Title: 4.1 Valence Electrons
1Chapter 4 Compounds and Their Bonds
- 4.1 Valence Electrons
- 4.2 Octet Rule and Ions
2Valence Electrons
- The valence electrons are the electrons in the
outer shell. - The electrons in the outer shell have the most
contact with other atoms and strongly influence
the chemical properties of atoms.
3Number of Valence Electrons
- For Group A elements, the number of valence
electrons is the number of electrons in the s and
p subshells of the outer shell. - In the electron configuration for phosphorus,
there are 5 valence electrons in the s and p
subshells with the highest number. 5
valence electrons P Group 5A
1s22s22p63s23p3
4Valence Electrons for Groups
5Learning Check
- State the number of valence electrons for each.
- A. Magnesium
- 1) 2 2) 6 3) 8
- B. Oxygen
- 1) 2 2) 4 3) 6
- C. Potassium
- 1) 1 2) 2 3) 7
6Solution
- State the number of valence electrons for each.
- A. Magnesium
- 1) 2 Group 2A 1s22s22p63s2
- B. Oxygen
- 3) 6 Group 6A 1s22s2 2p4
- C. Potassium
- 1) 1 Group 1A 1s22s22p63s23p64s1
7Electron Dot Structure
- An electron-dot structure is a convenient way to
represent the valence electrons. - For example, the two valence electrons for
magnesium are placed as single dots on any two
sides of the Mg symbol.
8Electron-Dot Structures
- Dot structures are used for Group A elements.
- The valence electrons are placed on the sides of
the symbol of an element.
9Learning Check
- ?
- A. X is the electron dot formula for
- 1) Na 2) K 3) Al
- ? ?
- B. ? X ? is the electron dot formula of
- ?
-
- 1) B 2) N 3) P
-
10Solution
- ?
- A. X is the electron dot formula for
- 1) Na 2) K
-
- ? ?
- B. ? X ? is the electron dot formula of
- ?
-
- 2) N 3) P
-
11Octet Rule
- The stability of the noble gases is associated
with 8 valence electrons (He has 2). Ne 2,
8 Ar 2, 8, 8 Kr 2, 8, 18, 8 - Atoms can become more stable by acquiring an
octet (8 electrons) in the outer shell. - The process of acquiring an octet involves the
loss, gain, or sharing of valence electrons.
12Ionization Energy
- Ionization energy is the energy it takes to
remove a valence electron. - Metals have lower ionization energies and
nonmetals have higher ionization energies.
13Metals Form Positive Ions
- Metals acquire octets by losing valence
electrons. - The loss of electrons converts an atom to an ion
that has the electron configuration of the
nearest noble gas. - Metals form positive ions because they have fewer
electrons than protons. Group 1A metals ??
ion 1 Group 2A metals ?? ion 2 Group
3A metals ?? ion 3
14Learning Check
- Give the ionic charge for each ion.
- A. 12 p and 10 e-
- 1) 0 2) 2 3) 2-
- B. 50p and 46 e-
- 1) 2 2) 4 3) 4-
- C. 15 p and 18e-
- 2) 3 2) 3- 3) 5-
15Solution
- Give the ionic charge for each ion.
- A. 12 p and 10 e-
- 2) 2
- B. 50p and 46 e-
- 2) 4
- C. 15 p and 18e-
- 2) 3-
16Formation of a Sodium Ion, Na
- Sodium forms an octet by losing its one valence
electron. - Na ? e? ?? Na
- 1s22s22p63s1 1s22s22p6 ( Ne)
- A positive ion forms with a 1 charge.
- Sodium atom Sodium ion
- 11 p 11 p
- 11 e- 10 e-
- 0 1
17Formation of Mg2
- Magnesium forms an octet by losing its two
valence electrons. - Magnesium atom Magnesium ion
- ?
- Mg ? 2e? ?? Mg2
- 1s22s22p63s2 1s22s22p6 ( Ne)
- A positive ion forms with a 2 charge.
- 12 p 12 p
- 12 e- 10
e- - 0
2
18Formation of Negative Ions
- When nonmetals gain electrons to achieve an octet
arrangement, they form negative ions. - The ionic charge of a nonmetal is 3-, 2-, or 1-.
