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4.1 Valence Electrons

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Chapter 4 Compounds and Their Bonds 4.1 Valence Electrons 4.2 Octet Rule and Ions Valence Electrons The valence electrons are the electrons in the outer shell. – PowerPoint PPT presentation

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Title: 4.1 Valence Electrons


1
Chapter 4 Compounds and Their Bonds
  • 4.1 Valence Electrons
  • 4.2 Octet Rule and Ions

2
Valence Electrons
  • The valence electrons are the electrons in the
    outer shell.
  • The electrons in the outer shell have the most
    contact with other atoms and strongly influence
    the chemical properties of atoms.

3
Number of Valence Electrons
  • For Group A elements, the number of valence
    electrons is the number of electrons in the s and
    p subshells of the outer shell.
  • In the electron configuration for phosphorus,
    there are 5 valence electrons in the s and p
    subshells with the highest number. 5
    valence electrons P Group 5A
    1s22s22p63s23p3

4
Valence Electrons for Groups

5
Learning Check
  • State the number of valence electrons for each.
  • A. Magnesium
  • 1) 2 2) 6 3) 8
  • B. Oxygen
  • 1) 2 2) 4 3) 6
  • C. Potassium
  • 1) 1 2) 2 3) 7

6
Solution
  • State the number of valence electrons for each.
  • A. Magnesium
  • 1) 2 Group 2A 1s22s22p63s2
  • B. Oxygen
  • 3) 6 Group 6A 1s22s2 2p4
  • C. Potassium
  • 1) 1 Group 1A 1s22s22p63s23p64s1

7
Electron Dot Structure
  • An electron-dot structure is a convenient way to
    represent the valence electrons.
  • For example, the two valence electrons for
    magnesium are placed as single dots on any two
    sides of the Mg symbol.

8
Electron-Dot Structures
  • Dot structures are used for Group A elements.
  • The valence electrons are placed on the sides of
    the symbol of an element.

9
Learning Check
  • ?
  • A. X is the electron dot formula for
  • 1) Na 2) K 3) Al
  • ? ?
  • B. ? X ? is the electron dot formula of
  • ?
  • 1) B 2) N 3) P

10
Solution
  • ?
  • A. X is the electron dot formula for
  • 1) Na 2) K
  • ? ?
  • B. ? X ? is the electron dot formula of
  • ?
  • 2) N 3) P

11
Octet Rule
  • The stability of the noble gases is associated
    with 8 valence electrons (He has 2). Ne 2,
    8 Ar 2, 8, 8 Kr 2, 8, 18, 8
  • Atoms can become more stable by acquiring an
    octet (8 electrons) in the outer shell.
  • The process of acquiring an octet involves the
    loss, gain, or sharing of valence electrons.

12
Ionization Energy
  • Ionization energy is the energy it takes to
    remove a valence electron.
  • Metals have lower ionization energies and
    nonmetals have higher ionization energies.

13
Metals Form Positive Ions
  • Metals acquire octets by losing valence
    electrons.
  • The loss of electrons converts an atom to an ion
    that has the electron configuration of the
    nearest noble gas.
  • Metals form positive ions because they have fewer
    electrons than protons. Group 1A metals ??
    ion 1 Group 2A metals ?? ion 2 Group
    3A metals ?? ion 3

14
Learning Check
  • Give the ionic charge for each ion.
  • A. 12 p and 10 e-
  • 1) 0 2) 2 3) 2-
  • B. 50p and 46 e-
  • 1) 2 2) 4 3) 4-
  • C. 15 p and 18e-
  • 2) 3 2) 3- 3) 5-

15
Solution
  • Give the ionic charge for each ion.
  • A. 12 p and 10 e-
  • 2) 2
  • B. 50p and 46 e-
  • 2) 4
  • C. 15 p and 18e-
  • 2) 3-

16
Formation of a Sodium Ion, Na
  • Sodium forms an octet by losing its one valence
    electron.
  • Na ? e? ?? Na
  • 1s22s22p63s1 1s22s22p6 ( Ne)
  • A positive ion forms with a 1 charge.
  • Sodium atom Sodium ion
  • 11 p 11 p
  • 11 e- 10 e-
  • 0 1

17
Formation of Mg2
  • Magnesium forms an octet by losing its two
    valence electrons.
  • Magnesium atom Magnesium ion
  • ?
  • Mg ? 2e? ?? Mg2
  • 1s22s22p63s2 1s22s22p6 ( Ne)
  • A positive ion forms with a 2 charge.
  • 12 p 12 p
  • 12 e- 10
    e-
  • 0
    2

18
Formation of Negative Ions
  • When nonmetals gain electrons to achieve an octet
    arrangement, they form negative ions.
  • The ionic charge of a nonmetal is 3-, 2-, or 1-.

