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Hardy Weinberg Notes

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p2 = frequency of homo dom. 2pq = frequency of hetero. q2 = frequency of homo recess ... How many individuals would you expect to be homo dom and heterozy? ... – PowerPoint PPT presentation

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Title: Hardy Weinberg Notes


1
Hardy Weinberg Notes
2
Allele Frequencies
  • Allele frequencies the abundance of each kind
    of allele in a population
  • To compare, use Hardy-Weinberg equilibrium (equati
    on p2 2pq q2 1)
  • p2 frequency of homo dom
  • 2pq frequency of hetero
  • q2 frequency of homo recess
  • p frequency of dominant allele
  • q frequency of the recessive allele

3
Hardy-Weinberg Theorem describes a
non-evolving population
  • Must meet 5 conditions for no change in
    frequencies of alleles at a given gene locus
  • 1. No gene mutations have occurred.
  • 2. Population is very large.
  • 3. Population is isolated from other pops of
    the species (no immigration or
    emigration.)
  • 4. No natural selection
  • 5. Mating is random.

4
Hardy-Weinberg example
  • The allele for the ability to roll ones tongue
    is dominant (R) over the allele for the lack of
    this ability (r).
  • In a population of 500 individuals, 25 show the
    recessive phenotype. How many individuals would
    you expect to be homo dom and heterozy?

5
  • The equation p2 2pq q2 1
  • Therefore, p q 1
  • 500 organisms, 25 are rr thus q2 .25
  • so 125 organisms are rr
  • If q2 .25, the q.5
  • Thus, p .5 1, leaves p .5
  • So, p2 .25, so 125 organisms are RR
  • 2pq leaves the heterozygotes, so
  • 2(.5)(.5) .5 or 50, so 250 organisms are Rr

6
Practice Problem
  • Seventy percent of a population show the
    dominant trait while 30 are recessive. What
    percentage of the population are carriers
    (heterozygous for dominant trait)?
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