Chapter 16: Acids and Bases - PowerPoint PPT Presentation

1 / 42
About This Presentation
Title:

Chapter 16: Acids and Bases

Description:

react with bases to form react with acids to salt and water form a salt and water ... L. A. L. B. Adduct. ep acceptor ep donor. Self-Ionization of Water ... – PowerPoint PPT presentation

Number of Views:167
Avg rating:3.0/5.0
Slides: 43
Provided by: JBo48
Category:

less

Transcript and Presenter's Notes

Title: Chapter 16: Acids and Bases


1
  • Chapter 16 Acids and Bases

2
Experimental Definitions
  • Acids Bases(alkalis)
  • Turn blue litmus red Turn red litmus blue
  • taste sour taste bitter
  • react with active metals slippery feel
  • react with bases to form react with acids to
    salt and water form a salt and water

3
Arrhenius Definition
  • Acids release hydrogen ions in water
  • HCl

H2O
H Cl-
  • Bases release hydroxide ions in water

H2O
Na OH-
NaOH
4
The Hydronium Ion
  • The H ion produced by an acid in water does not
    exist in isolation. It is bonded to a water
    molecule
  • H H2O H3O

H3O is called the hydronium ion.
The Lewis dot structure of the hydronium ion is
shown below
The hydronium ion is also hydrated by other water
molecules

HOH

H
5
Types of Acids
  • Monoprotic acids
  • release one hydrogen (proton) ion per formula
    unit.
  • HNO3 H NO3-
  • Diprotic acids
  • Release two protons per formula unit.
  • H2SO4 2H SO42-
  • Triprotic acids
  • Release three protons per formula unit.
  • H3PO4 3H PO43-

6
Carboxylic Acids
  • Not all hydrogens in a compound are acidic.
  • In acetic acid, only the hydrogen attached to the
    carboxyl group is acidic

Carboxyl group
H
Acidic hydrogen
Non-acidic hydrogens
Acetate Ion
7
Strong and Weak Acids and Bases
  • A strong acid or base is 100 ionized
  • HCl H Cl-
  • NaOH Na OH-
  • A weak acid or base is partially ionized,
    equilibrium
  • HC2H3O2 H C2H3O2-
  • NH3 H2O NH4 OH-

8
Aqueous NH3 is sometimes referred to as NH4OH
  • NH3 H2O NH4 OH- NH4OH

ammonia
Ammonium ion
Ammonium hydroxide
Hydroxide ion
Although some ammonium hydroxide is formed in
this reaction, the equilibrium lies to the left
and the solution is better referred to as
aqueous ammonia.
9
Acids React With Bases.(Neutralization)
  • H OH- H2O
  • HCl NaOH H2O NaCl
  • H NH3 NH4
  • HCl NH3 NH4Cl
  • HC2H3O2 OH- C2H3O2- H2O
  • HC2H3O2 NaOH NaC2H3O2 H2O

10
Reactions of Acids
  • With active metals
  • Form H2(g) and a salt
  • H2SO4(aq) Zn(s) H2(g) ZnSO4(aq)
  • With metal oxides
  • Form H2O(l) and a salt
  • 2HCl(aq) CaO(s) H2O(l) CaCl2(aq)
  • With carbonates and bicarbonates
  • Form CO2(g), H2O(l), and a salt
  • CaCO3(s) 2HCl(aq) CO2(g) H2O(l)
    CaCl2(aq)

11
Acidic Reactions
  • Acids react with metal sulfides
  • To form H2S(g) and a salt
  • H2SO4(aq) FeS(s) H2S(g) FeSO4(aq)
  • Non-metal oxides react with water to form acid
  • SO3(g) H2O(l) H2SO4(aq)
  • The acids formed this way in the atmosphere may
    fall back to earth as acid precipitation.

12
Reactions of Bases
  • With transition metal salts
  • Form insoluble metal hydroxides and a salt
  • 2KOH(aq) Ni(NO3)2(aq) Ni(OH)2(s)
    2KNO3(aq)
  • With amphoteric hydroxides
  • Amphoteric hydroxides will react with acids or
    bases
  • Al(OH)3(s) NaOH(aq) NaAl(OH)4(aq)
  • Al(OH)3(s) 3HCl(aq) AlCl3(aq) 3H2O(l)
  • With amphoteric metals
  • Form hydrogen gas and soluble metal complexes.
  • 2Al(s) 2NaOH(s) 6H2O(l) 2NaAl(OH)4(aq)3H2(g
    )

13
Definitions of Acids and Bases
  • Brønsted - Lowry
  • Acid proton (H) donor
  • Base proton acceptor
  • HF H2O H3O F-
  • acid base c.a. c.b.
  • NH3 H2O OH- NH4
  • base acid c. b. c. a.

