Review of exponential charging and discharging in RC Circuits - PowerPoint PPT Presentation

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Review of exponential charging and discharging in RC Circuits

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CMOS LOGIC Inside the CMOS inverter, no ID current flows through transistors when input is logic 1 or logic 0, because the NMOS transistor is cutoff for logic 0 (0 V ... – PowerPoint PPT presentation

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Title: Review of exponential charging and discharging in RC Circuits


1
CMOS LOGIC
  • Inside the CMOS inverter, no ID current flows
    through transistors when input is logic 1 or
    logic 0, because
  • the NMOS transistor is cutoff for logic 0 (0 V)
    input
  • the PMOS transistor is cutoff for logic 1 (VDD)
    input
  • current through the turned on transistor has
    nowhere to go if next stage consists of
    transistor gates

VDD
S
VOUT2
D
D
VIN
S
2
VIN 0 V
VIN VDD
  • NMOS transistor cutoff (since VGS(N) VIN 0
    V) acts as open circuit
  • PMOS transistor on (VGS(P) VIN VDD
    -VDD) but ID(P) 0 A gt VDS(P) 0 V
  • PMOS transistor cutoff (VGS(P) VIN VDD 0
    V) acts as open circuit
  • NMOS transistor on (VGS(N) VIN VDD)
    but ID(N) 0 A gt VDS(N) 0 V

ID(N) ( -ID(P))
X
VOUT
VDD
3
EASY MODEL FOR LOGIC ANALYSIS
There is a simpler model for the behavior of
transistors in a CMOS logic circuit, which
applies when the input to the logic circuit is
fully logic 0 or fully logic 1.
VGS VDD (for NMOS) VGS -VDD (for PMOS)
VGS 0 V
Each transistor will be in one of these two
situations!
D
G
S
We can use the model to quickly determine the
logical operation of a CMOS circuit (but we
cannot use it to find circuit currents or
voltages that will occur for mid-range input
voltages).
4
REVISIT CMOS INVERTER WITH SIMPLE LOGIC MODEL
Fill in the switch positions below
VDD
VDD
VOUT
VIN 0 V
VOUT
VIN VDD
5
VDD
CMOS NAND
S
S
A
PMOS1
PMOS2
F
B
NMOS1
S
NMOS2
S
6
Verify the logical operation of the CMOS NAND
circuit
VDD
VDD
S
S
S
S
A 0V
A 0V
F
F
B 0V
B VDD
S
S
S
S
7
Verify the logical operation of the CMOS NAND
circuit
VDD
VDD
S
S
S
S
A VDD
A VDD
F
F
B 0V
B VDD
S
S
S
S
8
CMOS NOR
VDD
S
A
PMOS1
S
B
PMOS2
F
NMOS1
NMOS2
S
S
9
Verify the logical operation of the CMOS NOR
circuit
VDD
VDD
S
A 0V
S
A 0V
S
B 0V
S
B VDD
F
F
S
S
S
S
10
Verify the logical operation of the CMOS NOR
circuit
VDD
VDD
S
A VDD
S
A VDD
S
B 0V
S
B VDD
F
F
S
S
S
S
11
PULL-UP AND PULL-DOWN DEVICES
In our logic circuits, the NMOS transistor
sources are connected to ground, and the PMOS
sources are connected to VDD.
Notice that when NMOS transistors are on (when
VGSN VDD) VDSN is shorted by switch, helping
connect output to ground. The NMOS transistor
functions as a pull-down device when active, it
brings the output to 0 V.
When PMOS transistors are on (when VGSP -VDD)
VDSP is shorted by switch, helping connect
output to VDD. The PMOS transistor functions as
a pull-up device when active, it brings the
output to VDD.
12
LIMITATIONS OF SWITCH MODEL
In reality, the pull-up devices must have some
VDS voltage and current flow to bring the output
high since natural capacitance must be charged.
Preview of next class
VDD
S
S
A
Similarly, the pull-down devices must have some
VDS voltage and current flow to bring the output
to ground since natural capacitance must be
discharged.
PMOS1
PMOS2
F
B
NMOS1
S
NMOS2
S
This is GATE DELAY.
13
LIMITATIONS OF SWITCH MODEL
Suppose one needed to fully analyze the circuit
for intermediate input voltages.
VDD
Requires many equations, many unknowns. But,
we can at least guess the modes.
S
S
A VDD
PMOS1
PMOS2
F
NMOS1
B VTH(N) e
S
NMOS2
S
14
Assume VDD around 5 V, VTH(N) around 1 V, VTH(P)
around -1 V, e around 0.5 V.
VDD
S
S
A VDD
PMOS1
PMOS2
NMOS1
B VTH(N) e
S
NMOS2
S
  • PMOS1 cutoff
  • NMOS1 barely on (VDS(N2) 0) gt saturation
  • NMOS2 fully on, but NMOS1 limits ID to small
    value gt triode
  • PMOS2 on, but NMOS1 and PMOS1 make ID small gt
    triode
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