Title: The Laws of Biot-Savart
1Magnetism
- The Laws of Biot-Savart Ampere
2Overview of Lecture
- Fundamental Law for Calculating Magnetic Field
- Biot-Savart Law (brute force)
- Amperes Law (high symmetry)
- Example Calculate Magnetic Field of Straight
Wire - from Biot-Savart Law
- from Amperes Law
- Calculate Force on Two Parallel Current-Carrying
Conductors
Text Reference Chapter 30.1-4
3Calculation of Electric Field
- Two ways to calculate the Electric Field
- Coulomb's Law
- What are the analogous equations for the Magnetic
Field?
4Calculation of Magnetic Field
- Two ways to calculate the Magnetic Field
- Biot-Savart Law
- These are the analogous equations for the
Magnetic Field!
5Biot-Savart Lawbits and pieces
(1819)
So, the magnetic field circulates around the
wire
6Magnetic Field of Straight Wire
- Calculate field at point P using Biot-Savart Law
Which way is B?
7Magnetic Field of Straight Wire
8Lecture 14, ACT 1
- What is the magnitude of the magnetic field at
the center of a loop of radius R, carrying
current I? -
9Lecture 14, ACT 1
- What is the magnitude of the magnetic field at
the center of a loop of radius R, carrying
current I? -
- To calculate the magnetic field at the center,
we must use the Biot-Savart Law
- Two nice things about calculating B at the
center of the loop - Idx is always perpendicular to r
- r is a constant (R)
10Magnetic Field of Straight Wire
- Calculate field at distance R from wire using
Ampere's Law
- Choose loop to be circle of radius R centered on
the wire in a plane to wire.
- Why?
- Magnitude of B is constant (fcn of R only)
- Direction of B is parallel to the path.
- Current enclosed by path I
- Ampere's Law simplifies the calculation thanks to
symmetry of the current! ( axial/cylindrical )
11Lecture 14, ACT 2
- A current I flows in an infinite straight wire in
the z direction as shown. A concentric infinite
cylinder of radius R carries current 2I in the -z
direction. - What is the magnetic field Bx(a) at point a, just
outside the cylinder as shown?
- What is the magnetic field Bx(b) at point b,
just inside the cylinder as shown?
12Lecture 14, ACT 2
- A current I flows in an infinite straight wire in
the z direction as shown. A concentric infinite
cylinder of radius R carries current 2I in the -z
direction. - What is the magnetic field Bx(a) at point a, just
outside the cylinder as shown?
- This situation has massive cylindrical symmetry!
- Applying Amperes Law, we see that the field at
point a must just be the field from an infinite
wire with current I flowing in the -z direction!
13Lecture 14, ACT 2
- A current I flows in an infinite straight wire in
the z direction as shown. A concentric infinite
cylinder of radius R carries current 2I in the -z
direction. - What is the magnetic field Bx(a) at point a, just
outside the cylinder as shown?
What is the magnetic field Bx(b) at point b,
just inside the cylinder as shown?
- Just inside the cylinder, the total current
enclosed by the Ampere loop will be I in the z
direction! - Therefore, the magnetic field at b will just be
minus the magnetic field at a!!
14Question
- How do we check this result??
- i.e. expect B from wire to be proportional to I/R.
- Measure FORCE on current-carrying wire due to the
magnetic field PRODUCED by ANOTHER current
carrying wire!
- How does force depend on currents and separation?
15Force on 2 ParallelCurrent-Carrying Conductors
- Calculate force on length L of wire b due to
field of wire a - The field at b due to a is given by
- Calculate force on length L of wire a due to
field of wire b - The field at a due to b is given by
16Lecture 14, ACT 3
- A current I flows in the positive y direction in
an infinite wire a current I also flows in the
loop as shown in the diagram. - What is Fx, net force on the loop in the
x-direction?
17Lecture 14, ACT 3
- A current I flows in the positive y direction in
an infinite wire a current I also flows in the
loop as shown in the diagram. - What is Fx, net force on the loop in the
x-direction?
- You may have remembered from a previous ACT
that the net force on a current loop in a
constant magnetic field is zero. - However, the magnetic field produced by the
infinite wire is not a constant field!!
- The forces on the left and right segments of
the loop DO NOT cancel!! - The left segment of the loop is in a larger
magnetic field. - Therefore, Fleft gt Fright
18 - Examples of Magnetic Field Calculations
19Overview of Lecture
- Calculate Magnetic Fields
- Inside a Long Straight Wire
- Infinite Current Sheet
- Solenoid
- Toroid
- Circular Loop
Text Reference Chapter 30.1-5
20Today is Amperes Law Day
"High symmetry"
21B Field Insidea Long Wire
- Suppose a total current I flows through the wire
of radius a into the screen as shown. - Calculate B field as a fcn of r, the distance
from the center of the wire.
