lt Available (that is,
(1,0,2)lt(3,3,2) true. - Available changed from (3,3,2) to (2,3,0) and
P1s allocation changed from (2,0,0) to (3,0,2)
-- IS THE SYSTEM STILL IN A SAFE STATE? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 2 3 0 - P1 2 0 0 3 0 2 3 2 2 1 2
2 0 2 0 - P2 3 0 2 9 0 2
6 0 0 - P3 2 1 1 2 2 2
0 1 1 - P4 0 0 2 4 3 3
4 3 1
25Example -- P1 Requests (1,0,2) (Cont.)
- Check that Request lt Available (that is,
(1,0,2)lt(3,3,2) true. - Available changed from (3,3,2) to (2,3,0) and
P1s allocation changed from (2,0,0) to (3,0,2)
-- IS THE SYSTEM STILL IN A SAFE STATE? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 2 3 0 7 5 5 - P1 2 0 0 3 0 2 3 2 2 1 2
2 0 2 0 5 3 2 - P2 3 0 2 9 0 2
6 0 0
10 5 7 - P3 2 1 1 2 2 2
0 1 1 7 4 3 - P4 0 0 2 4 3 3
4 3 1 7 4 5 - YES SYSTEM IS STILL IN A SAFE STATE
- Executing safety algorithm shows that sequence
ltP1, P3, P4, P0, P2gt satisfies safety
requirement. (as do ltP1, P3, P4, P2, P0gt , ltP1,
P3, P2, P4, P0gt , and ltP1, P3, P2, P0, P4gt)
26Example -- P4 Requests (3,3,0)
- Can request for (3,3,0) by P4 be granted?
- Assume initial state of system
- Check that Request lt Available (that is,
(3,3,0)lt(3,3,2) true. - Then check to see is the system is still in
safe state? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 0 0 2 - P1 2 0 0 3 2 2
1 2 2 - P2 3 0 2 9 0 2
6 0 0 - P3 2 1 1 2 2 2
0 1 1 - P4 0 0 2 3 3 2 4 3 3 4 3
1 1 0 1 -
-
27Example -- P4 Requests (3,3,0)
- Can request for (3,3,0) by P4 be granted?
- Assume initial state of system
- Check that Request lt Available (that is,
(3,3,0)lt(3,3,2) true. - Then check to see is the system is still in
safe state? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 7 5 3
7 4 3 3 3 2 0 0 2 - P1 2 0 0 3 2 2
1 2 2 - P2 3 0 2 9 0 2
6 0 0 - P3 2 1 1 2 2 2
0 1 1 - P4 0 0 2 3 3 2 4 3 3 4 3
1 1 0 1 - NO system is not in a safe state (need of every
process gt available) - If the resources were allocated, there would be
no sequence in which all of the programs could
run to completion
28Example -- P0 Requests (0,2,0)
- Can request for (0,2,0) by P0 be granted?
- Assume initial state of system
- Check that Request lt Available (that is,
(0,2,0)lt(3,3,2) true. - Then check to see is the system is still in
safe state? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 0 3 0 7 5 3 7 4
3 7 2 3 3 3 2 3 1 2 - P1 2 0 0 3 2 2
1 2 2 - P2 3 0 2 9 0 2
6 0 0 - P3 2 1 1 2 2 2
0 1 1 - P4 0 0 2 4 3 3
4 3 1 -
29Example -- P0 Requests (0,2,0)
- Can request for (0,2,0) by P0 be granted?
- Assume initial state of system
- Check that Request lt Available (that is,
(0,2,0)lt(3,3,2) true. - Then check to see is the system is still in
safe state? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 0 3 0 7 5 3 7 4
3 7 2 3 3 3 2 3 1 2 7 5 3 - P1 2 0 0 3 2 2
1 2 2 7 2 3 - P2 3 0 2 9 0 2
6 0 0 10
5 5 - P3 2 1 1 2 2 2
0 1 1 5 2 3 - P4 0 0 2 4 3 3
4 3 1
10 5 7 - Yes possibilities ltP3,P1,P0,P2,P4gt,
ltP3,P1,P0,P4,P2gt, ltP3,P1,P2,P0,P4gt - What if request was for (0,3,0)
30Example -- P0 Requests (0,2,0)
- Can request for (0,2,0) by P0 be granted?
- Assume initial state of system
- Check that Request lt Available (that is,
(0,2,0)lt(3,3,2) true. - Then check to see is the system is still in
safe state? - Allocation Max Need
Available - A B C A B C A B
C A B C - P0 0 1 0 0 3 0 7 5 3 7 4
3 7 2 3 3 3 2 3 1 2 7 5 3 - P1 2 0 0 3 2 2
1 2 2 7 2 3 - P2 3 0 2 9 0 2
6 0 0 10
5 5 - P3 2 1 1 2 2 2
0 1 1 5 2 3 - P4 0 0 2 4 3 3
4 3 1
10 5 7 - Yes possibilities ltP3,P1,P0,P2,P4gt,
ltP3,P1,P0,P4,P2gt, ltP3,P1,P2,P0,P4gt - What if request was for (0,3,0) NO UNSAFE
STATE - Available (3,0,2) and no process could be
guaranteed to run
31Deadlock Detection
- Bankers algorithm is expensive
- Sometimes it is cheaper to
- Allow the system to enter a deadlock state
- Detect the deadlock (using a detection algorithm)
- Recover from the deadlock (rollback or other
recovery scheme) - Involves use of
- Resource allocation graphs and graph theory and
algorithms - ////
32Single Instance of Each Resource Type
- Maintain a wait-for graph
- Nodes are processes.
