Title: Chapter 3: Fundamental Measurements
1Chapter 3 Fundamental Measurements
2Measurement
- Components of Measurement
- Numerical quantity
- Unit
- Name of substance
- For example,
- 325.0 mL water
Numerical quantity
unit
Name of substance
3Metric System
- Also called the International or SI system.
- Based on Units of 10
- SI base Units
- Other units derived from base units
- Prefixes indicating power of ten
4SI Units
Quantity Name Symbol Length meter m Mass kilog
ram kg Temperature Kelvin K Time second s Amount
mole mol
5Common Metric Prefixes
Prefix Symbol Decimal Exponential Mega M 1,000,00
0 106 Kilo k 1000 103 Centi c 0.01 10-2 M
illi m 0.001 10-3 Micro ? 0.000001 10-6
6Metric Units of Length
- Base Unit is the meter (m), a little longer than
a yard. - Other common Units
- Centimeter, cm 1 cm 0.01m, 0.4 inch
- Kilometer, km 1 km 1000 m, 5/8 mile
- Millimeter, mm 1 mm 0.001 m, thickness of a
dime.
7Units of Length
Insert Fig. 3.4
8Dimensional Analysis
- (Also called the factor-label method)
- To convert a measurement from one unit to
another, multiply the known quantity and unit(s)
by a conversion factor to equal the desired
quantity and unit(s)
Known quantity and unit(s)
Quantity with desired unit(s)
Conversion Factor(s)
X
9Converting Units Using Conversion Factors
- Equivalencies yield two conversion factors
- For example
- 1 ft 12 in
- 1ft/12 in 1
- or 12 in/1 ft 1
- How many inches in 5 ft?
- Number of inches 5ft x
12 in 1 ft
60 in.
10Considerations in Choosing Conversion Factors
- The chosen conversion factor cancels all units
except those required for the answer. - Set up the calculation so that the unit you are
converting from (beginning unit) is on the
opposite part of the conversion factor (numerator
or denominator) from the unit you are converting
to (final unit).
11Formulas
final unit
beginning unit x
final unit
beginning unit
ft
Mi x
ft
mi
12Choosing the correct conversion factor
- Choose the conversion factor which will yield the
correct units in the denominator and numerator
after the units are cancelled. - Problem How many cm are in 50 m?
- 1. Unit equivalency 1 cm 0.01 m
- 2. Conversion factors 1cm/0.01m or 0.01m/1cm
- 3. In the answer, you want cm in the numerator so
choose 1 cm/0.01m.
13Finish the Problem
- 4. Multiply given by chosen conversion factor
- Answer Given x Conversion factor
- Cm 50 m x
1 cm
5000 cm
0.01 m
5. Cancel units to get correct answer
14Conversion Factors May Be Multiplied Together in
Series
- Example Convert 179,800 s to days.
- Solution Plan s min hours
days - Conversion equivalents 1 min 60 s,
- l hr 60 min, 1 day 24 hr
- Conversion factors 1 min/60 s, 1 hr/60min,
- 1 day/ 24 hr
179800 s x
1min/60s x
1hr/60 min x
1 day/24hr
2.08 days
15Ratios with New Final Unit in Denominator
Final unit1
Beginning unit
Final unit1
X
Beginning unit
Final unit2
Final unit2
mi
mi
h
x
min
h
min
16Problem Which Has New Final Unit in Denominator
- Convert 55.0 mi/h to mi/min
- 1 h 60 min
- Conversion factor 1 h/60 min
- mi/min 55.0
mi
1 h
0.917
x
mi
h
60 min
min
17Volume Conversions
- The Volume of a rectangular solid
- Volume length x width x height
- or V (l)(w)(h)
- For a cube V (l)(l)(l) (l)3
- The SI unit of length is the meter.
- The SI unit of volume is the cubic meter, (a box
1 m on each side) m3 - m3 is a derived unit.
18Atomic Number Atomic Symbol Atomic Mass
19Volume Equivalencies
- 1 m3 (100 cm)3 (100)3 cm3
- 1,000,000 cm3
- 1 cm3 1 cc 1 mL (milliliter)
- 1mL 0.001 L, 1000mL 1 L (liter)
- 1 L 1 dm3 .001 m3
- 1mL 1000 mL (microliter, a millionth of a liter)
20Metric Volume and Length Relationships
Insert figure 3.5
21Volume Conversions
- Convert 324 mL to Liters
- 1 mL 0.001 L
- Conversion factor 0.001L/mL
324 mL x
0.001 L/mL
0.324 L
22Mass Conversions
- Important Mass Equivalencies
- 1 kg 1000g 1 g 0.001 kg
- 1 mg 0.001 g 1 g 1000 mg
- 1 µg 0.001 mg 0.000001 g
- 1 g 1,000,000 µg
23Mass Conversions
- Example problem
- Convert 456.0 g to kg.
