Title: Honors Chemistry, Chapter 13
1Chapter 13 Solutions
2Solutions
- If you put sugar in water, it is soluble and will
form a solution. Soluble means that a substance
is capable of being dissolved in another
substance. - Water and sugar form a solution. A solution is a
homogeneous mixture of two or more substances in
a single phase.
3Components of a Solution
- The simplest type of solution, like sugar in
water consists of - The dissolving medium is called the solvent.
- The substance being dissolved is called the
solute.
4Solute-Solvent Combinations
5Suspensions and Colloids
- If particles in a solute are so large that they
settle out unless the mixture is constantly
stirred or agitated, the mixture is called a
suspension. Particles over 1000 nm in diameter
(1000 X the size of atoms or molecules) form
suspensions. - Particles that are intermediate in size between
those in solution and suspensions form mixtures
known as colloidal dispersions, or simply
colloids. Particles between 1 nm and 1000 nm in
diameter may form colloids.
6Classes of Colloids
7Solutions, Colloids, Suspensions
8Solutes Electrolytes vs. Nonelectrolytes
- A substance that dissolves in water to make a
solution that conducts electric current is called
an electrolyte. - A substance that dissolves in water to make a
solution that does not conduct an electric
current is called a nonelectrolyte.
9Chapter 13, Section 1 Review
- Distinguish between heterogeneous and homogeneous
mixtures. - List three different solute-solvent combinations.
- Compare the properties of suspensions, colloids,
and solutions. - Distinguish between electrolytes and
non-electrolytes.
10Factors Affecting the Rate of Dissolution
- What can be done to increase the rate of
dissolution? - Increasing the surface area of the solute
- Agitating the solution
- Heating the solvent
11Solubility Characteristics
- Solution equilibrium is the physical state in
which the opposing process of dissolution and
crystallization of a solute occur at equal rates. - A solution that contains the maximum amount of
dissolved solute is described as a saturated
solution.
12Solubility Characteristics
- A solution that contains less solute than a
saturated solution under the existing conditions
is an unsaturated solution. - The solubility of a substance is the amount of
that substance required to form a saturated
solution with a specific amount of solvent at a
specified temperature.
13Dissolving Ionic Compounds in Aqueous Solution
- Water tends to surround charged ions. This
solution process is referred to as hydration. - When a crystalline compound incorporates water
into the crystal structure, the compound is known
as a hydrate. (Example CuSO4.5H2O)
14Nonpolar Solvents
- Nonpolar solvents are covalently bonded solvents
without strong molecular dipoles. - Ionic compounds are generally not soluble in
nonpolar solvents such as carbon tetrachloride
and toluene because they differ widely in
bonding, polarity, and intermolecular forces.
15Liquid Solutes and Solvents
- Liquid solutes and solvents that are not soluble
in each other are immiscible. - Liquids that dissolve freely in one another in
any proportion are said to be completely
miscible. (There is no partially miscible.)
Examples Water and Ethanol Hexane and
Octane Benzene and CCl4
16Effects of Pressure on Solubility
- Pressure has very little effect on the
solubilities of liquids and solids in liquid
solvents. However, increases in pressure
increase gas solubilities in liquids. - Gas solvent solution
17Henrys Law
- Henrys Law states that the solubility of a gas
in a liquid is directly proportional to the
partial pressure of that gas on the surface of
the liquid. - When the pressure over a liquid with dissolved
gas is reduced, bubbles of gas begin to form in
the solution. The rapid escape of gas from a
liquid in which it is dissolved is known as
effervescence.
18Three Steps In Dissolving
- Solute particles become separated from the solid.
(Requires addition of energy.) - Solvent particles must move aside to make room
for the solute particles. (Requires addition of
energy.) - Solvent particles are attracted to and solvate
solute particles. (Releases energy.)
19Heat of Solution
- The net amount of heat energy absorbed or
released when a specific amount of solute
dissolves in a solvent is the heat of solution. - Heats of solution may be either negative
(exothermic, heat is released) or positive
(endothermic, heat is required).
20Chapter 13, Section 2 Review
- List and explain three factors that affect the
rate at which a solid solute dissolves in a
liquid solvent. - Explain solution equilibrium, and distinguish
among saturated, unsaturated, and supersaturated
solutions. - Explain the meaning of like dissolves like in
terms of polar and non-polar substances.