- Pi ? Pj if Pi is waiting for Pj.
- (Graph looks similar to graphs used at
beginning of session) - Periodically invoke an algorithm that searches
for a cycle in the graph. - An algorithm to detect a cycle in a graph
requires an order of n2 operations, where n is
the number of vertices in the graph. - So, expensive
- For handling multiple instances of some resource
types, first look at resource allocation graph
(instead of a wait-for graph)
33Resource-Allocation Graph
- Similar to resource-allocation graphs used for
deadlock avoidance but since this is for
detection, do not have to include a priori claims
information (so no claim edges) - Have a set of vertices V and set of edges E
- Use to describe relationships between processes
and resources - V is partitioned into two types
- P P1, P2, , Pn, the set consisting of all
the processes in the system. - R R1, R2, , Rm, the set consisting of all
resource types in the system. - Request edge directed edge Pi ? Rj
- Assignment edge directed edge Rj ? Pi
34Resource Allocation Graph Symbols
Process Resource type with four
instances Process requesting resource of this
type Resource is allocated to process(doesnt
matter which one)
35Basic Concept
- Construct a resource allocation graph for system
- If graph contains no cycles -- then no
deadlock. - If graph contains a cycle -- then
- If only one instance per resource type, then
deadlock. - If several instances per resource type,
possibility of deadlock.
36Example of a Resource Allocation Graph
No cycles, so no deadlock Note no claim
edges, only request and allocation
37Resource Allocation Graph With A Deadlock
? Cycle (actually 2) AND Deadlock
38Resource Allocation Graph With A Cycle But No
Deadlock
No deadlock because have multiple instances of
R2 P2 or P4 can run, release its instance of
the resource, and then the cycle will be broken
39Evaluation Allocation Wait-for Graph
- To simplify and improve speed, and if single
instance of each resource type use
WAIT-FOR-GRAPH - Produce a Wait-For Graph by removing the resource
nodes from resource allocation graph - If cycle (and single instance of resources) gt
deadlock
40Resource-Allocation Graph and Wait-for Graph
Resource-Allocation Graph
Corresponding wait-for graph
41Detection Single Instance of Resource Type
- Maintain a wait-for graph
- Nodes are processes
- Pi gt Pj if Pi is waiting for Pj
- Periodically invoke an algorithm that searches
for cycle - Cycle deadlock
- Algorithm expensive O(n2) , where nnumber of
vertices - Plus overhead to maintain graph
- But still cheaper than general algorithm
- When should the detection algorithm be invoked?
- Depends on how often a deadlock may occur
- How many processes will need to be rolled back
(one for each disjoint cycle)
42Detection -- Several Instances of Resource Type
- Available A vector of length m indicates the
number of available resources of each type. - m distinct types of resources
- Value of entry instances of that type
- Allocation An n x m matrix defines the number
of resources of each type currently allocated to
each process. - n number of processes (i.e., one row for each
process) - Request An n x m matrix indicates the current
request of each process. - If Request ij k, then process Pi is
requesting k more instances of resource type. Rj. - NOTE this resembles earlier Bankers Algorithm
without Max
43Detection Algorithm
- Let Work and Finish be vectors of length m and n,
respectively Initialize - m number of distinct kinds of resources, n
number of processes - (a) Work Available
- (b) For i 1,2, , n, if Allocationi ? 0, then
Finishi false otherwise, Finishi
true. - 2. Find an index i such that both
- (a) Finishi false // Not done yet
- (b) Requesti ? Work // Can get all resources
needed // Work is single dim., with same
// format as row in Request -
- If no such i exists, go to step 4.
44Detection Algorithm (Cont.)
- 3. Work Work Allocationi
- Finishi truego to step 2.
- 4. If Finishi false, for some i, 0lt i lt n,
then the system is in deadlock state. Moreover,
if Finishi false, then Pi is deadlocked. -
Algorithm requires an order of O(m n2)
operations to detect whether the system is in
deadlocked state (where n number of resource
types and m number of resources of each type).
