Title: Kinematics in one dimension
1Chapter 2
- Kinematics in one dimension
2Kinematics
- Description of how objects move
- One dimensional translational motion is an object
moving along a straight line path - We will consider objects to be point particles
for simplicity (think about a runner
3In Other Words
- A complex look at something moving in a straight
line. - This complexity is necessary for later use in the
study of velocity and acceleration - You will eventually be able to solve the
velocity, time, or position in the x and y
directions at any point along this path.
4Frame of Reference
5 Reference Frames and Displacement
We make a distinction between distance and
displacement. Displacement (blue line) is how
far the object is from its starting point,
regardless of how it got there. Distance traveled
(dashed line) is measured along the actual path.
6Distance vs. Displacement
- Mary Prakel starts at the finish line, makes 8
grueling laps around the track, and stops exactly
where she started. - What is her distance traveled?
- What is her displacement?
7Coordinate axes
- Used to show direction
- Position of an object at any moment is given by
its x coordinate
- Directions of the axes can be placed at our
convenience. - Vertical motion often represented by the y axis
y
x
-x
-y
8Vectors
- Quantities that have both magnitude and
direction. - Ex displacement, velocity, acceleration
- Quantities such as distance and speed, which
describe only magnitude, are called scalars.
9Vectors continued
- Vectors which point in one direction get a
positive sign - Those in the opposite direction get a negative
sign. - Just because a displacement vector is negative
does not mean it is found in the x side of the
line. (what would be an example of this?) -
y
x
x2
x1
x
10Vectors continued
- Assume each division stands for 5 m
- Displacement is solved using the formula ?x x2
x1 - ?x 20m 5m
- Displacement is 15 m
y
x
x2
x1
x
11Vectors continued
- This vector shows a displacement of the same
magnitude in the opposite direction. - ?x x2 x1 in this case is
- ?x 5m 20m -15m
- Displacement is -15m
y
x2
x1
x
12Vectors continued
- In these cases a vector pointing right is
positive while a vector pointing left is
negative. -
y
x
13Understanding Quantities
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16Speed vs. Velocity
- Speed refers to how far an object travels in a
certain amount of time regardless of direction. - Average speed distance traveled
- time elapsed
- Speed is always a positive number
17Average Velocity
- Velocity refers to an objects displacement in a
certain amount of time. - Rate of change of position
- Average velocity displacement
- time elapsed
- final position initial position
- time elapsed
- Can be positive or negative
18Cruise control automatically keeps your car at a
constant speed. You head east for 4000 s with
the cruise control set at 31 m/s. You end up
150,000 m east of Versailles.
- How far east of Versailles did you start out?
- Sketch a graph of x vs. t for this motion.
- How fast are you traveling in mph?
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20 about 70 mi/hr
21Some Av. Velocity Examples
22Solve the Average Velocity for A,B,C,D
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24Now draw x vs. t graphs for the four cars.
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26Check your understanding
- Which of the cars have positive displacements?
- Which graph has the steepest slope?
- Put the cars speeds in order from greatest to
least. - Which has a greater velocity B or D?
- A and C (B and D have negative displacements)
- B (C has the most gradual slope)
- B, D, A, C.
- D has the greater velocity. A more negative
number is not greater than a less negative number.
27Nonuniform Motion
- Description of an object that does not maintain
the same motion during the entire time interval
being studied - In other words, it has changing velocity during
the time being studied - The previous graphs represented uniform motion.
Lets look at some nonuniform motion.
28Nonuniform motion
- Attempt to solve the average velocity for each of
these vehicles between 0 and 4 s. - Then attempt to sketch a graph for each cars
nonuniform motion. (not all graphs will be
straight lines)
29Average velocity
- A is 50 m/s
- B is 50 m/s
- C is 50 m/s
- D is -50 m/s
- E is -50 m/s
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31Interpreting slope for nonuniform motion
- If you draw a straight line segment (secant)
connecting points P1 and P2, its slope is the
average velocity of the object between those two
points - Which segment has the greater average velocity?
32Average vs. Instantaneous Velocity
- The average velocities we have been solving do
not describe variations in the objects velocity
throughout the trip. - The graphs just made do not necessarily represent
the actual velocities of the cars at any instant
of time between 0 and 4 s. - To find the velocity of an object at any moment
during the trip, a speedometer, graphical
analysis, or calculus must be used.
332-3 Instantaneous Velocity
The instantaneous velocity is the average
velocity, in the limit as the time interval
becomes infinitesimally short.
(2-3)
These graphs show (a) constant velocity and (b)
varying velocity.
34Graphical analysis
- To graphically solve the instantaneous velocity
at any point on the curve, we must draw a tangent
line that just grazes the curve and then solve
its slope. - All curves are essentially made up of many
straight lines.
35Graphs of v vs. t
- Graph a shows non uniform motion x vs. t.
- The lines of tangent for P1-P3 show the
instantaneous velocity at those points. - b shows the v vs. t graph for the same motion.
36Notice
- P1 slope is 0, so velocity is zero
- P2 has the steepest slope, so it represents the
greatest velocity. - P3 has a slope less than P2 so the velocity is
less at P3 than at P2 - This is the graphical representation of a
derivative in calculus.