14
Brønsted - Lowry
  • The driving force of the Brønsted Lowry
    acid-base reaction is the formation of weaker
    acids and weaker bases.
  • The products formed are conjugate acids (c. a.)
    and conjugate bases (c. b.)
  • The Brønsted Lowry acid and its conjugate base
    and the Brønsted Lowry base and its conjugate
    acid are called a conjugate acid-base pair.

15
Conjugate acids and bases
  • Identify conjugate Acid-Base pairs in an
    acid-base reaction. Complete reactions
    containing conjugate acid-base pairs.
  • Take a hypothetical reaction between an acid HA
    and a base B-.
  • HA B- A- HB
  • In the forward reaction HA acts as an acid by
    donating a proton to the base, B-.
  • In the reverse reaction, HB acts as an acid by
    donating the proton back to A-, the base.

16
Conjugate Acid-Base Pairs
  • The acid from the forward reaction, HA becomes
    A-, the base for the reverse reaction.
  • The base from the forward reaction, B- becomes
    the acid, HB for the reverse reaction.
  • HA and A- are a conjugate acid-base pair.
  • B- and HB are a conjugate acid-base pair.

17
Conjugate Acids and Bases
  • Every acid has a conjugate base, and every base
    has a conjugate acid.
  • The conjugate base of the pair has one fewer H
    and one more negative charge than the acid.
  • The conjugate acid of the pair has one more H and
    one fewer negative charge than the base.

18
Conjugate acid-base reactions
  • A BrØnsted-Lowry acid-base reaction occurs when
    an acid and a base react to form their conjugate
    base and conjugate acid, respectively
  • acid1 base2 base1 acid2
  • For example, in the reaction
  • HF H2O H3O F-
  • acid base c.a. c.b.
  • HF F- are a conjugate pair.
  • H2O H3O are a conjugate pair.

19
Definitions of Acids and Bases Continued
  • Lewis
  • Acid electron pair acceptor
  • Base electron pair donor
  • with previous examples
  • H H
  • H-N H- Ö ? H - N - H
    Ö
  • H H
    H H
  • L.B. L.A.
  • e p donor e p acceptor

20
Another Example of a Lewis Acid-Base Reaction
  • Cl H Cl
    H
  • Cl-Al N-H Cl-Al N-H
  • Cl H Cl
    H
  • L. A. L. B. Adduct
  • ep acceptor ep donor

21
Self-Ionization of Water
  • Write a chemical equation for the autoionization
    of water.
  • Water itself is slightly ionized in the liquid
    state The autoionization may be written two
    different ways
  • 2 H2O (l) H3O(aq) OH-(aq)
  • or
  • H2O (l) H (aq) OH-(aq)

22
Extent of Ionization of Water
  • The extent of ionization of water is given by the
    expression Kw
  • Kw H3O(aq)OH-(aq)
  • at 25oC, Kw 1.0 x 10-14.
  • H3O(aq) Kw/OH-(aq)
  • OH-(aq) Kw/ H3O(aq)

23
Ion Product Constant of Water, Kw
  • Kw HOH or
  • Kw H3OOH-
  • In a neutral solution, H OH- and
  • H3O OH-
  • At 25oC,, Kw 1 x 10-14 HOH-
  • In a neutral solution, substituting H for
    OH-
  • 1 x 10-14 HH H2 ?1 x 10-14
    ?H2

H 1 x 10-7 OH-
24
Balance between H3O OH-
  • In a neutral solution,
  • H3O(aq) OH-(aq) 1.0 x 10-7 M
  • In basic solution OH-(aq) gt H3O(aq)
  • OH-(aq) gt 1.0 x 10-7 M
  • H3O(aq) lt 1.0 x 10-7 M
  • In acidic solution H3O(aq) gt OH-(aq)
  • OH-(aq) lt 1.0 x 10-7 M
  • H3O(aq) gt 1.0 x 10-7 M

25
Relation between OH- H3O
  • When H3O(aq) increases, OH-(aq) decreases.
  • When H3O(aq)decreases, OH-(aq) increases.
  • When OH-(aq) increases, H3O(aq) decreases.
  • When OH-(aq)decreases, H3O(aq) increases.

