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Physics 2211 Todays Agenda

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... acceleration in time t aav ... Now let's calculate the magnitude: v2. v1. v1. v2. R. Similar triangles: But ... Magnitude: a = v2 / R. Direction: (toward ... – PowerPoint PPT presentation

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Title: Physics 2211 Todays Agenda


1
Physics 2211Todays Agenda
  • Acceleration in Uniform Circular Motion
  • acceleration
  • Dynamics

2
Physics 2211Todays Agenda
  • Problem 2. An airplane has a cruising speed of
    150 mi/h in calm air. The pilot finds that if he
    sets a compass heading of 10? south of east, it
    takes him 20 min to fly to a point that is 60 mi
    due east of his starting point. If east is
    assumed to be in the positive x direction (and
    north in the positive y direction), what is the
    direction of the wind?
  • (a) 39?
  • (b) 54?
  • (c) 49?
  • (d) 44?
  • 30?
  • answer (a)

3
Acceleration in Uniform Circular Motion (UCM)
  • Even though the speed is constant, velocity is
    not constant since the direction is changing
    must be some acceleration!
  • Consider average acceleration in time ?t
    aav ?v / ?t

v2
R
v1
4
Direction of acceleration
If speed is constant, acceleration always point
to the center of the circle
5
(No Transcript)
6
Acceleration in UCM
  • This is called Centripetal Acceleration.
  • Now lets calculate the magnitude

?v
v1
v2
But ?R v?t for small ?t
v2
R
So
v1
?R
7
Centripetal Acceleration
  • UCM results in acceleration
  • Magnitude a v2 / R
  • Direction (toward center of circle)

R
a
8
Motion in a Circle...
  • CENTRIPETAL ACCELERATION a v2 / R
  • SO THE CENTRIPETAL FORCE IS
  • ma mv2 / R
  • FNET ma
  • mv2 / R

v
y
FNET
R
9
Problem Motion in a Circle
  • A boy ties a rock of mass m to the end of a
    string and twirls it in the horizontal plane. The
    distance from his hand to the rock is R. The
    speed of the rock is constant and equal to v.
  • What is the tension T in the string?

v
T
R
10
Motion in a Circle...
  • Draw a Free Body Diagram (pick y direction to
    be down)
  • We will use FNET ma (surprise)
  • First find FNET in y direction
  • FNET T
  • PROBLEM
  • We dont know T!
  • We do know object is
  • moving in a circle
  • with speed v
  • How do we use this information?

y
T
11
Motion in a Circle...
  • CENTRIPETAL ACCELERATION a v2 / R
  • SO THE CENTRIPETAL FORCE IS
  • ma mv2 / R
  • FNET ma
  • T mv2 / R

v
y
T
R
12
Problem Rotating puck weight.
  • A mass m1 slides in a circular path with constant
    speed v on a horizontal frictionless table. It
    is held at a radius R by a string threaded
    through a frictionless hole at the center of the
    table. At the other end of the string hangs a
    second mass m2.
  • What is the tension (T) in the string?
  • What is the speed (v) of the sliding mass?

13
Problem Rotating puck weight...
T
  • Draw FBD of hanging mass
  • Since R is constant, a 0.
  • so T m2g

m2
m2g
14
Problem Rotating puck weight...
T m2g
N
T m2g
  • Draw FBD of sliding mass

m1
Use F T m1a where a v2 / R
m1g
m2g m1v2 / R
15
Recap of Todays lecture
  • Circular Motion
  • Centripetal Force
  • Motion in a vertical circle
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