Title: Chapter Seventeen
1Chapter Seventeen
- Thermodynamics
- Spontaneity, Entropy,
- and Free Energy
2Introduction
- Thermodynamics examines the relationship between
heat and work. - Spontaneity is the notion of whether or not a
process can take place unassisted. - Entropy is a measure of how energy is spread out
among the atoms and molecules of a system. - Free energy is a thermodynamic function that
relates enthalpy and entropy to spontaneity. - Free energy can also be related to equilibrium
constants.
3Why Study Thermodynamics?
- With a knowledge of thermodynamics and by making
a few calculations before embarking on a new
venture, scientists and engineers can save
themselves a great deal of time, money, and
frustration. - To the manufacturing chemist thermodynamics
gives information concerning the stability of his
substances, the yield which he may hope to
attain, the methods of avoiding undesirable
substances, the optimum range of temperature and
pressure, the proper choice of solvent - from the introduction to Thermodynamics and the
Free Energy of Chemical Substances by G.N. Lewis
M. Randall, 1923
4Spontaneous Change
- A spontaneous process is one that can occur in a
system left to itself no action from outside the
system is necessary to bring it about. - A non-spontaneous process is one that cannot take
place in a system left to itself. - If a process is spontaneous, the reverse process
is non-spontaneous and vice versa. - The spontaneous signifies nothing about how
fast a process occurs.
5Some Spontaneous Processes
- Water flows to the lower elevation.
- Ice cube melts at room temperature and 1 atm.
- Iron tool exposed to moist air rusts.
- A mixture of H2 and O2 burns when we set a match
to it.
6Spontaneous Change
- Thermodynamics determines the equilibrium state
of a system. Thermodynamics is used to predict
the proportions of products and reactants at
equilibrium. - Kinetics determines the pathway by which
equilibrium is reached. A high activation energy
can effectively block a reaction that is
thermodynamically favored. Combustion reactions
generally are thermodynamically favored, but
fortunately for life on Earth, most also have a
high activation energy.
7Direction of Decrease in Energy
8Spontaneous Change
- Early chemists proposed that spontaneous chemical
reactions should occur in the direction of
decreasing energy. - The idea that exothermic reactions are
spontaneous and that endothermic reactions are
not, works in many cases. - However, enthalpy change is not a sufficient
criterion for predicting spontaneous change. - Additional factors (entropy) must be considered.
9Spontaneous Mixing of Gases
10Formation of an Ideal Solution
11The Concept Of Entropy
- The spontaneity of two gases mixing is without a
significant enthalpy change and the
intermolecular forces are negligible. Clearly,
there is another factor involved in this process. - The other factor is a thermodynamic quantity
called entropy, a mathematical concept that is
difficult to portray visually. - Entropy (S) is a thermodynamic property that is a
measure of the randomness or disorder in a
system. Unit J/K
12The Concept Of Entropy
- The more disordered the distribution of
molecules, the greater the entropy. - Liquids are more disordered and have higher
entropies than solids. Sl gt Ss - Gases are much more disordered and have much
higher entropies than liquids. Sg gt Sl - Mixtures are more disordered and have higher
entropies than pure components. - A substance has higher entropy at higher
temperature.
13Increase in Entropy in theVaporization of water
14The Concept of Entropy
- The entropy is a state function.
- The difference in entropy (S) between two states
is the entropy change (?S). - ?S Sfinal Sinitial
- In general, entropy increases for the following
processes - Solids melt to liquids. ?S Sl Ss gt 0
(since Sl gt Ss) - Solids or liquids vaporize to form gases.
- ?S Sg Ss (or Sl) gt 0 (since Sg gt Ss or Sl)
- Solids or liquids dissolve in a solvent to form
solution. - A chemical reaction produces an increase in the
number of gas molecules. - A substance is heated.