19Formation of a Fluoride Ion, F-
- Fluorine forms an octet by adding an electron to
its seven valence electrons. - ? ? ? ? 1-
- F ? e? F
- ? ? ? ?
- 1s22s22p5 1s22s22p6 ( Ne)
- A negative ion forms with a -1 charge.
- Fluorine atom Fluoride ion
- 9 p 9 p
- 9 e- 10 e-
- 0 1
20Group Number and Ions
- The Group number can be used to determine the
charge of an ion. - The charge of a positive ion is equal to its
Group number. - Group 3A 3
- The charge of a negative ion is obtained by
subtracting its Group number from 8. - Group 6A - (8-6) 2-
21Examples of Ionic Charges
22Some Important Ions in the Body
23Learning Check
- A. How many valence electrons does aluminum have?
- 1) 2e- 2) 3e- 3) 5e-
- B. How does aluminum acquire an octet?
- 1) loses 3e- 2) gains 3e-
3) gains 5e- - C. What is the ionic charge of an aluminum ion?
- 1) 3- 2) 5- 3) 3
- D. The symbol for the aluminum ion is
- 1) Al3 2) Al3- 3) Al
24Solution
- A. How many valence electrons does aluminum
- have?
- 2) 3e-
- B. How does aluminum acquire an octet?
- 1) loses 3e-
- C. What is the ionic charge of an aluminum ion?
- 3) 3
- D. The symbol for the aluminum ion is
- 1) Al3
25Chapter 4 Compounds and Their Bonds
- 4.3 Ionic Compounds
- 4.4 Naming and Writing Ionic Formulas
26Ionic Compounds
- Ionic compounds consist of positive and negative
ions. - An ionic bond is an attraction between the
positive and negative charges. - In an ionic formula, the total charge of the
positive ions is equal to the total charge of the
negative ions. total positive charge
total negative charge
27Ionic Formulas
- The formulas of ionic compounds are determined
from the charges on the ions. - atoms ions
- ? ?
? ? - Na ? ? F ?? Na F ?? NaF
- ? ?
? ? - sodium fluorine
sodium fluoride - The overall charge of NaF is zero (0).
- (1 ) (1-) 0
28Charge Balance In NaCl
- The formula does not show the charges of the ions
in the compound. - The symbol of the metal is written first,
followed by the symbol of the nonmetal.
29Charge Balance In MgCl2
30Writing a Formula from Charges
- Write the formula of the ionic compound that
forms from Ba2 and Cl?. - Write the symbols of the positive ion and the
negative ion. Ba2 Cl?
- Balance the charges until the positive charge is
equal to the negative charge. - Ba2 Cl? two Cl-
needed Cl? - Write the formula using subscripts for the number
of ions for charge balance. BaCl2
31Learning Check
- Write the correct formula for the ionic compound
of - A. Na and S2-
- 1) NaS 2) Na2S 3) NaS2
- B. Al3 and Cl-
- 1) AlCl3 2) AlCl 3) Al3Cl
- C. Mg2 and N3-
- 1) MgN 2) Mg2N3 3) Mg3N2
32Solution
- A. Na and S2-
- 2) Na2S
- B. Al3 and Cl-
- 1) AlCl3
- C. Mg2 and N3-
- 3) Mg3N2
33Names of Ions
- Positive ions are named like the element.
- Negative ions are named by changing the end of
the element name to ide.
34Learning Check
- Complete the names of the following ions
- N3? O2?
F? - _________ __________ _________
- P3? S2?
Cl? - _________ __________ _________
- Br ?
- _________
35Solution
- N3? O2? F?
- nitride oxide fluoride
- P3? S2? Cl?
- phosphide sulfide chloride
- Br ?
