Title: Nikolai Lobachevsky (1792-1856)
1Nikolai Lobachevsky (1792-1856)
- Born 1 Dec 1792 in Nizhny Novgorod, RussiaDied
24 Feb 1856 in Kazan, Russia - Went to school and studied in Kazan under Martin
Bartels (1769 - 1833), who was a friend of Gauss. - 1811 Master's Degree in physics and mathematics.
- 1814 he was appointed to a lectureship
- 1816 he became an extraordinary professor.
- 1822 he was appointed as a full professor
- 1820 -1825 dean of the Math. and Physics
Department - 1827 he became rector of Kazan University
2Nikolai Lobachevsky (1792-1856)
- Accepting the possibility of HAA Lobachevsky
redefines parallels in the following way - 16. All straight lines which in a plane go out
from a point can, with reference to a given
straight line in the same plane, be divided into
two classes - into cutting and non-cutting. The
boundary lines of the one and the other class of
those lines will be called parallel to the given
line.
3Nikolai Lobachevsky (1792-1856)
4Nikolai Lobachevsky (1792-1856)
- Depending on the angle HAD which is called ?(p)
there are two possibilities. - Either
- ?(p)p/2 and there is only one parallel to CB
through A, - or
- ?(p)ltp/2 there are exactly two Lobachevsky
parallels. - This means that there are infinitely many lines
through A which do not intersect CB.
5Nikolai Lobachevsky (1792-1856)
- In the case that there are two parallels there
are also two sides of parallelism.
l
The side of parallelism of l
?(p)
p
?(p)
The side of parallelism of l
l
6Nikolai Lobachevsky (1792-1856)
- Lobachevsky needs to prove the following.
- His definition of parallelism uses the point A,
he has to show that in fact parallelism is a
symmetric property of two lines - 17. A straight line maintains the characteristic
of parallelism at all its points. - 18. Two lines are always mutually parallel.
-
-
7Nikolai Lobachevsky (1792-1856)
- He shows that HOA is not possible with the first
four of Euclids axioms (which he made more
precise e.g. 3). - 19. In a rectilineal triangle the sum of the
three angles can not be greater than two right
angles. -
-
8Nikolai Lobachevsky (1792-1856)
- He also shows that if one triangle has the
property that the sum of the interior angels is
180, then all triangles have this property. - This is the dichotomy between Euclidean geometry
(HRA) and non-Euclidian geometry (HAA). - 20. If in any rectilineal triangle the sum of
the three angles is equal to two right angles, so
is this also the case for every other triangle.
9Nikolai Lobachevsky (1792-1856)
- Finally he shows that the dichotomy extends to
parallels. - In Euclidean geometry there is exactly one
parallel line to a given line through a given
point not on that line. - In non-Euclidean geometry there are exactly two
parallel lines, in Lobachevskys sense, which
implies that there are infinitely many lines
through the point that do not intersect the given
line. - 22. If two perpendiculars to the same straight
line are parallel to each other then the sum of
the three angles in a rectilineal triangle is
equal to two right angels.
10Lobachevskys Euclidean and non-Euclidean geometry
- Euclidean or plane geometry is the geometry in
which the equivalent assumptions - For all lines and points p ?(p) p/2 and
equivalently - The sum of the interior angles of any triangle
p - hold.
- Non-Euclidean (imaginary) geometry is the
geometry in which the equivalent assumptions - For all lines and points p ?(p)lt p/2 and
equivalently - The sum of the interior angles of any triangle lt
p - hold.
11Nikolai Lobachevskys Non-Euclidean geometry
- Now assume that for all lines and points p ?(p)lt
p/2. - In this case parallels can have any angle which
is less than p/2 and moreover for any given angle
there is always a pair of parallels whose angle
is that angle - 23. For every given angle ? there is a line p
such that ?(p) ?.
12Nikolai Lobachevskys Non-Euclidean geometry
- Parallels cease to have the same distance to
each other at all points rather - 24. The farther parallel lines are prolonged on
the side of their parallelism, the more they
approach on another.
B
B
x
s
s
A
A
x
Moreover in the above figure sse-x.