19
Formation of a Fluoride Ion, F-
  • Fluorine forms an octet by adding an electron to
    its seven valence electrons.
  • ? ? ? ? 1-
  • F ? e? F
  • ? ? ? ?
  • 1s22s22p5 1s22s22p6 ( Ne)
  • A negative ion forms with a -1 charge.
  • Fluorine atom Fluoride ion
  • 9 p 9 p
  • 9 e- 10 e-
  • 0 1

20
Group Number and Ions
  • The Group number can be used to determine the
    charge of an ion.
  • The charge of a positive ion is equal to its
    Group number.
  • Group 3A 3
  • The charge of a negative ion is obtained by
    subtracting its Group number from 8.
  • Group 6A - (8-6) 2-

21
Examples of Ionic Charges

22
Some Important Ions in the Body
23
Learning Check
  • A. How many valence electrons does aluminum have?
  • 1) 2e- 2) 3e- 3) 5e-
  • B. How does aluminum acquire an octet?
  • 1) loses 3e- 2) gains 3e-
    3) gains 5e-
  • C. What is the ionic charge of an aluminum ion?
  • 1) 3- 2) 5- 3) 3
  • D. The symbol for the aluminum ion is
  • 1) Al3 2) Al3- 3) Al

24
Solution
  • A. How many valence electrons does aluminum
  • have?
  • 2) 3e-
  • B. How does aluminum acquire an octet?
  • 1) loses 3e-
  • C. What is the ionic charge of an aluminum ion?
  • 3) 3
  • D. The symbol for the aluminum ion is
  • 1) Al3

25
Chapter 4 Compounds and Their Bonds
  • 4.3 Ionic Compounds
  • 4.4 Naming and Writing Ionic Formulas

26
Ionic Compounds
  • Ionic compounds consist of positive and negative
    ions.
  • An ionic bond is an attraction between the
    positive and negative charges.
  • In an ionic formula, the total charge of the
    positive ions is equal to the total charge of the
    negative ions. total positive charge
    total negative charge

27
Ionic Formulas
  • The formulas of ionic compounds are determined
    from the charges on the ions.
  • atoms ions
  • ? ?
    ? ?
  • Na ? ? F ?? Na F ?? NaF
  • ? ?
    ? ?
  • sodium fluorine
    sodium fluoride
  • The overall charge of NaF is zero (0).
  • (1 ) (1-) 0

28
Charge Balance In NaCl
  • The formula does not show the charges of the ions
    in the compound.
  • The symbol of the metal is written first,
    followed by the symbol of the nonmetal.

29
Charge Balance In MgCl2
30
Writing a Formula from Charges
  • Write the formula of the ionic compound that
    forms from Ba2 and Cl?.
  • Write the symbols of the positive ion and the
    negative ion. Ba2 Cl?
  • Balance the charges until the positive charge is
    equal to the negative charge.
  • Ba2 Cl? two Cl-
    needed Cl?
  • Write the formula using subscripts for the number
    of ions for charge balance. BaCl2

31
Learning Check
  • Write the correct formula for the ionic compound
    of
  • A. Na and S2-
  • 1) NaS 2) Na2S 3) NaS2
  • B. Al3 and Cl-
  • 1) AlCl3 2) AlCl 3) Al3Cl
  • C. Mg2 and N3-
  • 1) MgN 2) Mg2N3 3) Mg3N2

32
Solution
  • A. Na and S2-
  • 2) Na2S
  • B. Al3 and Cl-
  • 1) AlCl3
  • C. Mg2 and N3-
  • 3) Mg3N2

33
Names of Ions
  • Positive ions are named like the element.
  • Negative ions are named by changing the end of
    the element name to ide.

