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where X and Y are T and V, respectively. Department of Atmospheric Sciences ... where X and Y are T and p, respectively. For a process of heating at V = const we get ... – PowerPoint PPT presentation

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Title: Ch.%204%20


1
Ch. 4 1st Law of Thermodynamics
  • Heat Capacities
  • Consider a homogeneous system of constant
    composition
  • Write dU (dH) as a total differential of the
    independent variables X and Y (for our purposes,
    X and Y could be any pair of p, V, and T). Then
  • From the 1st Law, ?Q dU pdV, we can
    substitute to get
  • where X and Y are T and V, respectively.

2
Ch. 4 1st Law of Thermodynamics
  • Heat Capacities
  • From ?Q dH Vdp we can substitute for dH to
    get
  • where X and Y are T and p, respectively.
  • For a process of heating at V const we get
  • or per unit mass we can write

3
Ch. 4 1st Law of Thermodynamics
  • Heat Capacities
  • For a process of heating at p const we get
  • or per unit mass we can write
  • Can also calculate heat of change of V and p at T
    const
  • Not very useful, but given for completeness

4
Ch. 4 1st Law of Thermodynamics
  • Calculation of Internal Energy and Enthalpy
  • Our equations for CV and Cp can be integrated
    directly for processes with V const and p
    const, respectively to find U and H, if CV and Cp
    are known as functions of T
  • CV and Cp, from experiment, are usually
    polynomials in T

5
Ch. 4 1st Law of Thermodynamics
  • Calculation of Internal Energy and Enthalpy
  • Consider 2 rigid vessels linked by a connection
    with a stopcock (pg. 34). One contains gas, the
    other evacuated.
  • Stopcock opened, gas in 1 expands to occupy both
    vessels.
  • Temperature measurements show that system
    exchanges no heat with environment ? no work
    done, Q 0, W 0, and ?U 0.
  • Since p changed during process, we have U U(T)
    only and partial derivative used above are total
    derivatives.

6
Ch. 4 1st Law of Thermodynamics
  • Calculation of Internal Energy and Enthalpy
  • Notes on this experiment
  • When experiment done carefully, small heat
    exchange was found (Joule-Thomson effect), which
    vanishes for ideal gas behavior
  • As gas confined in vessel 1 expands into 2, work
    is done by some portions of gas against others
    while volumes change (as molecules enter 2, they
    are effected by molecules following)
  • These are internal transfers that are not
    included in W
  • This shows the importance of defining system
    carefully and clearly when considering a
    thermodynamic process
  • In this case, the system is all the gas contained
    in both vessels (initially one is empty), whose
    total volume (V1 V2) does not change

7
Ch. 4 1st Law of Thermodynamics
  • More on Heat Capacities
  • As noted above, since U U(T) we have CV dU/dT
    and cv du/dT
  • We can write H U pV U nRT H(T)
    leading to Cp dH/dT and cp dh/dT
  • Since we are only interested in differences in
    internal energy and enthalpy, we can set the
    integration constant to 0 giving U ? CVT, H ?
    CpT, u ? cvT, and h ? cpT

8
Ch. 4 1st Law of Thermodynamics
  • More on Heat Capacities
  • Since we have CV dU/dT, Cp dH/dT and H U
    pV U nRT, we have
  • leading to Cp CV nR ? cp cv R recalling
    that n m/M.
  • As mentioned earlier, heat capacities for all
    gases can be measured and the coefficients for
    the polynomial expansion can be determined (C ?
    ?T ?T2 )

9
Ch. 4 1st Law of Thermodynamics
  • More on Heat Capacities
  • For simple gases like N2, O2, and Ar, the
    experimental data are nearly constant for all
    temperatures and pressures of interest, so the
    temperature variation is not considered.
  • From earlier we have, for monatomic gases, the
    total internal energy is U (3/2)NkT, which
    leads to CV (3/2)nR and cv (3/2)R.
    Similarly, Cp (5/2)nR and cp (5/2)R.
  • For diatomic gases, where there are more degrees
    of freedom, so we get CV (5/2)nR and cv
    (5/2)R. Similarly, Cp (7/2)nR and cp
    (7/2)R. The ratios Cp/CV cp/cv ?.

10
Ch. 4 1st Law of Thermodynamics
  • More on Heat Capacities
  • Dry air is considered to be a diatomic gas, so
    the second form applies.
  • The ratio, cp/cv ? 1.4.
  • We then attach the subscript, d, to the specific
    heats to indicate dry air.
  • This leads to cvd 718 J kg-1 K-1 and cpd 1005
    J kg-1 K-1 and Rd cpd cvd 287(.05) J kg-1
    K-1.

11
Ch. 4 1st Law of Thermodynamics
  • More on Heat Capacities
  • The table below shows the values of cpd for
    various temperatures and pressures. Note the
    slight variation.

12
Ch. 4 1st Law of Thermodynamics
  • More Forms of the 1st Law
  • Using the above expressions for (specific) heat
    capacities, we get more useful forms of the 1st
    Law, two of which are particularly useful
  • and

13
Ch. 4 1st Law of Thermodynamics
  • Special Cases
  • For an isothermal transformation
  • For an isochoric (constant volume) transformation
  • For an isobaric transformation
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