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Average Atomic Mass

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Title: Average Atomic Mass


1
Average Atomic Mass
2
Chapter 7.4Average Atomic Mass
  • Objective
  • (1) To calculate the average atomic mass for an
    atom.

3
Average Atomic Mass
  • Weighted average of the masses of the existing
    isotopes of an element.

4
Recall Atomic Mass Unit
  • The unit that describes the mass of an atom
  • Symbol amu

5
Example 1
  • The mass of a Cu-63 atom is 62.94 amu, and that
    of a Cu-65 atom is 64.93 amu. The percent
    abundance of Cu-63 is 69.17 and the percent
    abundance of Cu-65 is 30.83. What is the
    average atomic mass of Cu?

6
Example 1
  • The mass of a Cu-63 atom is 62.94 amu, and that
    of a Cu-65 atom is 64.93 amu. The percent
    abundance of Cu-63 is 69.17 and the percent
    abundance of Cu-65 is 30.83. What is the
    average atomic mass?
  • Step 1 Find the contribution of each isotope
  • Cu-63 (62.94 amu) x (0.6917) 43.535598 amu
  • Cu-65 (64.93 amu) x (0.3083) 20.017919 amu
  • Step 2 Add the relative abundances from each
    isotope together.
  • 43.535598 amu 20.017919 amu 63.553517 amu
  • Round answer to two numbers after the decimal
    63.55 amu

7
Example 2
  • Calculate the average atomic mass of chromium.
    It is made up of isotopes with the following
    percent compositions and atomic masses 83.79
    with a mass of 51.94 amu 9.50 with a mass of
    52.94 amu 4.35 with a mass of 49.95 amu 2.36
    with a mass of 53.94 amu.

8
Example 2
  • Calculate the average atomic mass of chromium.
    It is made up of isotopes with the following
    percent compositions and atomic masses 83.79
    with a mass of 51.94 amu 9.50 with a mass of
    52.94 amu 4.35 with a mass of 49.95 amu 2.36
    with a mass of 53.94 amu.
  • Step 1 Find the contribution of each isotope
  • (51.94 amu) x (0.8379) 43.520526 amu
  • (52.94 amu) x (0.0950) 5.0293 amu
  • (49.95 amu) x (0.0435) 2.172825 amu
  • (53.94 amu) x (0.0236) 1.272984 amu
  • Step 2 Add the relative abundances from each
    isotope together.
  • 43.520526 amu 5.0293 amu 2.172825 amu
    1.272984 amu 51.995635 amu
  • Round answer to two numbers after the decimal
    52.00 amu

9
Example 3
  • Calculate the average atomic mass of iron if its
    abundance in nature is 15 iron-55 and 85
    iron-56.

10
Example 3
  • Calculate the average atomic mass of iron if its
    abundance in nature is 15 iron-55 and 85
    iron-56.
  • Step 1 Calculate the contribution of each
    isotope
  • Iron-55 (55 amu) x (0.15) 8.25 amu
  • Iron-56 (56 amu) x (0.85) 47.6 amu
  • Step 2 Add the contribution from each isotope
    together
  • 8.25 amu 47.6 amu 55.85 amu
  • The element with an atomic mass of 10.8 amu is
    Boron.

11
Example 4
  • Chlorine exists as chlorine-35, which has a mass
    of 34.969 amu and makes up 75.8 of chlorine
    atoms. The rest of naturally occurring chlorine
    is chlorine-37, with a mass of 36.996 amu. What
    is the average atomic mass of chlorine?

12
Example 4
  • Chlorine exists as chlorine-35, which has a mass
    of 34.969 amu and makes up 75.8 of chlorine
    atoms. The rest of naturally occurring chlorine
    is chlorine-37, with a mass of 36.996 amu. What
    is the average atomic mass of chlorine?
  • Step 1 Find the contribution of each isotope
  • Cl-35 (34.969 amu) x (0.758) 26.506502 amu
  • Cl-37 (36.996 amu) x (0.242) 8.953032 amu
  • Step 2 Add the relative abundances from each
    isotope together.
  • 26.506502 amu 8.953032 amu 35.459534 amu
  • Round answer to two numbers after the decimal
    35.46 amu

1 0.758
13
Example 5
  • Element X has two isotopes. One has a mass of
    10.0 amu and an abundance of 20.0. The other
    has a mass of 11.0 amu and an abundance of 80.0.
    Estimate the average atomic mass. What element
    is it?

14
Example 5
  • Element X has two isotopes. One has a mass of
    10.0 amu and an abundance of 20.0. The other
    has a mass of 11.0 amu and an abundance of 80.0.
    Estimate the average atomic mass. What element
    is it?
  • Step 1 Calculate the contribution of each
    isotope
  • Isotope 1 (10.0 amu) x (0.20) 2 amu
  • Isotope 2 (11.0 amu) x (0.80) 8.8 amu
  • Step 2 Add the contribution from each isotope
    together
  • 2 amu 8.8 amu 10.8 amu
  • The element with an atomic mass of 10.8 amu is
    Boron.
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