- bromide
36Naming Ionic Compounds with Two Elements
- The name of a binary ionic compound (two
elements) gives the name of the metal ion first
and the name of the negative ion second. - Examples
- NaCl sodium chloride
- K2S potassium sulfide
- CaI2 calcium iodide
- Al2O3 aluminum oxide
37Learning Check
- Write the names of the following compounds
- 1) Na3N ___________
- 2) KBr ___________
- 3) Al2S3 ___________
- 4) MgO ___________
38Solution
- Complete the names of the following compounds
- 1) Na3N sodium nitride
- 2) KBr potassium bromide
- 3) Al2S3 aluminum sulfide
- 4) MgO magnesium oxide
39Ionic Charges of Transition Metals
- Most transition elements have two or more
positive ions.
40Summary of Common Ions
- Of the transition metals, silver and zinc are
important elements that form only one ion.
41Learning Check
- A. The formula for the ionic compound of
- Na and O2- is
- 1) NaO 2) Na2O 3) NaO2
- B. The formula of a compound of aluminum and
chlorine is - 1) Al3Cl 2) AlCl2 3) AlCl3
-
- C. The formula of Fe3 and O2- is
- 1) Fe3O2 2) FeO3 3) Fe2O3
42Solution
- A. The formula for the ionic compound of
- Na and O2- is
- 2) Na2O
- B. The formula of a compound of aluminum and
chlorine is - 3) AlCl3
- C. The formula of Fe3 and O2- is
- 3) Fe2O3
43Naming Compounds with Transition Metals
- Transition metals with two different ions use a
Roman numeral following the name of the metal to
indicate ionic charge.
44Learning Check
- Select the correct name for each.
- A. Fe2S3
- 1) iron sulfide
- 2) iron(II) sulfide
- 3) iron (III) sulfide
- B. CuSO4
- 1) copper sulfate
- 2) copper(I) sulfate
- 3) copper (II) sulfate
45Solution
- Select the correct name for each.
- A. Fe2S3
- 3) iron (III) sulfide
- B. CuSO4
- 3) copper (II) sulfate
46Learning Check
- The correct formula is
- A. Copper (I) nitride
- 1) CuN 2) CuN3 3) Cu3N
- B. Lead (IV) oxide
- 1) PbO2 2) PbO 3) Pb2O4
47Solution
- The correct formula is
- A. Copper (I) nitride
- 3) Cu3N
- B. Lead (IV) oxide
- 1) PbO2
48Chapter 4 Compounds and Their Bonds
- 4.5 Covalent Bonds
- 4.6 Naming and Writing Formulas of Covalent
Compounds - 4.7 Bond Polarity
49Covalent Bonds
- Covalent bonds form between two nonmetals from
Groups 4A, 5A, 6A, and 7A. - In a covalent bond, electrons are shared to
complete octets.
50Learning Check
- Indicate whether a bond between the following is
1) Ionic 2) Covalent - ____A. sodium and oxygen
- ____B. nitrogen and oxygen
- ____C. phosphorus and chlorine
- ____D. calcium and sulfur
- ____E. chlorine and bromine
51Solution
- Indicate whether a bond between the following is
1) Ionic 2) Covalent - 1 A. sodium and oxygen
- 2 B. nitrogen and oxygen
- 2 C. phosphorus and chlorine
- 1 D. calcium and sulfur
- 2 E. chlorine and bromine
52H2, A Covalent Molecule
- In hydrogen, two hydrogen atoms share their
electrons to form a covalent bond. - Each hydrogen atom acquires a stable outer shell
of two (2) electrons like helium (He). - H? ?H H H H?H H2
- hydrogen molecule
53Diatomic Elements
- As elements, the following share electrons to
form diatomic, covalent molecules.
54Learning Check
- What is the name of each of the following
diatomic molecules? - H2 hydrogen
- N2 nitrogen
- Cl2 _______________
- O2 _______________
- I2 _______________
55Solution
- What are the names of each of the following
diatomic molecules? - H2 hydrogen
- N2 nitrogen
- Cl2 chlorine
- O2 oxygen
- I2 iodine
56Covalent Bonds in NH3
- The compound NH3 consists of a N atom and three H
atoms. - ? ?
- ? N ? and 3 H ?
- ?
- By sharing electrons to form NH3, the electron
dot structure is written as - H Bonding pairs
- ? ?
