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Interference in Waves

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Title: Interference in Waves


1
Interference in Waves
  • SPH4U Grade 12 Physics
  • Unit 2

2
Tribal Challenge!
  • A ray of light travels from glass into water.
    Find the angle of refraction in water if the
    angle of incidence in glass is 30º.
  • (nwater 1.33, and nglass 1.5)
  • 3 points first team correct
  • 1 point every correct answer after that

3
Tribal Challenge!
  • A ray of light travels from glass into
    water. Find the angle of refraction in water if
    the angle of incidence in glass is 30º.
  • (nwater 1.33, and nglass 1.5)
  • Solution

Therefore, the angle of refraction in water is
34.3º.
4
Review
  • When two waves cross paths and become
    superimposed, they interact in different ways.
    This interaction is called interference.
  • Waves that build each other up have constructive
    interference.
  • Waves that cancel each other out have destructive
    interference.

5
Review
Constructive Interference
Destructive Interference
6
Two Point Interference Pattern
  • When we have two identical point sources that are
    side by side, in phase, and have identical
    frequencies, we can analyse the interference
    pattern that is produced to learn more about the
    waves.
  • ripple tank simulation of two point source
    pattern http//www.falstad.com/ripple/

7
Two Point Interference Pattern
Antinodes
Nodes
Sources
8
Two Point Interference Pattern
Thin line trough
  • In the diagram, crests are represented by thick
    lines and troughs are represented by thin lines.
    We get constructive interference then whenever a
    thick line meets thick line, or when a thin line
    meets a thin line. This constructive
    interference causes antinodes, shown by the red
    dots.

Thick line crest
9
Two Point Interference Pattern
  • Destructive interference occurs whenever a thick
    line meets a thin line. These points form nodes,
    which are represented by a blue dot. The nodes
    and antinodes appear to stand still which makes
    this a standing wave pattern.

10
Two Point Interference Pattern
  • The antinodes and nodes seem to all be located on
    lines. These are called antinodal lines and
    nodal lines, respectively. There is a central
    line in the pattern, the line that bisects the
    line segment drawn between the two sources. This
    is called the central antinodal line.

Central antinodal line
11
Two Point Interference Pattern
  • The antinodes and nodes seem to all be located on
    lines. These are called antinodal lines and
    nodal lines, respectively. There is a central
    line in the pattern, the line that bisects the
    line segment drawn between the two sources. This
    is called the central antinodal line.

Central antinodal line
12
Two Point Interference Pattern
  • The number of nodal lines increases when you do
    any of the following
  • Increase frequency of the sources
  • Decrease the wavelength of the waves
  • Increase separation between the sources

13
Mathematical Analysis
1st nodal line, n1
  • If we have a two point source interference
    pattern like this one we can analyse it
    mathematically in order to determine the
    wavelength of the waves.

2nd nodal line, n1
n3
The nodal lines are measured from the central
antinodal line outward.
14
Mathematical Analysis
  • Lets put a point P1 somewhere on the first nodal
    line. We can measure the path length between
    each source and this point. These are the blue
    and red lines.

A
P1
15
Mathematical Analysis
  • The path difference, ?s is the difference between
    the length of the blue and red lines. On the
    first nodal line, the path difference equals ½ ?.

P1
?s P1S1 P1S2 ½ ?
This equation works for points that are on the
first nodal line only
16
Mathematical Analysis
  • In general, we can find the path difference for a
    point on any nodal line using the equation below

P1
?s P1S1 P1S2 (n-½) ?
This equation works for points that are on the
nth nodal line, only if the wavelengths are large
enough or if the point P is not too far away from
the sources.
17
Mathematical Analysis
P1
  • If the point P1 is very far away compared to the
    distance between the sources, we can use this
    equation

?n
d
? wavelength n nth nodal line d
distance between S1 and S2 ?n angle between the
central line and the nth nodal line
18
Mathematical Analysis
P1
xn
  • Note that due to trigonometry, you can also find
    ?n using basic trigonometry

