Title: Pipeline Hydraulics
1Pipeline Hydraulics
2Importance
- Irrigation hydraulics involves
- The determination of the pressure distribution in
the system - The selection of pipe sizes and fittings to
convey and regulate water delivery - The determination of the power and energy
requirements to pressurize and lift water
3Basic Relationships
- Q Vm Af
- Flow rate (velocity) x (cross-sectional area)
- Called the continuity equation
- Units must be consistent
- Maximum recommended V in a pipeline is about 5
feet/second
4Maximum Flow Rates in Pipelines
5Energy
- Forms of energy available in water
- Kinetic energy due to velocity
- Potential energy due to elevation
- Potential energy due to pressure
6Units
- Energy per unit weight of water "head
- Energy (ft-lb)/Weight (lb) Head (ft)
- Velocity head Elevation head Pressure head
- Length units (e.g., feet, meters)
7Velocity Head
- Velocity head
-
- g gravitational constant 32.2 ft/s2
- when V is 5 ft/s, V2/(2g) is only about 0.4 ft
(usually negligible)
8Elevation Head
- Elevation head (gravitational head) Z
- Height of water above some arbitrary reference
point (datum) - Water at a higher elevation has more potential
energy than water at a lower elevation
9Pressure Head
- Pressure force per unit area (e.g., pounds per
square inch) - Pressure head pressure per unit weight of water
- h P / ?
- h pressure head , P pressure
- ? weight of a unit volume of water
- ? 62.4 lb/ft3 0.433 psi/ft
- 1/ ? 2.31ft/psi
- h 2.31P (P is in psi h in ft)
10Calculate P at the Bottom of a Column of Water
When depth of 2 ft is considered V 2 ft3 W 2
ft3 62.4 lb/ft3 124.8 lb A 144 in2 P
W/A 124.8lb / 144 in2 0.866 lb/in2 If
depth is 1ft then V 1 ft3 W 62.4lb P
62.4lb/144in2 0.433lb/in2
11Calculate P at the Bottom of a Column of Water
V 2 ft3 W 124.8 lb A 2ft2 288 in2 P
124.8lb / 288in2 0.433 lb/in2
The area of a pond or tank does not affect
pressure. Pressure is a function of water depth
only.
12Manometer Rising up From a Pipeline
Pressure, P lb/ft2 ? specific weight of
water, (62.4 lb/ft3)
HP/g
13- hydraulic head, H
- Bernoullis equation (conservation of energy)
- H1 H2 hL
- H1 hydraulic head at point 1 in a system
- H2 hydraulic head at point 2 in a system
- hL head loss during flow from point 1 to
point 2 (hL is due to friction loss)
14Components of Hydraulic Head for Pipeline With
Various Orientations
hL
15Components of Hydraulic Head for Pipeline With
Various Orientations Contd
hL
16Components of Hydraulic Head for Pipeline With
Various Orientations Contd
hL
17Friction Loss
- Description
- energy loss due to flow resistance as a fluid
moves in a pipeline - Factors affecting
- flow rate
- pipe diameter
- pipe length
- pipe roughness
- type of fluid
18Ways of Calculating Friction Loss
- Equations
- Hazen-Williams is one of many (eqn 8.8)
- Tables
- for a given pipe material, pipe diameter, and
flow rate, look up values for friction loss in
feet per hundred feet of pipe - SDR standard dimension ratio pipe
diameter ? wall thickness
19Dimensional Comparison of Sch. 40, Class 160, and
Class 125 PVC Pipe
20Friction Loss for IPS PVC Pipe
IPS Iron Pipe Size (same dimensions as steel
pipe of same nominal size)
21Friction Loss for IPS PVC Pipe contd
22Example Problem
- A 4-inch nominal diameter PVC pipe has a
outside diameter of 4.5 inches and a wall
thickness of 0.173 inches. What is the pipe SDR? - Solution SDR Diameter/Wall Thickness
- SDR 4.50/0.173 26.0
23Pipes With Multiple Outlets
- lower friction loss because V decreases with
distance down the pipe - (Q decreases as flow is lost through the
outlets VQ/A) - first calculate friction loss as if there were no
outlets, and then multiply by the "multiple
outlet factor", F
24Multiple Outlet Factors for Laterals With Equally
Spaced Outlets of the Same Discharge
25Example Problem
- A 2-inch diameter, SDR 21 PVC pipe carries a
flow of 60 gpm. The flow is discharged through 15
sprinklers evenly spread along its 600-ft length.
What is the total head loss in the pipe? - Solution Hf 4.62 ft / 100 ft (Table 8.2)
- Hf 4.62 600 ft / 100 ft 27.72 ft
- F 0.379 (Table 8.3 15 outlets)
- Hf 27.72 ft 0.379 10.51 ft
26Minor Losses
- Source of minor losses
- fittings, valves, bends, elbows, etc
- friction, turbulence, change in flow direction,
etc - hm head loss in fitting (ft)
- K resistance coefficient for fitting
27Resistance Coefficient H for Use Determining Head
Losses in Fittings and Valves
28Calculation Shortcuts
- V in ft/s
- Q in gpm
- D in inches (INSIDE diameter)
- hm in ft
- Q in gpm
- D in inches (INSIDE diameter)
29Example Problem
- A 4-inch pipe carries a flow of 160 gpm. How
much head loss occurs when the flow passes
through a 90o elbow (flanged, regular radius) ? - Solution K 0.31
- (Table 8.4 4-in, regular 90o elbow)
- D 4.0 inches