21Chapter 13, Section 2 Review
- List three interactions that contribute to the
heat of solution, and explain what causes
dissolution to be exothermic or endothermic. - Compare the effects of temperature and pressure
on solubility.
22Concentration of Solutions
- The concentration of a solution is a measure of
the amount of solute in a given amount of solvent
(molality) or solution (molarity).
23Molarity
- Molarity is the number of moles of solute in one
liter of solution. - Example 0.5 mole of NaOH in 1 liter of solution
is 0.5 molar NaOH - To prepare 0.5 molar NaOH, 20.0 g (0.5 mole) of
NaOH is dissolved in less than a liter of water,
then the volume is carefully brought up to 1
liter.
24Sample Problem 13-1
- You have 3.50 L of solution that contains 90.0 g.
of sodium chloride, NaCl. What is the molarity
of the solution? - Given 90.0 g of NaCl
- 3.5 liter of solution
- 90.0 g of NaCl x 1 mole of NaCl 1.54 mol
58.44 g NaCl
25Sample Problem 13-1
1.54 mol NaCl 0.440 M NaCl 3.50 L of
solution
26Sample Problem 13-2
You have 0.8 L of 0.5 M HCl solution. How many
moles of HCl does this solution contain? Given
0.8L of HCl Solution 0.5 M HCl is the
solution Concent. 0.5 mole of HCl x 0.8 L
0.4 mole HCl 1 L of Solution
27Sample Problem 13-3
- To produce 40 g. of Ag2CrO4, you will need at
least 23.4 grams of K2CrO4 in solution as a
reactant. All you have on hand in the stock room
is 5 L of a 6 M K2CrO4 solution. What volume of
the solution is needed to give you the 23.4 g of
K2CrO4 needed for the reaction?
28Sample Problem 13-3
Given 5 L of 6.0 M K2CrO4 Mass needed 23.4
g of K2CrO4 Mass of product 40.0 g
Ag2CrO4 1 mol K2CrO4 194.2 g. 23.4 g K2CrO4
x 1 mol K2CrO4 1.20 mol 194.2 g K2CrO4
29Sample Problem 13-3
1.20 mol K2CrO4 6.0 M K2CrO4 x L of K2CrO4 x
0.020 L K2CrO4 Solution
30Molality
- Molality is the concentration of a solution
expressed in moles of solute per kilogram of
solvent. - Example 40.0 g of NaOH (1 mole) dissolved in 1
kg of water would make a 1 m NaOH solution
31Sample Problem 13-4
- A solution was prepared by dissolving 17.1 g of
sucrose (C12H22O11) in 125 g of water. Find the
molal concentration of this solution. - Given 17.1 g of C12H22O11
- 125 g of H2O
- 1 mol of C12H22O11 342.34 g
32Sample Problem 13-4
342.34 g C12H22O11 x 1 mol C12H22O11
342.34 g C12H22O11 0.0500
mol C12H22O11 125 g H2O x 1 kg H2O 0.125
kg H2O 1000 g H2O
33Sample Problem 13-4
0.0500 mol C12H22O11 0.400 m C12H22O11
0.125 kg H2O
34Sample Problem 13-5
- A solution of iodine, I2, in CCl4 is used when
iodine is needed for a certain chemical test.
How much iodine must be added to prepare a 0.480
m solution of iodine in CCl4 if 100.0 g of CCl4
is used? - Given 0.480 m I2
- 100 g of CCl4
- 253.8 g of I2 1 mole
35Sample Problem 13-5
100.0 g CCl4 x 1 kg CCl4 0.100 kg CCl4
1000 g CCl4 0.48 m x mol I2
0.100 kg CCl4 x 0.0480 mol I2
36Sample Problem 13-5
0.0480 mol I2 x 253.8 g I2 12.2 g I2
1 mol I2
37Chapter 13, Section 3 Review
- Given the mass of solute and volume of solvent,
calculate the concentration of a solution. - Given the concentration of a solution, determine
the amount of solute in a given amount of
solution. - Given the concentration of a solution, determine
the amount of solution that contains a given
amount of solute.