- H N H
- ? ? Lone
pair of electrons
57Number of Covalent Bonds
- Often, the number of covalent bonds formed by a
nonmetal is equal to the number of electrons
needed to complete the octet.
58Dot Structures and Models of Some Covalent
Compounds
59Multiple Bonds
- Sharing one pair of electrons is a single
bond. X X or XX - In multiple bonds, two pairs of electrons are
shared to form a double bond or three pairs of
electrons are shared in a triple bond. X X
or X X X X or X X
60Multiple Bonds in N2
- In nitrogen, octets are achieved by sharing three
pairs of electrons. - When three pairs of electrons are shared, the
multiple bond is called a triple bond. - octets
- ? ? ? ?
? ? ? ? - ? N ? ? N ? ?? NN
- ? ?
- triple bond
61Naming Covalent Compounds
- In the name of a covalent compound, the first
nonmetal is named followed by the name of the
second nonmetal ending in ide. - Prefixes indicate the number of atoms of each
element.
62Learning Check
- Complete the name of each covalent compound
- CO carbon ______oxide
- CO2 carbon _______________
- PCl3 phosphorus ___________
- CCl4 carbon _______________
- N2O ______________________
63Solution
- Complete the name of each covalent compound
- CO carbon monoxide
- CO2 carbon dioxide
- PCl3 phosphorus trichloride
- CCl4 carbon tetrachloride
- N2O dinitrogen monoxide
64Formulas and Names of Some Covalent Compounds
65Learning Check
- Select the correct name for each compound.
- A. SiCl4 1) silicon chloride
- 2) tetrasilicon chloride
- 3) silicon tetrachloride
- B. P2O5 1) phosphorus oxide
- 2) phosphorus pentoxide
- 3) diphosphorus pentoxide
- C. Cl2O7 1) dichlorine heptoxide
- 2) dichlorine oxide
- 3) chlorine heptoxide
66Solution
- Select the correct name for each compound.
- A. SiCl4 3) silicon tetrachloride
- B. P2O5 3) diphosphorus pentoxide
-
- C. Cl2O7 1) dichlorine heptoxide
67Electronegativity
- Electronegativity is the attraction of an atom
for shared electrons. - The nonmetals have high electronegativity values
with fluorine as the highest. - The metals have low electronegativity values.
68Some Electronegativity Values for Group A Elements
69Nonpolar Covalent Bonds
- The atoms in a nonpolar covalent bond have
electronegativity differences of 0.3 or less. - Examples Atoms Electronegativity Type
of Difference Bond N-N 3.0 - 3.0
0.0 Nonpolar covalentCl-Br 3.0 - 2.8 0.2
Nonpolar covalentH-Si 2.1 - 1.8 0.3
Nonpolar covalent
70Polar Covalent Bonds
- The atoms in a polar covalent bond have
electronegativity differences of 0.4 to 1.6. - Examples Atoms Electronegativity Type
of Difference BondO-Cl 3.5 - 3.0 0.5
Polar covalentCl-C 3.0 - 2.5 0.5 Polar
covalentO-S 3.5 - 2.5 1.0 Polar covalent
71Comparing Nonpolar and Polar Covalent Bonds
72Ionic Bonds
- The atoms in an ionic bond have electronegativity
differences of 1.7 or more. - Examples Atoms Electronegativity Type
of Difference BondCl-K 3.0 0.8
2.2 IonicN-Na 3.0 0.9 2.1 IonicS-Cs 2.5
0.7 1.8 Ionic
73Range of Bond Types
74Predicting Bond Type
75Learning Check
- Identify the type of bond between the following
as - 1) nonpolar covalent
- 2) polar covalent
- 3) ionic
- A. K-N
- B. N-O
- C. Cl-Cl
76Solution
- A. K-N
- 3) ionic
- B. N-O
- 2) polar covalent
- C. Cl-Cl
- 1) nonpolar covalent
77Chapter 4 Compounds and Their Bonds
78Polyatomic Ions
