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The Laws of Biot-Savart

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Ampere's Law. These are the analogous equations for the Magnetic Field! ... Applying Ampere's Law, we see that the field at point a must just be the field ... – PowerPoint PPT presentation

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Title: The Laws of Biot-Savart


1
Magnetism
  • The Laws of Biot-Savart Ampere

2
Overview of Lecture
  • Fundamental Law for Calculating Magnetic Field
  • Biot-Savart Law (brute force)
  • Amperes Law (high symmetry)
  • Example Calculate Magnetic Field of Straight
    Wire
  • from Biot-Savart Law
  • from Amperes Law
  • Calculate Force on Two Parallel Current-Carrying
    Conductors

Text Reference Chapter 30.1-4
3
Calculation of Electric Field
  • Two ways to calculate the Electric Field
  • Coulomb's Law
  • Gauss' Law
  • What are the analogous equations for the Magnetic
    Field?

4
Calculation of Magnetic Field
  • Two ways to calculate the Magnetic Field
  • Biot-Savart Law
  • Ampere's Law
  • These are the analogous equations for the
    Magnetic Field!

5
Biot-Savart Lawbits and pieces
(1819)
So, the magnetic field circulates around the
wire
6
Magnetic Field of Straight Wire
  • Calculate field at point P using Biot-Savart Law

Which way is B?
  • Rewrite in terms of R,q

7
Magnetic Field of Straight Wire
8
Lecture 14, ACT 1
  • What is the magnitude of the magnetic field at
    the center of a loop of radius R, carrying
    current I?

9
Lecture 14, ACT 1
  • What is the magnitude of the magnetic field at
    the center of a loop of radius R, carrying
    current I?
  • To calculate the magnetic field at the center,
    we must use the Biot-Savart Law
  • Two nice things about calculating B at the
    center of the loop
  • Idx is always perpendicular to r
  • r is a constant (R)

10
Magnetic Field of Straight Wire
  • Calculate field at distance R from wire using
    Ampere's Law

  • Choose loop to be circle of radius R centered on
    the wire in a plane to wire.
  • Why?
  • Magnitude of B is constant (fcn of R only)
  • Direction of B is parallel to the path.
  • Current enclosed by path I
  • Ampere's Law simplifies the calculation thanks to
    symmetry of the current! ( axial/cylindrical )

11
Lecture 14, ACT 2
  • A current I flows in an infinite straight wire in
    the z direction as shown. A concentric infinite
    cylinder of radius R carries current 2I in the -z
    direction.
  • What is the magnetic field Bx(a) at point a, just
    outside the cylinder as shown?
  • What is the magnetic field Bx(b) at point b,
    just inside the cylinder as shown?

12
Lecture 14, ACT 2
  • A current I flows in an infinite straight wire in
    the z direction as shown. A concentric infinite
    cylinder of radius R carries current 2I in the -z
    direction.
  • What is the magnetic field Bx(a) at point a, just
    outside the cylinder as shown?
  • This situation has massive cylindrical symmetry!
  • Applying Amperes Law, we see that the field at
    point a must just be the field from an infinite
    wire with current I flowing in the -z direction!

13
Lecture 14, ACT 2
  • A current I flows in an infinite straight wire in
    the z direction as shown. A concentric infinite
    cylinder of radius R carries current 2I in the -z
    direction.
  • What is the magnetic field Bx(a) at point a, just
    outside the cylinder as shown?

What is the magnetic field Bx(b) at point b,
just inside the cylinder as shown?
  • Just inside the cylinder, the total current
    enclosed by the Ampere loop will be I in the z
    direction!
  • Therefore, the magnetic field at b will just be
    minus the magnetic field at a!!

14
Question
  • How do we check this result??
  • i.e. expect B from wire to be proportional to I/R.
  • Measure FORCE on current-carrying wire due to the
    magnetic field PRODUCED by ANOTHER current
    carrying wire!
  • How does force depend on currents and separation?

15
Force on 2 ParallelCurrent-Carrying Conductors
  • Calculate force on length L of wire b due to
    field of wire a
  • The field at b due to a is given by
  • Calculate force on length L of wire a due to
    field of wire b
  • The field at a due to b is given by

16
Lecture 14, ACT 3
  • A current I flows in the positive y direction in
    an infinite wire a current I also flows in the
    loop as shown in the diagram.
  • What is Fx, net force on the loop in the
    x-direction?

17
Lecture 14, ACT 3
  • A current I flows in the positive y direction in
    an infinite wire a current I also flows in the
    loop as shown in the diagram.
  • What is Fx, net force on the loop in the
    x-direction?
  • You may have remembered from a previous ACT
    that the net force on a current loop in a
    constant magnetic field is zero.
  • However, the magnetic field produced by the
    infinite wire is not a constant field!!
  • The forces on the left and right segments of
    the loop DO NOT cancel!!
  • The left segment of the loop is in a larger
    magnetic field.
  • Therefore, Fleft gt Fright

18
  • Examples of Magnetic Field Calculations

19
Overview of Lecture
  • Calculate Magnetic Fields
  • Inside a Long Straight Wire
  • Infinite Current Sheet
  • Solenoid
  • Toroid
  • Circular Loop

Text Reference Chapter 30.1-5
20
Today is Amperes Law Day
"High symmetry"
21
B Field Insidea Long Wire
  • Suppose a total current I flows through the wire
    of radius a into the screen as shown.
  • Calculate B field as a fcn of r, the distance
    from the center of the wire.
  • B field is only a fcn of r Þ take path to be
    circle of radius r
  • Current passing through circle
  • Ampere's Law

22
B Field of aLong Wire
  • Inside the wire (r lt a)
  • Outside the wire (rgta)

23
Lecture 15, ACT 1
  • Two cylindrical conductors each carry current I
    into the screen as shown. The conductor on the
    left is solid and has radius R3a. The conductor
    on the right has a hole in the middle and carries
    current only between Ra and R3a.
  • What is the relation between the magnetic field
    at R 6a for the two cases (Lleft, Rright)?