- Answer
- Equivalency 1000 g 1 kg
- Factor 1 kg/1000 g
- 456.0g x 1 kg/1000 g
0.4560 kg
24Mass Equivalents
Insert figure 3.10
25English/Metric Conversions
- Common English/Metric Conversion Equivalencies
are shown in Table 3.5 - English/Metric conversions may also be done with
conversion factors
Known quantity and unit(s)
Quantity with desired unit(s)
Conversion Factor(s)
X
26Another Problem
- Convert 31.0 in to cm
- 1 in 2.54 cm
- 2.54cm/ in
- 31.0 in x
2.54 cm
78.7 cm
1 in
27Conversion Factors May Be Multiplied Together in
Series
- Convert 55 mi/h to m/s
- Conversion equivalencies/factors
- 1 km 0.62 mi 1 km/0.62mi
- 1 km 1000 m 1000m/1 km
- 60 min 1 h 1h/60 min
- 60 s 1 min 1 min/60 s
- 55
mi
1km
1000m
1 h
x
x
1 min
x
x
h
0.62 mi
km
24.6 m/s
60 min
60 s
28Uncertainty in Measurement
- Differentiate between precision and accuracy.
- Precision- The closeness of a measurement to
other measurements of the same phenomenon in a
series of experiments - Accuracy- The closeness of a measurement to the
true value.
29A Comparison of Accuracy and Precision
30Significant Figures
- The number of significant figures (digits) is a
measure of the uncertainty of a measurement. The
greater the number of significant digits, the
less uncertain a number is. - The number of significant figures equals the
number of digits that are certain, plus one
additional digit , which is an uncertain digit.
31Reading a Volumetric Device
Insert figure 3.13
Note the Meniscus
32Determine the Number of Significant Digits
- All digits are significant except zeros that are
not measured but are used only to position the
decimal point. - 1. The measured quantity should have a decimal
point. - 2. Start at the left of the number and move
right until you reach the first non-zero digit. - 3. Count that digit and every digit to its right
as significant.
33If the Number Has No Decimal Point
- For example 9500 m. It would be assumed that the
zeros are not significant. Scientific notation
is used to show which zeros are significant - 9.5 x 103 has 2 significant digits.
- 9.50 x 103 has 3 significant digits.
- 9.500 x 103 has 4 significant digits.
34How many significant digits does each of the
following numbers have?
- Number significant digits
- 0.0050 m 2
- 0.0003056 L 4
- 56,980. Cm3 5
- 3.7890 x 104 s 5
- 1.2 x 10-8 mL 2
35Exact Numbers
- There is no uncertainty associated with exact
numbers. Numbers that are a result of counting
are exact (if the counting is done exactly).
Definitions contain exact numbers. For example
60 s in one min, 1000 mg 1 g, 0.01m 1 cm - Exact numbers do not limit the number of
significant figures in an answer. - Exact numbers have the number of significant
digits the calculation requires.
36Multiplying and Dividing
- When numbers are multiplied and divided, the
answer has the same number of significant digits
as measurement with the least number of
significant digits. (Exact numbers have an
infinite number of significant digits.) - E. g., 0.00569 x 0.91 0.0052
- 3 sd 2 sd 2 sd
37Significant Figures in Division
- 9863./876.89 11.25
- 4 sd 5 sd 4 sd
38Significant Figures in Addition and Subtraction
- In addition and subtraction, the answer has the
same number of decimal places as the measurement
with the fewest number of decimal places - E. g., 23.560 2.1 25.7
- 3 dp 1 dp 1 dp
- 0.0056 - 0.004067 0.0015
- 2 dp 4 dp 2 dp
39Rounding
- The round a number to the proper number of
significant figures or decimal points, start at
the right of the number and remove all digits
needed to have the correct number of digits. - If the last digit removed is gt5, round up.
(Increase the last remaining digit by 1.) - If the last digit removed islt 5 leave the
remaining last digit the same.
40Scientific Notation
- Exponential notation is also called Scientific
Notation. - A method of expressing very large and very small
numbers.
41Convert Between Notations
- Numbers in Scientific Notation are in the form
X.YZ x 10n. - X.YZ is the coefficient n is the exponent.
- To convert numbers gt 10 to Scientific Notation,
move the decimal point to the left until the
number has the proper form, then nthe number of
places moved. - E. g. 5286.2
5.2862 x 103
3 places
42Convert to Scientific Notation
- If the number is between 1 and 9.999, n0.
- E. g., 6.623 6.623 x 100
- If the number is lt 1, move the decimal point to
the right until the number is in the proper form,
n - the number of places moved. - E.g., 0.0000652
6.52 x 10-5
5 places
43Convert from Scientific to Normal Notation
- If n gt0, move decimal point n places to the
right, adding 0s as necessary. - E. g., 5.3 x 104 53000 53000
- If n 0, drop the exponential part.