- A polyatomic ion is a group of two or more atoms
that has an overall ionic charge. - Some examples of polyatomic ions are
- NH4 ammonium OH - hydroxide
- NO3- nitrate NO2 - nitrite
- CO32 - carbonate PO43 - phosphate
- HCO3 - hydrogen carbonate (bicarbonate)
79Common Polyatomic Ions
80Formulas with Polyatomic Ions
- The formula of an ionic compound containing a
polyatomic ion is written to make the overall
charge equal zero (0). - Na and NO3- NaNO3
- When two or more polyatomic ions are needed, the
polyatomic ion is enclosed in parentheses. - polyatomic ion
- Mg2 and NO3 - Mg(NO3)2
- subscript 2 for charge balance
81Some Compounds with Polyatomic Ions
82Learning Check
- Select the correct formula for each
- A. Aluminum nitrate
- 1) AlNO3 2) Al(NO)3 3)
Al(NO3)3 - B. Copper(II) nitrate
- 1) CuNO3 2) Cu(NO3)2 3) Cu2(NO3)
- C. Iron (III) hydroxide
- 1) FeOH 2) Fe3OH 3) Fe(OH)3
- D. Tin(IV) hydroxide
- 1) Sn(OH)4 2) Sn(OH)2 3) Sn4(OH)
83Solution
- Select the correct formula for each
- A. Aluminum nitrate
- 3) Al(NO3)3
- B. Copper(II) nitrate
- 2) Cu(NO3)2
- C. Iron (III) hydroxide
- 3) Fe(OH)3
- D. Tin(IV) hydroxide
- 1) Sn(OH)4
84Naming Compounds with Polyatomic Ions
- For compounds with polyatomic ions, the positive
ion is named first followed by the name of the
polyatomic ion.NaNO3 sodium nitrateK2SO4 potas
sium sulfateAl(HCO3)3 aluminum bicarbonate or
aluminum hydrogen carbonate(NH4)3PO4 ammonium
phosphate
85Learning Check
- Match each formula with the correct name
- A. Na2CO3 1) magnesium sulfite
- MgSO3 2) magnesium sulfate
- MgSO4 3) sodium carbonate
- B. Ca(HCO3)2 1) calcium carbonate
- CaCO3 2) calcium phosphate
- Ca3(PO4)2 3) calcium bicarbonate
86Solution
- A. Na2CO3 3) sodium carbonate
- MgSO3 1) magnesium sulfite
- MgSO4 2) magnesium sulfate
- B. Ca(HCO3)2 3) calcium bicarbonate
- CaCO3 1) calcium carbonate
- Ca3(PO4)2 2) calcium phosphate
87Summary of Naming Compounds
88Naming Rules
89Naming Rules (continued)
90Learning Check
- Name each of the following compounds
- A. Mg(NO3)2
- B. CuCl2
- C. N2O4
- D. Fe2(SO4)3
- E. Ba3(PO4)2
91Solution
- Name each of the following compounds
- A. Mg(NO3)2 magnesium nitrate
- B. CuCl2 copper(II) chloride
- C. N2O4 dinitrogen tetroxide
- D. Fe2(SO4)3 iron(III) sulfate
- E. Ba3(PO4)2 barium phosphate
92Learning Check
- Write the correct formula for each
- A. potassium sulfide
- B. calcium carbonate
- C. sodium phosphite
- D. iron(III) oxide
- E. iron (II) nitrate
93Solution
- Write the correct formula for each
- A. potassium sulfide K2S
- B. calcium carbonate CaCO3
- C. sodium phosphite Na3PO3
- D. iron(III) oxide Fe2O3
- E. iron (II) nitrate Fe(NO3)2
94Chapter 4 Compounds and Their Bonds
- 4.9 Shapes of Molecules
- 4.10 Polar and Nonpolar Molecules
95VSEPR
- The shape of a molecule is predicted from the
geometry of the electrons pairs around the
central atom. - In the valence-shell electron-pair repulsion
theory (VSEPR), the electron pairs are arranged
as far apart as possible to give the least amount
of repulsion of the negatively charged electrons.
96Two Electron Pairs
- In a molecule of BeCl2, there are two bonding
pairs around the central atom Be. (Be is an
exception to the octet rule.) - The arrangement of two electron pairs to
minimize their repulsion is 180 or opposite each
other. - The shape of the molecule is linear.
