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Pipeline Hydraulics

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Title: Pipeline Hydraulics


1
Pipeline Hydraulics
2
Importance
  • Irrigation hydraulics involves
  • The determination of the pressure distribution in
    the system
  • The selection of pipe sizes and fittings to
    convey and regulate water delivery
  • The determination of the power and energy
    requirements to pressurize and lift water

3
Basic Relationships
  • Q Vm Af
  • Flow rate (velocity) x (cross-sectional area)
  • Called the continuity equation
  • Units must be consistent
  • Maximum recommended V in a pipeline is about 5
    feet/second

4
Maximum Flow Rates in Pipelines
5
Energy
  • Forms of energy available in water
  • Kinetic energy due to velocity
  • Potential energy due to elevation
  • Potential energy due to pressure

6
Units
  • Energy per unit weight of water "head
  • Energy (ft-lb)/Weight (lb) Head (ft)
  • Velocity head Elevation head Pressure head
  • Length units (e.g., feet, meters) 

7
Velocity Head
  • Velocity head
  •  
  • g gravitational constant 32.2 ft/s2
  • when V is 5 ft/s, V2/(2g) is only about 0.4 ft
    (usually negligible)

8
Elevation Head
  • Elevation head (gravitational head) Z
  • Height of water above some arbitrary reference
    point (datum)
  • Water at a higher elevation has more potential
    energy than water at a lower elevation

9
Pressure Head
  • Pressure force per unit area (e.g., pounds per
    square inch)
  • Pressure head pressure per unit weight of water
  • h P / ?
  • h pressure head , P pressure
  • ? weight of a unit volume of water
  • ? 62.4 lb/ft3 0.433 psi/ft
  • 1/ ? 2.31ft/psi
  • h 2.31P (P is in psi h in ft)

10
Calculate P at the Bottom of a Column of Water
When depth of 2 ft is considered V 2 ft3 W 2
ft3 62.4 lb/ft3 124.8 lb A 144 in2 P
W/A 124.8lb / 144 in2 0.866 lb/in2 If
depth is 1ft then V 1 ft3 W 62.4lb P
62.4lb/144in2 0.433lb/in2
11
Calculate P at the Bottom of a Column of Water
V 2 ft3 W 124.8 lb A 2ft2 288 in2 P
124.8lb / 288in2 0.433 lb/in2
The area of a pond or tank does not affect
pressure. Pressure is a function of water depth
only.
12
Manometer Rising up From a Pipeline
Pressure, P lb/ft2 ? specific weight of
water, (62.4 lb/ft3)
HP/g
13
  • hydraulic head, H
  • Bernoullis equation (conservation of energy)
  • H1 H2 hL
  • H1 hydraulic head at point 1 in a system
  • H2 hydraulic head at point 2 in a system
  • hL head loss during flow from point 1 to
    point 2 (hL is due to friction loss)

14
Components of Hydraulic Head for Pipeline With
Various Orientations
hL
15
Components of Hydraulic Head for Pipeline With
Various Orientations Contd
hL
16
Components of Hydraulic Head for Pipeline With
Various Orientations Contd
hL
17
Friction Loss
  • Description
  • energy loss due to flow resistance as a fluid
    moves in a pipeline
  • Factors affecting
  • flow rate
  • pipe diameter
  • pipe length
  • pipe roughness
  • type of fluid

18
Ways of Calculating Friction Loss
  • Equations
  • Hazen-Williams is one of many (eqn 8.8)
  • Tables
  • for a given pipe material, pipe diameter, and
    flow rate, look up values for friction loss in
    feet per hundred feet of pipe
  •  SDR standard dimension ratio pipe
    diameter ? wall thickness

19
Dimensional Comparison of Sch. 40, Class 160, and
Class 125 PVC Pipe
20
Friction Loss for IPS PVC Pipe
IPS Iron Pipe Size (same dimensions as steel
pipe of same nominal size)
21
Friction Loss for IPS PVC Pipe contd
22
Example Problem
  • A 4-inch nominal diameter PVC pipe has a
    outside diameter of 4.5 inches and a wall
    thickness of 0.173 inches. What is the pipe SDR?
  • Solution SDR Diameter/Wall Thickness
  • SDR 4.50/0.173 26.0

23
Pipes With Multiple Outlets
  • lower friction loss because V decreases with
    distance down the pipe
  • (Q decreases as flow is lost through the
    outlets VQ/A)
  • first calculate friction loss as if there were no
    outlets, and then multiply by the "multiple
    outlet factor", F

24
Multiple Outlet Factors for Laterals With Equally
Spaced Outlets of the Same Discharge
25
Example Problem
  • A 2-inch diameter, SDR 21 PVC pipe carries a
    flow of 60 gpm. The flow is discharged through 15
    sprinklers evenly spread along its 600-ft length.
    What is the total head loss in the pipe?
  • Solution Hf 4.62 ft / 100 ft (Table 8.2)
  • Hf 4.62 600 ft / 100 ft 27.72 ft
  • F 0.379 (Table 8.3 15 outlets)
  • Hf 27.72 ft 0.379 10.51 ft

26
Minor Losses
  • Source of minor losses
  • fittings, valves, bends, elbows, etc
  • friction, turbulence, change in flow direction,
    etc
  • hm head loss in fitting (ft)
  • K resistance coefficient for fitting

27
Resistance Coefficient H for Use Determining Head
Losses in Fittings and Valves
28
Calculation Shortcuts
  • V in ft/s
  • Q in gpm
  • D in inches (INSIDE diameter)
  • hm in ft
  • Q in gpm
  • D in inches (INSIDE diameter)

29
Example Problem
  • A 4-inch pipe carries a flow of 160 gpm. How
    much head loss occurs when the flow passes
    through a 90o elbow (flanged, regular radius) ?
  • Solution K 0.31
  • (Table 8.4 4-in, regular 90o elbow)
  • D 4.0 inches
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