All Roads Lead to Mole City

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All Roads Lead to Mole City
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What Have We Learned Thus Far (10.1)
How to convert from molecules to moles/moles to
molecules
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Molecules to Mole .
If you have 7.36 x 1022 molecules of barium
sulfate, how many moles of BaSO4 do you have?
7.36 x 1022 molecules BaSO4
1 mole BaSO4
0.122 mole BaSO4
6.02 x 1023 molecules BaSO4
Molecules / Avogadros Moles
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Moles to Molecules.
If you have 0.632 moles of barium sulfate, how
many molecules of BaSO4 do you have?
0.632 moles BaSO4
6.02 x 1023 molecules BaSO4
3.80 x 1023 molecules BaSO4
1 mole BaSO4
Moles x Avogadros Molecules
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What Have We Learned Thus Far (10.1)
How to calculate the molar mass of a compound
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For instance .
What is the molar mass of CuHAsO3?
Cu 1(63.5) 63.5 g/mol H 1(1.0)
1.0 g/mol As 1(74.9) 74.9
g/mol O 3(16.0) 48.0 g/mol
187.4 g/mol
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What Have We Learned Thus Far (10.2)
How to convert from grams to moles/moles to grams
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Grams to Moles .
If you have 12.212 g of CuHAsO3. How many moles
do you have?
12.212 g CuHAsO3
1 mole CuHAsO3
.065165421 mole CuHAsO3
187.4 g CuHAsO3
Cu 1(63.5) 63.5 H 1(1.0)
1.0 As 1(74.9) 74.9 O 3(16.0)
48.0
.06517 mole CuHAsO3
6.517 x 10-2 mole CuHAsO3
187.4 g/mol
Grams / Molar Mass Moles
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Moles to Grams .
If you have 1.54 moles of CuHAsO3. How many grams
do you have?
1.54 mol CuHAsO3
187.4 g CuHAsO3
288.596 g CuHAsO3
1 mole CuHAsO3
Cu 1(63.5) 63.5 H 1(1.0)
1.0 As 1(74.9) 74.9 O 3(16.0)
48.0
289 g CuHAsO3 (only 3 sig figs)
187.4 g/mol
Moles x Molar Mass Grams
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Delayed Objective (10.2)
Learn how to convert between moles and volume (L,
gas)
We will learn this when we derive the Ideal Gas
Law in Chapter 14.3, but just multiply or
divide by 22.4 L
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All Roads Go Through Mole City
Divide by 6.02 x 1023
Molecule Town
Multiply by 6.02 x 1023
Divide by molar mass
Multiply by molar mass
Divide by 22.4 L
Gramville
Mole City
Multiply by 22.4 L
Gas Station
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Sample mixed mole problem Molecules to Grams
If you have 3.45 x 1025 molecules of NH3, how
many grams do you have?
3.45 x 1025 molecules NH3
1 mol NH3
17.0 g NH3
974.252 g NH3
6.02 x 1023 molecules NH3
1 mol NH3
974 g NH3
N 1(14.0) 14.0 g/mol H 3(1.0)
3.0 g/mol
molar mass NH3 17.0 g/mol
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Sample mixed mole problem Grams to
Molecules/Atoms
If you have 66.23 g of CO2, how many oxygen atoms
do you have?
6.02 x 1023 molecules CO2
66.23 g CO2
1 mol CO2
2 atoms oxygen
44.0 g CO2
1 mol CO2
1 molecule CO2
1.8123 x 1024 oxygen atoms
1.81 x 1024 oxygen atoms
C 1(12.0) 12.0 g/mol O 2(16.0)
32.0 g/mol
molar mass CO2 44.0 g/mol