34
Learning Check
  • Complete the names of the following ions
  • N3? O2?
    F?
  • _________ __________ _________
  • P3? S2?
    Cl?
  • _________ __________ _________
  • Br ?
  • _________

35
Solution
  • N3? O2? F?
  • nitride oxide fluoride
  • P3? S2? Cl?
  • phosphide sulfide chloride
  • Br ?
  • bromide

36
Naming Ionic Compounds with Two Elements
  • The name of a binary ionic compound (two
    elements) gives the name of the metal ion first
    and the name of the negative ion second.
  • Examples
  • NaCl sodium chloride
  • K2S potassium sulfide
  • CaI2 calcium iodide
  • Al2O3 aluminum oxide

37
Learning Check
  • Write the names of the following compounds
  • 1) Na3N ___________
  • 2) KBr ___________
  • 3) Al2S3 ___________
  • 4) MgO ___________

38
Solution
  • Complete the names of the following compounds
  • 1) Na3N sodium nitride
  • 2) KBr potassium bromide
  • 3) Al2S3 aluminum sulfide
  • 4) MgO magnesium oxide

39
Ionic Charges of Transition Metals
  • Most transition elements have two or more
    positive ions.

40
Summary of Common Ions
  • Of the transition metals, silver and zinc are
    important elements that form only one ion.

41
Learning Check
  • A. The formula for the ionic compound of
  • Na and O2- is
  • 1) NaO 2) Na2O 3) NaO2
  • B. The formula of a compound of aluminum and
    chlorine is
  • 1) Al3Cl 2) AlCl2 3) AlCl3
  • C. The formula of Fe3 and O2- is
  • 1) Fe3O2 2) FeO3 3) Fe2O3

42
Solution
  • A. The formula for the ionic compound of
  • Na and O2- is
  • 2) Na2O
  • B. The formula of a compound of aluminum and
    chlorine is
  • 3) AlCl3
  • C. The formula of Fe3 and O2- is
  • 3) Fe2O3

43
Naming Compounds with Transition Metals
  • Transition metals with two different ions use a
    Roman numeral following the name of the metal to
    indicate ionic charge.

44
Learning Check
  • Select the correct name for each.
  • A. Fe2S3
  • 1) iron sulfide
  • 2) iron(II) sulfide
  • 3) iron (III) sulfide
  • B. CuSO4
  • 1) copper sulfate
  • 2) copper(I) sulfate
  • 3) copper (II) sulfate

45
Solution
  • Select the correct name for each.
  • A. Fe2S3
  • 3) iron (III) sulfide
  • B. CuSO4
  • 3) copper (II) sulfate

46
Learning Check
  • The correct formula is
  • A. Copper (I) nitride
  • 1) CuN 2) CuN3 3) Cu3N
  • B. Lead (IV) oxide
  • 1) PbO2 2) PbO 3) Pb2O4

47
Solution
  • The correct formula is
  • A. Copper (I) nitride
  • 3) Cu3N
  • B. Lead (IV) oxide
  • 1) PbO2

48
Chapter 4 Compounds and Their Bonds
  • 4.5 Covalent Bonds
  • 4.6 Naming and Writing Formulas of Covalent
    Compounds
  • 4.7 Bond Polarity

49
Covalent Bonds
  • Covalent bonds form between two nonmetals from
    Groups 4A, 5A, 6A, and 7A.
  • In a covalent bond, electrons are shared to
    complete octets.

50
Learning Check
  • Indicate whether a bond between the following is
    1) Ionic 2) Covalent
  • ____A. sodium and oxygen
  • ____B. nitrogen and oxygen
  • ____C. phosphorus and chlorine
  • ____D. calcium and sulfur
  • ____E. chlorine and bromine

51
Solution
  • Indicate whether a bond between the following is
    1) Ionic 2) Covalent
  • 1 A. sodium and oxygen
  • 2 B. nitrogen and oxygen
  • 2 C. phosphorus and chlorine
  • 1 D. calcium and sulfur
  • 2 E. chlorine and bromine

52
H2, A Covalent Molecule
  • In hydrogen, two hydrogen atoms share their
    electrons to form a covalent bond.
  • Each hydrogen atom acquires a stable outer shell
    of two (2) electrons like helium (He).
  • H? ?H H H H?H H2
  • hydrogen molecule

53
Diatomic Elements
  • As elements, the following share electrons to
    form diatomic, covalent molecules.

54
Learning Check
  • What is the name of each of the following
    diatomic molecules?
  • H2 hydrogen
  • N2 nitrogen
  • Cl2 _______________
  • O2 _______________
  • I2 _______________

55
Solution
  • What are the names of each of the following
    diatomic molecules?
  • H2 hydrogen
  • N2 nitrogen
  • Cl2 chlorine
  • O2 oxygen
  • I2 iodine

56
Covalent Bonds in NH3
  • The compound NH3 consists of a N atom and three H
    atoms.
  • ? ?
  • ? N ? and 3 H ?
  • ?
  • By sharing electrons to form NH3, the electron
    dot structure is written as
  • H Bonding pairs
  • ? ?
  • H N H
  • ? ? Lone
    pair of electrons

57
Number of Covalent Bonds
  • Often, the number of covalent bonds formed by a
    nonmetal is equal to the number of electrons
    needed to complete the octet.