- B field is only a fcn of r Þ take path to be
circle of radius r
- Current passing through circle
22B Field of aLong Wire
23Lecture 15, ACT 1
- Two cylindrical conductors each carry current I
into the screen as shown. The conductor on the
left is solid and has radius R3a. The conductor
on the right has a hole in the middle and carries
current only between Ra and R3a. - What is the relation between the magnetic field
at R 6a for the two cases (Lleft, Rright)?
24Lecture 15, ACT 1
- Two cylindrical conductors each carry current I
into the screen as shown. The conductor on the
left is solid and has radius R3a. The conductor
on the right has a hole in the middle and carries
current only between Ra and R3a. - What is the relation between the magnetic field
at R 6a for the two cases (Lleft, Rright)?
- Amperes Law can be used to find the field in
both cases. - The Amperian loop in each case is a circle of
radius R6a in the plane of the screen.
- The field in each case has cylindrical symmetry,
being everywhere tangent to the circle. - Therefore the field at R6a depends only on the
total current enclosed!! - In each case, a total current I is enclosed.
25Lecture 15, ACT 1
- Two cylindrical conductors each carry current I
into the screen as shown. The conductor on the
left is solid and has radius R3a. The conductor
on the right has a hole in the middle and carries
current only between Ra and R3a. - What is the relation between the magnetic field
at R 6a for the two cases (Lleft, Rright)?
- Once again, the field depends only on how much
current is enclosed.
26B Field of Current Sheet
- Consider an sheet of current described by n
wires/length each carrying current i into the
screen as shown. Calculate the B field.
- What is the direction of the field?
- Symmetry Þ y direction!
- Calculate using Ampere's law using a square of
side w
27B Field of a Solenoid
- A constant magnetic field can (in principle) be
produced by an sheet of current. In practice,
however, a constant magnetic field is often
produced by a solenoid.
- If a ltlt L, the B field is to first order
contained within the solenoid, in the axial
direction, and of constant magnitude. In this
limit, we can calculate the field using Ampere's
Law.
28B Field of a Solenoid
- To calculate the B field of the solenoid using
Ampere's Law, we need to justify the claim that
the B field is 0 outside the solenoid.
- To do this, view the solenoid from the side as
2 current sheets.
- The fields are in the same direction in the
region between the sheets (inside the solenoid)
and cancel outside the sheets (outside the
solenoid).
- Draw square path of side w
29Toroid
- Toroid defined by N total turns with current i.
- B0 outside toroid! (Consider integrating B on
circle outside toroid)
- To find B inside, consider circle of radius r,
centered at the center of the toroid.
Apply Amperes Law
30Circular Loop
- Circular loop of radius R carries current i.
Calculate B along the axis of the loop
- Magnitude of dB from element dl
- What is the direction of the field?
- Symmetry Þ B in z-direction.
Þ
31Circular Loop
Þ
- Note the form the field takes for zgtgtR
- Expressed in terms of the magnetic moment
note the typical dipole field behavior!
Þ
32Lecture 15, ACT 2
- Equal currents I flow in identical circular loops
as shown in the diagram. The loop on the
right(left) carries current in the ccw(cw)
direction as seen looking along the z
direction. - What is the magnetic field Bz(A) at point A, the
midpoint between the two loops?
33Lecture 15, ACT 2
- Equal currents I flow in identical circular loops
as shown in the diagram. The loop on the
right(left) carries current in the ccw(cw)
direction as seen looking along the z
direction. - What is the magnetic field Bz(A) at point A, the
midpoint between the two loops?
(b) Bz(A) 0
(c) Bz(A) gt 0
(a) Bz(A) lt 0
- The right current loop gives rise to Bz lt0 at
point A.
- The left current loop gives rise to Bz gt0 at
point A.
- From symmetry, the magnitudes of the fields
must be equal. - Therefore, B(A) 0!
34Lecture 15, ACT 2
- Equal currents I flow in identical circular loops
as shown in the diagram. The loop on the
right(left) carries current in the ccw(cw)
direction as seen looking along the z
direction. - What is the magnetic field Bz(A) at point A, the
midpoint between the two loops?
(b) Bz(A) 0
(c) Bz(A) gt 0
(a) Bz(A) lt 0
- What is the magnetic field Bz(B) at point B,
just to the right of the right loop?
(c) Bz(B) gt 0
(b) Bz(B) 0
(a) Bz(B) lt 0
- The signs of the fields from each loop are the
same at B as they are at A!
- However, point B is closer to the right loop,
so its field wins!
35Circular Loop
R
B
z
0
0
z