26
pH and pOH
  • Given one of the following, calculate the others
    H(aq) H3O(aq) , OH-(aq), pH, pOH.
  • Definition pX -log(X)
  • pH -logH(aq) -logH3O(aq)
  • pOH - logOH-(aq)

27
Some relationships
  • Kw H3O(aq)OH-(aq)
  • pKw - logKw -logH3O(aq)OH-(aq)
  • -log(1.0x10-14) -log H3O(aq)-logOH-(aq)
  • 14 pH pOH pH 14 - pOH pOH 14 - pH
  • H3O(aq) Kw/OH-(aq) (10-14)/OH-(aq)
  • OH-(aq) Kw/H3O(aq) (10-14)/H3O(aq)

28
Sample Problem
  • The pH of a solution is 9.40. Calculate the
    H(aq) H3O(aq) OH-(aq) and pOH.
  • pH -logH(aq) logH(aq) -pH
  • H(aq) antilog(-pH) 10-pH 10-9.40
  • 4.0 x 10-10 M H3O(aq)
  • OH-(aq) (10-14)/ H3O(aq) 10-14/ 4.0 x
    10-10
  • 2.5 x 10-5 M
  • pOH 14 - pH 14 - 9.40 4.60
  • pOH - logOH-(aq) - log(2.5 x 10-5 M) 4.60

29
Acidic, Basic, and Neutral Solutions
  • Given pH, determine whether a solution is acidic,
    neutral or basic (alkaline).
  • If pH 7, H(aq) OH-(aq) and the solution
    is neutral.
  • If pH lt 7, H(aq) gt OH-(aq) and the solution
    is acidic.
  • If pH gt 7, H(aq) gt OH-(aq) and the solution
    is basic or alkaline.

30
For Example
  • The pH of a solution is 9.29. The solution is
    basic or alkaline.
  • The pH of another solution is 2.13. The solution
    is acidic.
  • The pH of yet another solution is 7.00 at 25oC.
    The solution is neutral.

31
pH Chart
32
pH Properties
33
Measurement of pH
  • pH indicator
  • A species whose color is different in acid and in
    base, which is used to monitor the pH of a
    solution.
  • An indicator is a weak acid or base which has a
    different color for its acid form or its
    conjugate base form.
  • More accurate pH measurements are made with
    electronic devices called pH meters.

34
Hydrolysis Salts in Water
  • When salts dissolve in water acid, basic, or
    neutral solutions may be formed. The process is
    called hydrolysis
  • The pH of the resulting solution depends on the
    combination of acid and base used in forming the
    salt

35
Solution Formed From Salt
36
Example Problem
  • Does NaC2H3O2 form an acidic, basic, or neutral
    solution when dissolved in water?
  • NaC2H3O2, sodium acetate is a salt of a weak acid
    (acetic acid) and a strong base (NaOH).
  • HC2H3O2 NaOH NaC2H3O2 H2O
  • When the salt dissolves, the acetate ion reacts
    with water to form OH- ion
  • NaC2H3O2 Na C2H3O2-
  • C2H3O2- H2O HC2H3O2 OH-

37
Buffers
  • Buffers are solutions which keep the pH of a
    solution almost constant when a strong acid or
    base are added.
  • Buffers are prepared by mixing a weak acid and
    the salt of the acid or by mixing a weak base and
    the salt of the base.

38
How the acetic acid/sodium acetate buffer works.
  • The solution contains HC2H3O2 (which acts as an
    acid) and C2H3O2- (which acts as a base)
  • When base (OH-) is added, it is neutralized by
    HC2H3O2
  • OH- HC2H3O2 C2H3O2- H2O
  • When acid (H) is added, it is neutralized by
    C2H3O2-
  • H C2H3O2- HC2H3O2

39
Acid-Base Titration
  • The concentration or amount of acid or base in a
    sample may be determined by a neutralization
    reaction
  • When determining the concentration of a an acid,
    a carefully measured volume of the acid is added
    to a flask.
  • A few drops of acid-base indicator are added to
    the flask.
  • A standard base, of known concentration is added
    slowly to the flask from a buret until just one
    drop of the added base changes the color of the
    indicator.
  • This point is called the end point of the
    titration.

40
Buret Used in Acid-Base Titrations
41
Titration
  • At the end point an equivalent amount of base has
    been added. This is sometimes called the
    equivalence point.
  • At the equivalence point, the moles of H in the
    acid is equal to the moles of OH- added.

42
Example Problem
  • Calculate the concentration of an HCl solution
    determined by a titration in which 50.0 mL of the
    solution is added to a flask. Indicator is
    added, and 29.6 mL of 0.967 M NaOH are required
    to reach the end point.
  • HCl NaOH NaCl H2O

mol HCl mol NaOH (0.967 mol/L)(29.6mL)(.001L/m
L)
0.0274 mol
M(NaOH) mol/L (0.0274 mol)/(50.0mL)(0.001L/mL
)
0.548 mol/L 0.548M
Write a Comment
User Comments (0)
About PowerShow.com