58
Dot Structures and Models of Some Covalent
Compounds

59
Multiple Bonds
  • Sharing one pair of electrons is a single
    bond. X X or XX
  • In multiple bonds, two pairs of electrons are
    shared to form a double bond or three pairs of
    electrons are shared in a triple bond. X X
    or X X X X or X X

60
Multiple Bonds in N2
  • In nitrogen, octets are achieved by sharing three
    pairs of electrons.
  • When three pairs of electrons are shared, the
    multiple bond is called a triple bond.
  • octets
  • ? ? ? ?
    ? ? ? ?
  • ? N ? ? N ? ?? NN
  • ? ?
  • triple bond

61
Naming Covalent Compounds
  • In the name of a covalent compound, the first
    nonmetal is named followed by the name of the
    second nonmetal ending in ide.
  • Prefixes indicate the number of atoms of each
    element.

62
Learning Check
  • Complete the name of each covalent compound
  • CO carbon ______oxide
  • CO2 carbon _______________
  • PCl3 phosphorus ___________
  • CCl4 carbon _______________
  • N2O ______________________

63
Solution
  • Complete the name of each covalent compound
  • CO carbon monoxide
  • CO2 carbon dioxide
  • PCl3 phosphorus trichloride
  • CCl4 carbon tetrachloride
  • N2O dinitrogen monoxide

64
Formulas and Names of Some Covalent Compounds

65
Learning Check
  • Select the correct name for each compound.
  • A. SiCl4 1) silicon chloride
  • 2) tetrasilicon chloride
  • 3) silicon tetrachloride
  • B. P2O5 1) phosphorus oxide
  • 2) phosphorus pentoxide
  • 3) diphosphorus pentoxide
  • C. Cl2O7 1) dichlorine heptoxide
  • 2) dichlorine oxide
  • 3) chlorine heptoxide

66
Solution
  • Select the correct name for each compound.
  • A. SiCl4 3) silicon tetrachloride
  • B. P2O5 3) diphosphorus pentoxide
  • C. Cl2O7 1) dichlorine heptoxide

67
Electronegativity
  • Electronegativity is the attraction of an atom
    for shared electrons.
  • The nonmetals have high electronegativity values
    with fluorine as the highest.
  • The metals have low electronegativity values.

68
Some Electronegativity Values for Group A Elements

69
Nonpolar Covalent Bonds
  • The atoms in a nonpolar covalent bond have
    electronegativity differences of 0.3 or less.
  • Examples Atoms Electronegativity Type
    of Difference Bond N-N 3.0 - 3.0
    0.0 Nonpolar covalentCl-Br 3.0 - 2.8 0.2
    Nonpolar covalentH-Si 2.1 - 1.8 0.3
    Nonpolar covalent

70
Polar Covalent Bonds
  • The atoms in a polar covalent bond have
    electronegativity differences of 0.4 to 1.6.
  • Examples Atoms Electronegativity Type
    of Difference BondO-Cl 3.5 - 3.0 0.5
    Polar covalentCl-C 3.0 - 2.5 0.5 Polar
    covalentO-S 3.5 - 2.5 1.0 Polar covalent

71
Comparing Nonpolar and Polar Covalent Bonds

72
Ionic Bonds
  • The atoms in an ionic bond have electronegativity
    differences of 1.7 or more.
  • Examples Atoms Electronegativity Type
    of Difference BondCl-K 3.0 0.8
    2.2 IonicN-Na 3.0 0.9 2.1 IonicS-Cs 2.5
    0.7 1.8 Ionic

73
Range of Bond Types

74
Predicting Bond Type
75
Learning Check
  • Identify the type of bond between the following
    as
  • 1) nonpolar covalent
  • 2) polar covalent
  • 3) ionic
  • A. K-N
  • B. N-O
  • C. Cl-Cl

76
Solution
  • A. K-N
  • 3) ionic
  • B. N-O
  • 2) polar covalent
  • C. Cl-Cl
  • 1) nonpolar covalent

77
Chapter 4 Compounds and Their Bonds
  • 4.8 Polyatomic Ions

78
Polyatomic Ions
  • A polyatomic ion is a group of two or more atoms
    that has an overall ionic charge.
  • Some examples of polyatomic ions are
  • NH4 ammonium OH - hydroxide
  • NO3- nitrate NO2 - nitrite
  • CO32 - carbonate PO43 - phosphate
  • HCO3 - hydrogen carbonate (bicarbonate)

