Title: Honors Chemistry, Chapter 14
1Chapter 14 Ions in Aqueous Solutions and
Colligative Properties
2Dissociation
- When a compound that is made of ions dissolves in
water, the ions separate from one another. This
separation of ions that occurs when an ionic
compound dissolves is called dissociation. - Examples
- NaCl(s) water Na(aq) Cl-(aq)
- CaCl2(s) water Ca2(aq) 2Cl-(aq)
3Sample Problem 14-1
- Write the equation for the dissociation of
aluminum sulfate, Al2(SO4)3, in water. How many
moles of aluminum ions and sulfate ions are
produced by dissolving 1 mole of aluminum
sulfate? What is the total number of moles of
ions produced by dissolving 1 mole of aluminum
sulfate? - Al2(SO4)3(s) water 2Al3(aq) 3SO42-(aq)
4Sample Problem 14-1
Al2(SO4)3(s) water 2Al3(aq) 3SO42-(aq) 1
mol Al2(SO4)3? 2 mol Al3 and 3 mol SO42- 2 mol
Al33 mol SO42- 5 mol of solute ions
5General Solubility Rules
- Most Na, K, and NH4 compounds are soluble.
- Most nitrates, acetates and chlorates are
soluble. - Most Cl- are soluble, except for Ag, Hg(I), and
Pb. PbCl2 is soluble in hot water. - Most sulfates are soluble, except Ba, Sr, and Pb.
- Most carbonates, phosphates, and silicates are
insoluble, except those of Na, K, and NH4. - Most sulfides are insoluble, except those of Ca,
Sr, Na, K, and NH4.
6Soluble?
- Ca3(PO4)2?
- What about
- (NH4)2S(s) water 2NH4(aq) S2-(aq)
- And
- Cd(NO3)2(s) water Cd2(aq) 2NO3-(aq) ?
- Double Replacement gives
- NH4NO3 and CdS. Are either insoluble?
7Net Ionic Equations
- A net ionic equation includes only those
compounds and ions that undergo a chemical change
in a reaction in an aqueous solution. - Ions that do not take part in a chemical reaction
and are found in solution both before and after
the reaction are spectator ions.
8Net Ionic Equations
- Example
- Cd2(aq) 2NO3-(aq) 2NH4(aq) S2-(aq)
- ? CdS(s) 2NO3-(aq) 2NH4
- Becomes
- Cd2(aq) S2-(aq) ? CdS(s)
9Sample Problem 14-2
- Identify the precipitate that forms when aqueous
solutions of zinc nitrate and ammonium sulfide
are combined. Write the equation for the
possible double-replacement reaction. Then writ
the formula equation, overall ionic equation, and
net ionic equation for the reaction.
10Sample Problem 14-2
- Zn(NO3)2(aq) (NH4)2S(aq) ?
- ZnS(?)
2NH4NO3(?) - Are either insoluble?
- Zn(NO3)2(aq) (NH4)2S(aq) ?
- ZnS(s)
2NH4NO3(aq)
11Sample Problem 14-2
Zn2(aq) 2NO3-(aq) 2NH4-(aq) S2-(aq) ?
ZnS(s) 2NH4 2NO3-(aq) Net
ionic equation Zn2(aq) S2-(aq) ?ZnS(s)
12Ionization
- Ions are formed from solute molecules by the
action of the solvent in a process called
ionization. - Ionization is different than dissociation in that
the ions do not exist before the action of the
solvent. In dissociation ions are already
present and are simply separated by the action of
the solvent.
13Hydronium Ion
- The H3O ion is known as the hydronium ion.
- Example
- H2O(l) HCl(g) ? H3O(aq) Cl-(aq)
14Strong and Weak Electrolytes
- A strong electrolyte is any compound whose dilute
aqueous solutions conduct electricity well this
is due to the presence of all or almost all of
the dissolved compound in the form of ions. - Example Aqueous solution of NaCl.
