Repertory Grid: an example

1
Repertory Grid an example

• Students
• Brian (E1)
• Kim (E2)
• Terry (E3)
• Ian (E4)
• Stephen (E5)
• Nadia (E6)
• David (E7)

2
The Session

• Three students selected at random
• Brian (E1), Kim(E2) and Terry(E3)
• E1 and E3 are similar (school-leaver), E2 is
  different (mature)
• Construct (C1) is school-leaver
  --------------------------- mature
• E4 is mature
• E5 is mature
• E6 is mature
• E7 is mature
• Rating grid becomes
• E1 E2 E3 E4 E5 E6 E7
• C1 3 1 3 1 1 1 1 C1
• (school-leaver) (mature)

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4
Distance between concepts

• eg between E1 and E2 sum of absolute values of
  the difference for each construct.
• for school leaver(C1) 3-1 2 2
• for poor qualifications (C2) 1-2 -1 1
• for unsure (C3) 3-1 2 2
• for asks questions (C4) 1-3 -2 2
• for good attendance (C5) 1-3 -2 2
• for does work (C6) 1-3 -2 2
• for joins in socially (C7) 1-3 -2 2
• for not organised (C8) 3 -1 2 2
• for scruffy (C9) 3-1 2 2
• total 17

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Distance Matrix

• E1 E2 E3 E4 E5 E6 E7
• E1 0 17 12 8 6 13 10
• E2 0 5 9 14 4 7
• E3 0 10 12 9 8
• E4 0 6 6 6
• E5 0 9 8
• E6 0 11
• E7 0

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Calculating a hierarchy

• find the smallest distance E2 is closest to E6

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E2
E6
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Re-draw the distance matrix

• Use an average approach
• eg dist(E2,E1) 17, dist(E6,E1) 13 gt
  dist(E2/E6,E1) average(17,13) 15
• E2/E6 E1 E3 E4 E5 E7
• E2/E6 0 15 7 7.5 11.5 9
• E1 0 12 8 6 10
• E3 0 10 12 8
• E4 0 6 6
• E5 0 8
• E7 0

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Modifying Hierarchy

6
4
E2
E6
E5
E1
E4
E7
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Re-draw the distance matrix

• Again use an average approach eg
• dist(E2/E6, E1/E5/E4/E7)) average of
• dist(E2/E6,E1)
• dist(E2/E6,E5)
• etc
• i.e. average(15,11.5,7.5,9) 10.75
• E2/E6 E1/E5/E4/E7 E3
• E2/E6 0
• E1/E5/E4/E7 10.75 0
• E3 7 10.5 0

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Modifying the Hierarchy
13
7
6
4
E2
E6
E5
E1
E4
E7
E3
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Re-draw the distance matrix

• All we need to now is to calculate the distance
  between (E2/E6/E3) and (E1/E5/E4/E7)
• i.e. average of dist(E2/E6, E1/E5/E4/E7) and
  dist(E3,E1/E5/E4/E7)
• (10.75 10.5)/2 10.625

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Modifying the Hierarchy
11
7
6
4
E2
E6
E5
E1
E4
E7
E3