79
Common Polyatomic Ions

80
Formulas with Polyatomic Ions
  • The formula of an ionic compound containing a
    polyatomic ion is written to make the overall
    charge equal zero (0).
  • Na and NO3- NaNO3
  • When two or more polyatomic ions are needed, the
    polyatomic ion is enclosed in parentheses.
  • polyatomic ion
  • Mg2 and NO3 - Mg(NO3)2
  • subscript 2 for charge balance

81
Some Compounds with Polyatomic Ions

82
Learning Check
  • Select the correct formula for each
  • A. Aluminum nitrate
  • 1) AlNO3 2) Al(NO)3 3)
    Al(NO3)3
  • B. Copper(II) nitrate
  • 1) CuNO3 2) Cu(NO3)2 3) Cu2(NO3)
  • C. Iron (III) hydroxide
  • 1) FeOH 2) Fe3OH 3) Fe(OH)3
  • D. Tin(IV) hydroxide
  • 1) Sn(OH)4 2) Sn(OH)2 3) Sn4(OH)

83
Solution
  • Select the correct formula for each
  • A. Aluminum nitrate
  • 3) Al(NO3)3
  • B. Copper(II) nitrate
  • 2) Cu(NO3)2
  • C. Iron (III) hydroxide
  • 3) Fe(OH)3
  • D. Tin(IV) hydroxide
  • 1) Sn(OH)4

84
Naming Compounds with Polyatomic Ions
  • For compounds with polyatomic ions, the positive
    ion is named first followed by the name of the
    polyatomic ion.NaNO3 sodium nitrateK2SO4 potas
    sium sulfateAl(HCO3)3 aluminum bicarbonate or
    aluminum hydrogen carbonate(NH4)3PO4 ammonium
    phosphate

85
Learning Check
  • Match each formula with the correct name
  • A. Na2CO3 1) magnesium sulfite
  • MgSO3 2) magnesium sulfate
  • MgSO4 3) sodium carbonate
  • B. Ca(HCO3)2 1) calcium carbonate
  • CaCO3 2) calcium phosphate
  • Ca3(PO4)2 3) calcium bicarbonate

86
Solution
  • A. Na2CO3 3) sodium carbonate
  • MgSO3 1) magnesium sulfite
  • MgSO4 2) magnesium sulfate
  • B. Ca(HCO3)2 3) calcium bicarbonate
  • CaCO3 1) calcium carbonate
  • Ca3(PO4)2 2) calcium phosphate

87
Summary of Naming Compounds
88
Naming Rules
89
Naming Rules (continued)
90
Learning Check
  • Name each of the following compounds
  • A. Mg(NO3)2
  • B. CuCl2
  • C. N2O4
  • D. Fe2(SO4)3
  • E. Ba3(PO4)2

91
Solution
  • Name each of the following compounds
  • A. Mg(NO3)2 magnesium nitrate
  • B. CuCl2 copper(II) chloride
  • C. N2O4 dinitrogen tetroxide
  • D. Fe2(SO4)3 iron(III) sulfate
  • E. Ba3(PO4)2 barium phosphate

92
Learning Check
  • Write the correct formula for each
  • A. potassium sulfide
  • B. calcium carbonate
  • C. sodium phosphite
  • D. iron(III) oxide
  • E. iron (II) nitrate

93
Solution
  • Write the correct formula for each
  • A. potassium sulfide K2S
  • B. calcium carbonate CaCO3
  • C. sodium phosphite Na3PO3
  • D. iron(III) oxide Fe2O3
  • E. iron (II) nitrate Fe(NO3)2

94
Chapter 4 Compounds and Their Bonds
  • 4.9 Shapes of Molecules
  • 4.10 Polar and Nonpolar Molecules

95
VSEPR
  • The shape of a molecule is predicted from the
    geometry of the electrons pairs around the
    central atom.
  • In the valence-shell electron-pair repulsion
    theory (VSEPR), the electron pairs are arranged
    as far apart as possible to give the least amount
    of repulsion of the negatively charged electrons.

96
Two Electron Pairs
  • In a molecule of BeCl2, there are two bonding
    pairs around the central atom Be. (Be is an
    exception to the octet rule.)
  • The arrangement of two electron pairs to
    minimize their repulsion is 180 or opposite each
    other.
  • The shape of the molecule is linear.