24
Lecture 15, ACT 1
  • Two cylindrical conductors each carry current I
    into the screen as shown. The conductor on the
    left is solid and has radius R3a. The conductor
    on the right has a hole in the middle and carries
    current only between Ra and R3a.
  • What is the relation between the magnetic field
    at R 6a for the two cases (Lleft, Rright)?
  • Amperes Law can be used to find the field in
    both cases.
  • The Amperian loop in each case is a circle of
    radius R6a in the plane of the screen.
  • The field in each case has cylindrical symmetry,
    being everywhere tangent to the circle.
  • Therefore the field at R6a depends only on the
    total current enclosed!!
  • In each case, a total current I is enclosed.

25
Lecture 15, ACT 1
  • Two cylindrical conductors each carry current I
    into the screen as shown. The conductor on the
    left is solid and has radius R3a. The conductor
    on the right has a hole in the middle and carries
    current only between Ra and R3a.
  • What is the relation between the magnetic field
    at R 6a for the two cases (Lleft, Rright)?
  • Once again, the field depends only on how much
    current is enclosed.
  • For the LEFT conductor
  • For the RIGHT conductor

26
B Field of Current Sheet
  • Consider an sheet of current described by n
    wires/length each carrying current i into the
    screen as shown. Calculate the B field.
  • What is the direction of the field?
  • Symmetry Þ y direction!
  • Calculate using Ampere's law using a square of
    side w

27
B Field of a Solenoid
  • A constant magnetic field can (in principle) be
    produced by an sheet of current. In practice,
    however, a constant magnetic field is often
    produced by a solenoid.
  • If a ltlt L, the B field is to first order
    contained within the solenoid, in the axial
    direction, and of constant magnitude. In this
    limit, we can calculate the field using Ampere's
    Law.

28
B Field of a Solenoid
  • To calculate the B field of the solenoid using
    Ampere's Law, we need to justify the claim that
    the B field is 0 outside the solenoid.
  • To do this, view the solenoid from the side as
    2 current sheets.
  • The fields are in the same direction in the
    region between the sheets (inside the solenoid)
    and cancel outside the sheets (outside the
    solenoid).
  • Draw square path of side w

29
Toroid
  • Toroid defined by N total turns with current i.
  • B0 outside toroid! (Consider integrating B on
    circle outside toroid)
  • To find B inside, consider circle of radius r,
    centered at the center of the toroid.

Apply Amperes Law
30
Circular Loop
  • Circular loop of radius R carries current i.
    Calculate B along the axis of the loop
  • Magnitude of dB from element dl
  • What is the direction of the field?
  • Symmetry Þ B in z-direction.

Þ
31
Circular Loop
Þ
  • Note the form the field takes for zgtgtR
  • Expressed in terms of the magnetic moment

note the typical dipole field behavior!
Þ
32
Lecture 15, ACT 2
  • Equal currents I flow in identical circular loops
    as shown in the diagram. The loop on the
    right(left) carries current in the ccw(cw)
    direction as seen looking along the z
    direction.
  • What is the magnetic field Bz(A) at point A, the
    midpoint between the two loops?

33
Lecture 15, ACT 2
  • Equal currents I flow in identical circular loops
    as shown in the diagram. The loop on the
    right(left) carries current in the ccw(cw)
    direction as seen looking along the z
    direction.
  • What is the magnetic field Bz(A) at point A, the
    midpoint between the two loops?

(b) Bz(A) 0
(c) Bz(A) gt 0
(a) Bz(A) lt 0
  • The right current loop gives rise to Bz lt0 at
    point A.
  • The left current loop gives rise to Bz gt0 at
    point A.
  • From symmetry, the magnitudes of the fields
    must be equal.
  • Therefore, B(A) 0!

34
Lecture 15, ACT 2
  • Equal currents I flow in identical circular loops
    as shown in the diagram. The loop on the
    right(left) carries current in the ccw(cw)
    direction as seen looking along the z
    direction.
  • What is the magnetic field Bz(A) at point A, the
    midpoint between the two loops?

(b) Bz(A) 0
(c) Bz(A) gt 0
(a) Bz(A) lt 0
  • What is the magnetic field Bz(B) at point B,
    just to the right of the right loop?

(c) Bz(B) gt 0
(b) Bz(B) 0
(a) Bz(B) lt 0
  • The signs of the fields from each loop are the
    same at B as they are at A!
  • However, point B is closer to the right loop,
    so its field wins!

35
Circular Loop
R
B
z
0
0
z
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