L
?n
d
? wavelength n nth nodal line d
distance between S1 and S2 ?n angle between the
central line and the nth nodal line
19
Mathematical Analysis
P1
xn
  • This of course implies the following equation to
    be true

L
?n
d
? wavelength n nth nodal line d
distance between S1 and S2 ?n angle between the
central line and the nth nodal line
20
Example 1
  • Two identical point sources 5.0cm apart,
    operating in phase at a frequency of 8.0Hz,
    generate an interference pattern in a ripple
    tank. A certain point on the first nodal line is
    located 10.0cm from one source and 11.0cm from
    the other. What is the wavelength of the waves?

21
Example 1
  • Two identical point sources 5.0cm apart,
    operating in phase at a frequency of 8.0Hz,
    generate an interference pattern in a ripple
    tank. A certain point on the first nodal line is
    located 10.0cm from one source and 11.0cm from
    the other. What is the wavelength of the waves?

22
Youngs Double Slit Experiment
  • Youngs Double Slit experiment, conducted at the
    end of the 1700s, is famous because it showed
    that light created an interference pattern that
    resembled the interference of water waves in a
    ripple tank.

23
Youngs Double Slit Experiment
  • Videos
  • Derek Owens http//www.youtube.com/watch?vAMBcg
    VlamoU
  • Dr. Quantum
  • http//www.youtube.com/watch?vQ1YqgPAtzho

24
Youngs Double Slit Experiment
  • The experiment showed that light coming from the
    two slits interfered with itself to create
    constructive and destructive interference.

25
Youngs Double Slit Experiment
  • Where we have constructive interference we get
    brighter bands of light, and where there is
    destructive interference we get bands of
    darkness.

26
Youngs Double Slit Experiment
  • People had tried to do this experiment prior to
    Young, but their attempts had failed because the
    sources they had used were too far apart, and
    were out of phase with each other.

27
Youngs Double Slit Experiment
  • Young fixed these problems by using one source,
    the sun, and then splitting that light using a
    screen to make two sources. He also made the
    holes for S1 and S2 very close together. This
    allowed an interference pattern to be visible
    even though the wavelength of light is very
    small. (about 400-800 nano meters).

28
Youngs Double Slit Experiment
  • The fact that light passing through the two slits
    acted like point sources that created circular
    waves, was further evidence of diffraction
    (bending) of light.
  • The experiment as a whole was strong evidence of
    the wave nature of light. At this point the wave
    theory could explain all properties of light
    except for propagation through a vacuum.

29
Youngs Double Slit Experiment
  • The experiment also provided a way to measure the
    wavelength of light, using the same equations we
    just derived for a two point source interference
    pattern.
  • In youngs experiment, a nth order dark fringe
    would be at a location

30
Youngs Double Slit Experiment
  • We can also use the following equation to
    calculate the wavelength of light in Youngs
    experiment
  • ?x is the distance between adjacent dark lines
  • L is the distance from the two sources of light
    to the screen
  • d is the distance between the two sources of
    light
  • ? is the wavelength of light

31
Example 2
  • You are measuring the wavelength of light from a
    certain single-colour source. You direct the
    light through two slits with a separation of
    0.15mm, and an interference pattern is created on
    a screen 3.0m away. You find the distance
    between the first and the eighth consecutive dark
    lines to be 8.0cm. At what wavelength is your
    source radiating?

32
Example 2
  • You are measuring the wavelength of light from a
    certain single-colour source. You direct the
    light through two slits with a separation of
    0.15mm, and an interference pattern is created on
    a screen 3.0m away. You find the distance
    between the first and the eighth consecutive dark
    lines to be 8.0cm. At what wavelength is your
    source radiating?

33
Homework
  • Prepare for tomorrows lab
  • Read Section 9.3 9.5
  • Make additional notes to supplement the lesson
    notes. Complete the following questions
  • What is Poissons Bright spot? How did its
    discovery help to solidify the scientific view
    that light behaved like a wave?
  • Pg. 468 2,3
  • Pg. 484 2, 4, 5
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