97
Two Electron Pairs with Double Bonds
  • The electron-dot structure for CO2 consists of
    two double bonds to the central atom C.
  • Because the electrons in a double bond are held
    together, a double bond is counted as a single
    unit.
  • Repulsion is minimized when the double bonds are
    placed opposite each other at 180 to give a
    linear shape.

98
Three Electron Pairs
  • In BF3, there are 3 electron pairs around the
    central atom B. (B is an exception to the octet
    rule.)
  • Repulsion is minimized by placing three electron
    pairs in a plane at angles of 120, which is a
    trigonal planar arrangement.
  • The shape with three bonded atoms is trigonal
    planar.

99
Two Bonding Pairs and A Nonbonding Pair
  • In SO2, there are 3 electron units around the
    central atom S.
  • Two electron units are bonded to atoms and one
    electron pair is a nonbonding pair.
  • Repulsion is minimized by placing three electron
    pairs in a plane at angles of 120, which is
    trigonal planar.
  • The shape with two bonded atoms is bent.

100
Learning Check
  • The shape of a molecule of N2O (N N O) is
  • 1) linear
  • 2) trigonal planar
  • 3) bent (120)

101
Solution
  • The shape of a molecule of N2O (N N O) is
  • 1) linear
  • The electron-dot structure uses 5 e for each N
    and 6 e for O (16 e total) has octets using two
    double bond to the central N and one nonbonding
    pair. The shape with two bonded atoms is linear.
  • N N O

102
Four Electron Pairs
  • In CH4, there are 4 electron pairs around the
    central atom C.
  • Repulsion is minimized by placing four electron
    pairs at angles of 109, which is a tetrahedral
    arrangement.
  • The shape with four bonded atoms is called
    tetrahedral.

103
Three Bonding Atoms and One Nonbonding Pair
  • In NH3, there are 4 electron pairs around the N.
  • Three pairs are bonded to atoms and one is a
    nonbonding pair.
  • Repulsion is minimized by placing four electron
    pairs at angles of 109, which is a tetrahedral
    arrangement.
  • The shape with three bonded atoms is pyramidal.

104
Two Bonding Atoms and Two Lone Pairs
  • In H2O, there are 4 electron pairs around O.
  • Two pairs are bonded to atoms and two are
    nonbonding pairs.
  • Repulsion is minimized by placing four electron
    pairs at angles of 109 called a tetrahedral
    arrangement.
  • The shape with two bonded atoms is called bent.

105
Some Steps Using VSEPR to Predict Shape
  • Draw the electron dot structure.
  • Count the electron pairs around the central atom.
  • Arrange the electron pairs to minimize repulsion.
  • Determine the shape using the number of bonded
    atoms in the electron arrangement.

106
Summary of Electron Arrangements and Shapes

107
Learning Check
  • Use VSEPR theory to determine the shape of the
    following molecules or ions.
  • 1) tetrahedral 2) pyramidal 3) bent
  • A. PF3
  • B. H2S
  • C. CCl4
  • D. PO43-

108
Solution
  • Use VSEPR theory to determine the shape of the
    following molecules or ions.
  • 1) tetrahedral 2) pyramidal 3) bent
  • A. PF3 2) pyramidal
  • B. H2S 3) bent
  • C. CCl4 1) tetrahedral
  • D. PO43- 1) tetrahedral

109
Polar Molecules
  • A polar molecule contains polar bonds.
  • The separation of positive and negative charge is
    called a dipole.
  • In a polar molecule, dipoles do not cancel.
  • ? ?-
  • HCl ClNCl
  • dipole Cl
  • dipoles do not cancel

110
Nonpolar Molecules
  • A nonpolar molecule contains nonpolar bonds
  • ClCl HH
  • or a symmetrical arrangement of polar bonds.
  • OCO Cl
  • ClCCl
  • Cl
  • dipoles cancel

111
Learning Check
  • Identify each of the following molecules as
  • 1) polar or 2) nonpolar. Explain.
  • A. PBr3
  • B. HBr
  • C. Br2
  • D. SiBr4

112
Solution
  • Identify each of the following molecules as
  • 1) polar or 2) nonpolar. Explain.
  • A. PBr3 1) polar pyramidal
  • B. HBr 1) polar polar bond
  • C. Br2 2) nonpolar, nonpolar bond
  • D. SiBr4 2) nonpolar dipoles cancel
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