45Example of Detection Algorithm
- Five processes P0 through P4 three resource
types A (7 instances), B (2 instances), and C (6
instances). - Snapshot at time T0
- Allocation Request Available
- A B C A B C A B C
- P0 0 1 0 0 0 0 0 0 0
- P1 2 0 0 2 0 2
- P2 3 0 3 0 0 0
- P3 2 1 1 1 0 0
- P4 0 0 2 0 0 2
- Looks VERY similar to Bankers Algorithm seen
earlier - Bankers Algorithm used Allocation, Max,
Need, and Available - Request here is same as Need was there, and
Max is gone - Difference that was before, this is while
processes running
46Example of Detection Algorithm
- Five processes P0 through P4 three resource
types A (7 instances), B (2 instances), and C (6
instances). - Snapshot at time T0
- Allocation Request Available
- A B C A B C A B C
- P0 0 1 0 0 0 0 0 0 0
- P1 2 0 0 2 0 2
- P2 3 0 3 0 0 0
- P3 2 1 1 1 0 0
- P4 0 0 2 0 0 2
- Question is still the same is there a sequence
in which the processes can run and receive all
the resources they need ? - Sequence ltP0, P2, P3, P1, P4gt , ltP2, P0, P3, P1,
P4gt, ltP0, P2, P4, P3, P1gt , etc. will result in
Finishi true for all i.
47Example (Cont.)
- What if P2 requests an additional instance of
type C. - Allocation Request Available
- A B C A B C A B C
- P0 0 1 0 0 0 0 0 0 0
- P1 2 0 0 2 0 2
- P2 3 0 3 0 0 0 0 0 1
- P3 2 1 1 1 0 0
- P4 0 0 2 0 0 2
- State of system?
48Example (Cont.)
- What if P2 requests an additional instance of
type C. - Allocation Request Available
- A B C A B C A B C
- P0 0 1 0 0 0 0 0 0 0
- P1 2 0 0 2 0 2
- P2 3 0 3 0 0 0 0 0 1
- P3 2 1 1 1 0 0
- P4 0 0 2 0 0 2
- State of system?
- Can reclaim resources held by process P0, but
there are insufficient resources to fulfill other
processes requests. - Deadlock exists, consisting of processes P1, P2,
P3, and P4.
49Detection-Algorithm Usage
- QUESTION When, and how often, to invoke depends
on - How often a deadlock is likely to occur?
- How many processes will need to be rolled back?
- One for each disjoint cycle
- If detection algorithm is invoked arbitrarily,
there may be many cycles in the resource graph - So will not be able to tell which of the many
deadlocked processes caused the deadlock
will have to roll back many processes. - If invoke whenever an allocation request is made
- Only one process at most will ever have to be
rolled back - BUT deadlock algorithm requires O(mn2) worst
case - Also rollback / recovery quite expensive, too
- Becomes a little different than Bankers
Algorithm (i.e., becomes preemption, not
detection)
50Recovery from Deadlock Process Termination
- Process termination kill the offending
processes - Abort all deadlocked processes -- OR --
- Abort one process at a time until the deadlock
cycle is eliminated. - BUT termination is nasty business
- Previous execution time all wasted
- May leave data in unusable / incoherent state
(roll back transactions ?) - Will leave jobs partially completed (e.g.,
printing, copying tape, etc.) - Determining which process to terminate and
checking if cycle is broken is COSTLY - In which order should the processes be aborted?
- Priority of the process.
- How long process has run, and how much longer
until it finishes. - Resources the process has used.
- Resources process needs to complete.
- How many processes will need to be terminated.
- Is process interactive or batch?
51Recovery from Deadlock Resource Preemption
- Rollback some proccess(es) and preempt their
resources - Selecting a victim not easy
- Involves both questions of resources and
processes, similar to process termination
questions - Least costly
- Priority, length of time deadlocked, ripple
effect, resources held - Rollback return to some safe state, restart
process for that state - Finding safe state is not easy must keep data
coherent - Could terminate, but costly (thats why trying to
rollback, so dont have to kill process, i.e.,
rollback to very beginning) - Starvation must avoid, and insure same process
is not always rolled back
52Combined Approach to Deadlock Handling
- Can combine the three basic approaches
- prevention
- avoidance
- detection
- and allow the use of the optimal approach for
each of resources in the system. - Partition resources into hierarchically ordered
classes. - Use most appropriate technique for handling
deadlocks within each class. - Remember / count the cost
53The Real World and Deadlock Handling
- Many / most systems do not try to handle
deadlocks at low levels of the OS programmers
must avoid them! - Running deadlock prevention / detection /
avoidance / recovery algorithms simply too
expensive - O(n2)
- Too great an impact on overall system performance
- Develop protocols, locks, ordering of resources
- Use critical sections / monitors in code
- Shared resources
- Data / physical resources
- Deadlocks
54Suggested Approack to Deadlock Handling
- At high levels of the system
- Low levels enforce high level locks
- Ability to cancel deadlocked jobs manually
- Timeouts
- At lower levels, can also use
- Queues for printer, comm, tape, disk, etc.
- Asynchronous instead of synchronous ops
- I/O scheduling algorithms to avoid starvation
- Avoidance / heirarchical protocols (order)
- Timeout values and good error recovery
- State machines / monitors
- OO techninques (object enforces CS thread safe)
- Order resources / locks protocols
- Have traps to catch
55Approaches to Deadlock Handling -2-
- Deadlocks are often caused by
- Inadequate documentation
- Poor design (complexity)
- Shoddy reviews
- Insufficient testing
- Dont let this happen to you
56End of Chapter 7