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Title: Lecture 12: Phase diagrams


1
Lecture 12 Phase diagrams
  • PHYS 430/603 material
  • Laszlo Takacs
  • UMBC Department of Physics

2
Phases and the phase rule
  • Phase Uniform agglomeration of material - no
    boundaries inside
  • Gibbs phase rule f n - p 2
  • f degrees of freedom, i.e. number of freely
    selectable thermodynamic parameters. Typically
    temperature, pressure, concentrations.
  • n number of chemical components.
  • p number of phases in equilibrium
  • When phases are in equilibrium, atoms of any
    component can be transferred between phases.
    Equilibrium requires equal chemical potentials,
    mathematically equations that reduce the number
    of freely selectable parameters.

3
The phase diagram of UF6 as a function of p and
T n 1, thus f 3 - p
4
Pressure-temperature phase diagram of single
component systems sulfur and silicon dioxide.n
1, thus f 3 - p
5
The T-p phase diagram of FeUsually processes
are carried out at atmospheric pressure, thus we
will usually neglect the pressure dependence.
Extreme high pressure does cause phase changes.
6
  • n 2, thus f 4 - p
  • The phase diagram of a two-component system is
    usually shown for a fixed - ambient - pressure.
    The remaining variables are temperature and the
    concentration of either component. Notice
  • allotropic phases (Ti),
  • solid solutions,
  • compound phases,
  • two-phase regions,
  • transformations,
  • etc.

7
The lever rule on the amount of each phase in a
two-phase region
  • Sample is 1 mole total, contains
  • (1 - c) mole of component A
  • c mole of component B
  • We can also consider the sample as
  • m? mole of phase ? with c? plus
  • m? mole of phase ? with c?
  • Total of component A in the sample
  • 1 - c m? (1 - c?) m? (1 - c?)
  • Total of component B in the sample
  • c m? c? m? c?
  • The sum of these two equations gives
  • 1 m? m? as it should be.
  • From the last two equations we get
  • m? (c? - c) / (c? - c?)
  • m? (c - c?) / (c? - c?)
  • m? / m? (c? - c) / (c - c?)

?
?
c? c c?
c cB
A
B
Notice that c? is not the same as cA, even if
phase ? is a solid solution based on A.
8
What determines the phase diagram?
  • Equilibrium is given by the minimum of the Gibbs
    potential, G. If more than one phase are
    possible, the phase with the lowest G is the
    equilibrium state.
  • G H - TS At low temperature enthalpy dominates.
  • Entropy becomes increasingly important at
    higher T.
  • Ideal solution Two chemically similar components
  • G H - T (Sv SM) GM - TSM
  • Assume
  • GM changes linearly from A to B.
  • Configurational entropy SM -Nk c ln c (1-c)
    ln (1-c)
  • (same idea as with vacancies)
  • The slope of SM goes to /- 8 when c --gt 0 or 1

9
G(T,c) of an ideal solution
  • GM is a simple weighted average of the Gibbs
    potential of the components and ?Sm is the
    configurational entropy.
  • Notice that the entropy term becomes more
    important with increasing temperature, increasing
    the curvature of the G(c) curve.

10
  • Comparing G for the ideal solution and the
    similar G for the liquid phase allows the
    construction of a hypothetical phase diagram.
  • Notice that S is lower for low, L is lower for
    high temperature.
  • Notice the changing curvature.
  • In intermediate states, neither L nor S gives the
    smallest possible G. The state is a mixture of
    the two common tangent gives the concentrations,
    the lever rule gives the relative amounts.

11
Why the common tangent?
  • For an average concentration of c, we have x
    fraction with c1 and (1 - x) with c2.
  • c x c1 (1 - x) c2, thus
  • x (c2 - c) / (c2 - c1) 1 - x (c - c1) / (c2
    - c1)
  • The Gibbs potential for the mixture
  • G G1 x G2 (1 - x)
  • G1 (c2 - c) / (c2 - c1) G2 (c - c1) / (c2
    - c1)
  • This is a linear equation that describes a
    straight line between the end points. We get the
    lowest G when finding the lowest straight line
    still having end points on the G(c) curve - that
    is the common tangent.

G1
G2
c1 c c2
12
The Ag-Au system is close to an ideal solution.
13
Regular solutions
  • Beside mixing entropy, differences in nearest
    neighbor bond energy provide a variation of the
    enthalpy term HAA, HBB, HAB.
  • Suppose N atoms (A and B together), z nearest
    neighbors, c is concentration of B.
  • NAA 1/2 N (1-c) z(1-c) 1/2 (total A)
    (mean A neighbor)
  • NBB 1/2 N c z c
  • NAB N z c (1-c)
  • Hm NAAHAA NBBHBB NABHAB 1/2 Nz (1-c)HAA
    cHBB 2c(1-c)H0
  • where H0 HAB - 1/2(HAA HBB)
  • The last term in Hm has a maximum for H0 gt 0,
    competes with the minimum caused by
    configurational entropy. The slope of entropy is
    /- 8 at the borders, the slope of Hm is finite.
  • Can result in limited solubility.
  • G Hm - TSm

14
  • Gibbs free energy for a regular solution
  • H0 lt 0 makes Gm sharply peaked - ordering,
    compound formation
  • H0 gt 0 can result in two minima. For c1 lt c lt c2,
    the lowest energy state is a mixture - phase
    separation, limited mutual solubility.
  • If HAA HBB and c ltlt 1, the solubility limit
    from dG/dc 0 is
  • c1 exp(-zH0/kT)
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