- A weak electrolyte is any compound whos dilute
aqueous solutions conduct electricity poorly
this is due to the presence of a small amount of
dissolved compound in the form of ions. - Example Aqueous solution of HF or HC2H3OO.
15Colligative Properties
- Properties that depend upon the concentration of
solute particles but not on their identity are
called colligative properties.
16Vapor Pressure Lowering
- A non-volatile substance is one that has little
tendency to become a gas under existing
conditions. - When a non-volatile substance is dissolved in a
solvent, some solvent at the surface of the
liquid is displaced by the solute. This reduces
the probability that solvent molecules can escape
from the surface thus lowers the vapor pressure.
17Freeze-Point Depression
- The freeze-point depression, Dtf, is the
difference between the freezing points of the
pure solvent and a solution of non-electrolyte in
that solvent, and is directly proportional to the
molal concentration of the solution. - The molal freezing-point constant (Kf), is the
freezing-point depression of the solvent in a 1
molal solution of a nonvolatile, nonelectrolyte
solute. - Dtf Kf m
18Sample Problem 14-3
- What is the freezing-point depression of water in
a solution of 17.1 g of sucrose, C12H22O11, and
200 g of water? What is the actual freezing
point of the solution? - Given 17.1 g sucrose
- 200 g water
- Kf -1.86oC/m
- C12H22O11 342.34 g/mol
19Sample Problem 14-3
17.1g sucrose x1 mol sucrose 0.0500 mol
342.34 g 0.0500mol sucrose
x 1000 g water 0.250 m 200 g water
1 kg water Dtf 0.250 m x (-1.86oC/m)
-0.465oC f.p. solution 0oC (-0.465oC)
-0.465oC
20Sample Problem 14-4
- A water solution containing an unknown quantity
of a nonelectrolyte solute is found to have a
freezing point of -0.23oC. What is the molal
concentration of the solution? - T/P/S
- 0.12 m
21Boiling Point elevation
- The boiling-point elevation, Dtb, is the
difference between the boiling points of the pure
solvent and a nonelectrolye solution of that
solvent, and it is proportional to the molal
concentration of the solution. - The molal boiling-point constant (Kb) is the
boiling-point elevation of the solvent in a
1-molal solution of a nonvolatile, nonelectrolyte
solute. - Dtb Kb m
22Sample Problem 14-5
- What is the boiling-point elevation of a solution
made from 20.0 g of a nonelectrolyte solute and
400 g of water? The molar mass of the solute is
62.0 g/mol - Given 20.0 g of solute
- 400 g of water
- 62.0 g/mol molar mass
23Sample Problem 14-5
Dtb Kb m Dtb Kb m 20.0 g solute x 1 mol
solute 0.323 mol
62.0 g 0.323 mol solute x 1000 g water 0.808 m
400 g water 1 kg water Dtb
0.51oC/m x 8.08 m 0.41oC
24Osmotic Pressure
- Semipermeable membranes allow the movement of
some particles while blocking the movement of
others. - The movement of solvent through a semipermeable
membrane from the side of lower solute
concentration to the side of higher solute
concentration is osmosis. - Osmotic pressure is the external pressure tat
must be applied to stop osmosis.
25Electrolytes and Colligative Properties
- How many moles of ions are presented by a 1 molar
solution of barium nitrate? - Ba(NO3)2 (s) ? Ba2(aq) 2NO3-(aq)
- Answer 3 molar
26Sample Problem 14-6
- What is the expected change in the freezing point
of water in a solution of 62.5 g of barrium
nitrate, Ba(NO3)2, in 1.00 kg of water? - Given 62.5 g Ba(NO3)2
- Ba(NO3)2 is 261.35 g/mol
- 1.00 Kg of water
- Dtf -1.86oC/m
27Sample Problem 14-6
Given 62.5 g Ba(NO3)2 Ba(NO3)2 is 261.35
g/mol 1.00 Kg of water Dtf
-1.86oC/m T/P/S -1.33oC