97Two Electron Pairs with Double Bonds
- The electron-dot structure for CO2 consists of
two double bonds to the central atom C. - Because the electrons in a double bond are held
together, a double bond is counted as a single
unit. - Repulsion is minimized when the double bonds are
placed opposite each other at 180 to give a
linear shape.
98Three Electron Pairs
- In BF3, there are 3 electron pairs around the
central atom B. (B is an exception to the octet
rule.) - Repulsion is minimized by placing three electron
pairs in a plane at angles of 120, which is a
trigonal planar arrangement. - The shape with three bonded atoms is trigonal
planar.
99Two Bonding Pairs and A Nonbonding Pair
- In SO2, there are 3 electron units around the
central atom S. - Two electron units are bonded to atoms and one
electron pair is a nonbonding pair. - Repulsion is minimized by placing three electron
pairs in a plane at angles of 120, which is
trigonal planar. - The shape with two bonded atoms is bent.
100Learning Check
- The shape of a molecule of N2O (N N O) is
- 1) linear
- 2) trigonal planar
- 3) bent (120)
101Solution
- The shape of a molecule of N2O (N N O) is
- 1) linear
- The electron-dot structure uses 5 e for each N
and 6 e for O (16 e total) has octets using two
double bond to the central N and one nonbonding
pair. The shape with two bonded atoms is linear. -
- N N O
-
102Four Electron Pairs
- In CH4, there are 4 electron pairs around the
central atom C. - Repulsion is minimized by placing four electron
pairs at angles of 109, which is a tetrahedral
arrangement. - The shape with four bonded atoms is called
tetrahedral.
103Three Bonding Atoms and One Nonbonding Pair
- In NH3, there are 4 electron pairs around the N.
- Three pairs are bonded to atoms and one is a
nonbonding pair. - Repulsion is minimized by placing four electron
pairs at angles of 109, which is a tetrahedral
arrangement. - The shape with three bonded atoms is pyramidal.
104Two Bonding Atoms and Two Lone Pairs
- In H2O, there are 4 electron pairs around O.
- Two pairs are bonded to atoms and two are
nonbonding pairs. - Repulsion is minimized by placing four electron
pairs at angles of 109 called a tetrahedral
arrangement. - The shape with two bonded atoms is called bent.
105Some Steps Using VSEPR to Predict Shape
- Draw the electron dot structure.
- Count the electron pairs around the central atom.
- Arrange the electron pairs to minimize repulsion.
- Determine the shape using the number of bonded
atoms in the electron arrangement.
106Summary of Electron Arrangements and Shapes
107Learning Check
- Use VSEPR theory to determine the shape of the
following molecules or ions. - 1) tetrahedral 2) pyramidal 3) bent
- A. PF3
- B. H2S
- C. CCl4
- D. PO43-
108Solution
- Use VSEPR theory to determine the shape of the
following molecules or ions. - 1) tetrahedral 2) pyramidal 3) bent
- A. PF3 2) pyramidal
- B. H2S 3) bent
- C. CCl4 1) tetrahedral
- D. PO43- 1) tetrahedral
109Polar Molecules
- A polar molecule contains polar bonds.
- The separation of positive and negative charge is
called a dipole. - In a polar molecule, dipoles do not cancel.
- ? ?-
- HCl ClNCl
- dipole Cl
- dipoles do not cancel
110Nonpolar Molecules
- A nonpolar molecule contains nonpolar bonds
- ClCl HH
- or a symmetrical arrangement of polar bonds.
- OCO Cl
- ClCCl
- Cl
- dipoles cancel
111Learning Check
- Identify each of the following molecules as
- 1) polar or 2) nonpolar. Explain.
- A. PBr3
- B. HBr
- C. Br2
- D. SiBr4
112Solution
- Identify each of the following molecules as
- 1) polar or 2) nonpolar. Explain.
- A. PBr3 1) polar pyramidal
- B. HBr 1) polar polar bond
- C. Br2 2) nonpolar, nonpolar bond
- D. SiBr4 2) nonpolar dipoles cancel