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Spontaneity of Reaction

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Chapter 17 Spontaneity of Reaction Thermodynamic functions of enthalpy, entropy, and Gibbs free energy. Chapter 17 Spontaneous reactions: examples - CH4(g) + 2O2(g ... – PowerPoint PPT presentation

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Title: Spontaneity of Reaction


1
Chapter 17
  • Spontaneity of Reaction
  • Thermodynamic functions of enthalpy, entropy, and
    Gibbs free energy.

2
Chapter 17
  • Spontaneous reactions examples -
  • CH4(g) 2O2(g) --gt CO2(g) 2 H2O(l)
  • H2O(s) --gt H2O(l) at 25oC.

3
Spontaneity Factors
  • 1.) Energy factor at 25oC, 1 atm, exothermic
    reactions are ordinarily spontaneous (nature
    tends toward stability)

4
Spontaneity Factors
  • 2.) Randomness factor other things being equal,
    systems tend move from a more ordered to a more
    random state.

5
Spontaneity Factors
  • Nature tends toward disorder (the entropy of the
    universe is increasing).

6
Entropy Changes
  • ?S S products - S reactants measure of change
    in order (randomness)
  • Ex. Solid --gt liquid ?S positive

7
Entropy Changes
  • ?S is usually positive for a reaction in which
    the number of moles of gas increases.

8
Entropy Changes
  • Determine if the entropy of the following
    reactions will be positive or negative.
  • 2 SO3(g)--gt2 SO2(g) O2(g)
  • N2(g) 3 H2(g) --gt 2 NH3(g)
  • first reaction positive, second negative.

9
Entropy Changes
  • ?So calculations (?S at 1atm, 25oC - see chart).
  • ?So ?So products - ?So reactants.
  • ?S is positive for elements and compounds.

10
Entropy Changes
  • Reactions/processes for which ?So is positive
    tend to be spontaneous, at least at high
    temperatures

11
Entropy Changes
  • H2O(s)--gtH2O(l),?So gt 0
  • H2O(l)--gtH2O(g),?So gt 0
  • Fe2O3(s)3H2(g)--gt 2Fe(s) 3 H2O(g), ?So gt 0.
  • All are endothermic, but become spontaneous at
    high temps.

12
Free Energy Changes
  • ?Go represents the useful energy available for
    work. Negative energy available from the
    reaction to do work.
  • Positive energy needed to get the reaction to
    occur.

13
Free Energy Changes
  • ?Go is a state function and is dependent only on
    the initial states of the reactants and not the
    pathway of the reaction.

14
Free Energy Changes
  • ?Go ??o - T?So
  • Note that ?G, like ?S, is dependent on pressure
    and concentration. Unlike ?Ho and ?So, Go is
    strongly temperature dependent.

15
Free Energy Changes
  • If ?Go lt 0, reaction is spontaneous at standard
    conditions (1 M conc., 1 atm P).
  • If Go gt 0, reaction is nonspontaneous at standard
    conditions.

16
Free Energy Changes
  • If Go 0, reaction is at equilibrium at standard
    conditions.

17
Free Energy Changes
  • Effect of ?Ho and ?So on spontaneity
  • If ?Ho gt 0, ?So lt 0, and ?Go gt 0 at all temps?
  • If ?Ho lt 0, ?So gt 0, and ?Go lt 0 at all temps?

18
Free Energy Changes
  • If ?Ho gt 0, ?So gt 0, and ?Go gt 0 at low temps?
    High temps?
  • If ?Ho lt 0, ?So lt 0, and ?Go lt 0 at low temps?
    High temps?

19
Free Energy Changes
  • Calculation of ?Go from ?So and ?Ho.
  • Fe2O3(s)3H2(g)--gt 2Fe(s) 3 H2O(g). What is ?Go
    at 25oC? 500oC?
  • 56.6kJ, -10.6 kJ.

20
Free Energy Changes
  • At what temp does the reduction of iron (III)
    oxide by hydrogen become spontaneous at 1 atm?
  • T 96.8/0.1387 698 K.

21
Free Energy Changes
  • Calculation ?Go at 25oC from, ?Gof
  • ?Go (? ?Gof products) -
  • (? ? Gof reactants).

22
Free Energy Changes
  • Calculation ?G from ?Go
  • ?G ?Go RT ln Q.
  • R 0.00831 kJ/K

23
Free Energy Changes
  • Given that ?Go lead (II) chloride ionizing in
    solution is 27.3 kJ and that the concentration of
    Pb2 and Cl- are each 0.0010 M,calculate ?G of
    this reaction (at 25oC).
  • -24.0 kJ

24
Free Energy Changes
  • Relationship of ?G and K (Keq).
  • ?Go -RT ln K.
  • If K gt 1, ?Go lt 0, reaction is spontaneous at
    standard conditions.

25
Free Energy Changes
  • Relationship of ?G and K (Keq).
  • ?Go -RT ln K.
  • If K lt 1, ?Go gt 0, reaction is nonspontaneous at
    standard conditions.

26
Free Energy Changes
  • Relationship of ?G and K (Keq).
  • ?Go -RT ln K.
  • If K 1, ?Go 0, reaction is at equilibrium at
    standard conditions.
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