- E. g., 2.5x100 2.5
4 places
44Convert to Normal Notation
- If n lt 0, move decimal point n places to the
left, adding 0s as necessary - E. g. 7.23 x 10-4 0000723 0.000723
4 places
45Multiply and Divide Numbers in Scientific Notation
- To multiply, algebraically add exponents and
multiply coefficients. Adjust decimal point if
necessary - (5.3x104) x (6.5x10-7) 5.3 x 6.5 x 10(4-7)
34.24 x 10-3 3.424 x 10-2 3.4 x 10-2 - If the decimal point is moved to the left, the
exponent is increased by the number of places
moved. If the decimal point is moved to the
right the decimal point is decreased by the
number of places moved.
Decimal point moved 1 place to the left
46Dividing Numbers in Scientific Notation
- To divide, divide the numerator coefficient by
the denominator coefficient and subtract the
denominator exponent from the numerator
exponent. Adjust decimal point as needed. - E. g., x10(8-3) 1.8 x
105
8.2x108
8.2
4.6x103
4.6
47Adding and Subtracting Numbers in Scientific
Notation
- Convert numbers to be added or subtracted to have
the same exponent. Add or subtract the
coefficients. Adjust decimal point and exponent
to proper form. - E. g., 4.24x102 3.6 x 103
Move decimal point 1 place to the left to
increase the exponent by 1
- 0.424 x 103 3.6 x 103 4.024 x 103 4.0 x 103
48Calculators
- Most calculators will do the exponential notation
work for you. - Learn how your calculator does exponential
notation.
49Density and Specific Gravity
- What is density?
- Density mass/volume
- Specific Gravity
- S. G. (Density of Substance)/(Density of Water)
- Density of water 1.00 g/mL at 4o C
- Q A student took an unknown liquid and
discovered that a volume of 9.02 mL had a mass of
8.31g. Calculate the density and S. G. - A d m/v 8.31g/9.02mL 0.92 g/mL
- S. G. (0.92 g/mL)/(1.00 g/mL) 0.92
(Note Specific gravity has no units.)
50Objective 5 (cont.)
- Q Calculate the mass of a 30 mL sample of a
substance which has a density of 0.92 g/mL. - A d m/v m d x v (0.92g/mL)x(30mL)
27.6 g
51Objective 5 (cont.)
- Q Calculate the volume of a 100g sample of a
substance which has a density of 0.92 g/mL. - A d m/v
- v m/d 100g/0.92g/mL
108.7 mL
52Density and Specific Gravity
- Immiscible liquids with a lesser density will
float on top of liquids with a greater density. - Two devices to measure specific gravity or
density - Hydrometer
- Pycnometer
53Hydrometers for Measuring Specific Gravity
Insert figure 3.18
54Temperature Measurements
- Common Units of Temperature
- Fahrenheit (oF)
- Celsius (oC)
- Kelvin (K)
- Boiling Point of Water
- 212oF , 100oC, 373.15 K
- Freezing Point of Water
- 32oF, 0oC, 273.15 K
- Absolute zero is 0 K. You cant get any colder
than this!
55A Comparison of Temperature Scales
Insert Figure 3.21
56Conversion Among Temperature Units
- Because the temperature scales have different
zero points, formulas must be used to carry out
the conversions. - K oC 273.15
- oC K- 273.15
- oC
(oF - 32)
5
(oF - 32)
or
9
1.8
9
(oC)
32
oF
5
or
1.8(oC) 32
57Example Temperature Conversions
- Convert 350oF to oC and K.
- oC (350-32) (318)(5/9) 177oC
- K 177 273 450 K
- Convert -40oC to oF
- oF (9/5)(-40) 32 9x(-8) 32
- -7232 -40o F
- Convert 298 K to oC
- oC 298 - 273 25o C
5
9
58Heat Energy
- Energy (heat) can flow spontaneously from a high
temperature source to a low temperature sink. - The amount of heat flow depends on the nature of
the substances and the temperature change (?T). - Heat gained or lost (S. H.)(mass)(?T)
- S. H. is the specific heat, an intensive property
of the substance.
59Units of Heat
- Joules, J (Kg m2/s2)
- Kilojoules, kJ 1000 Joules
- calories, cal
- Kilocalories, kcal also called the large
Calorie, Cal (capital C) - 1 cal 4.184 J
- 1 kcal 4184 J 4.184 kJ
60Sample Heat Problems
- Calculate the heat energy required to raise the
temperature of 24.5 g of mercury from 5.0 oC to
35.2oC. - Answer ?T 35.2-5.0 30.2
- S. H. 0.139 J/g oC mass 24.5 g
- Heat gained or lost (S. H.)(mass)(?T)
- Heat gained or lost (0.139)(24.5)(30.2) 103 J