15The Concept of Entropy An Example
- Predict whether each of the following leads to
an increase or decrease in the entropy of a
system. If in doubt, explain why. - NH3 (g) HCl (g) ? NH4Cl (s)
- 2 AgCl (s) ? 2 Ag (s) Cl2 (g)
- CO (g) H2O (g) ? CO2 (g) H2 (g)
16The Concept of Entropy
- There are two natural tendencies behind
spontaneous processes the tendency to achieve a
lower energy state and the tendency toward a more
disordered state. - In many cases, however, the two factors work in
opposition. One may increase and the other
decrease or vice versa. In these cases, which
factor predominates needs to be determined.
17Entropy
- Sometimes it is necessary to obtain quantitative
values of entropy changes. - ?S qrev / T
18The Third Law of Thermodynamics
- The entropy of a pure, perfect crystal can be
taken to be zero at 0 K.
19Entropy As A Function Of Temperature
boiling
melting
20Entropy As A Function Of Temperature
- There are sharp increases in entropy at the
melting point and boiling point. - The entropy of CH3Cl (g) is significantly greater
than that of H2 (g). - In general, the more atoms in its molecules, the
greater is the entropy of a substance. - Entropy is an extensive property its value
depends on the amount of substance.
21Standard Molar Entropies
- The standard molar entropy, So, is the entropy of
one mole of a substance in its standard state. - Standard State
- for solids or liquids pure element or compound
at - 1 atm and temperature of interest.
- for gases pure gas behaving as an ideal gas at
- 1 atm and temperature of interest.
- Standard entropy changes for chemical reactions
- ?S? ?vp So(products) - ?vr So(reactants)
22- ?S?(reaction) ?vp So(products) - ?vr
So(reactants) - So - standard molar value of entropy for a
substance - usually at 298K - vp, vr - the reaction stoichiometric coefficients
- This formula is similar to Hesss Law for
enthalpy - ?H?(reaction) ?vp Ho(products) - ?vr
Ho(reactants) - values tabulated in Appendix C
23An Example
- Determine the value of ?S? for the reaction
- 2 NH3 (g) 5 O2 (g) ? 4 NO (g) 6 H2O (g).
24The Second Law Of Thermodynamics
- In order to use the increase of entropy as a sole
criterion for spontaneous change, the entropy
change of a system and its surroundings must be
considered. This total entropy change is called
the entropy change of the universe. - The Second Law of Thermodynamics establishes that
all spontaneous or natural processes increase the
entropy of the universe. - ?Suniverse ?Ssystem ?Ssurroundings gt 0
25?Stotal ?Suniverse ?Ssystem
?Ssurroundings Spontaneous ?Suniverse gt
0 Consider H2O(l) ? H2O(s) at
-15?C Spontaneous or not?
26p. 743 Willard Gibbs recognized that qsurr -qp
-?Hsys
27Free Energy And Free Energy Change
- The free energy change (?G) for a process at
constant temperature and pressure is given by the
Gibbs equation - ?Gsys ?Hsys - T?Ssys
- If ?G lt 0 (negative), a process is spontaneous.
- If ?G gt 0 (positive), a process is
non-spontaneous. - If ?G 0, neither the forward nor the reverse
process is favored there is no net change, and
the process is at equilibrium.
28Criterion For Spontaneous Change ?G ?H - T?S
29An Example
- Predict which of the four cases in Table 17.1
you expect to apply to the following reactions. - (a) 2 NH4NO3 (s) ? 2 N2 (g) 4 H2O (g) O2 (g)
- ? Ho -236 kJ
- (b) Cl2 (g) ? 2 Cl (g)
30Standard Free Energy Change
- The standard free energy change, ?Go, of a
reaction is the free energy change when reactants
and products are in their standard states. - The standard free energy of formation, ?Gof, is
the free energy change that occurs in the
formation of 1 mol of a substance in its standard
state from the reference forms of its elements in
their standard states. - The standard free energy change in chemical
reactions - ?Go(rxn) ?vp ?Gof (products) - ?vr ?Gof
(reactants)
31Some important reference points for enthalpy,
entropy and free energy By definition, the
enthalpy of formation and free energy of
formation of the elements in their normal phases
at standard conditions (1 atm 298K) is ZERO In
contrast, the entropy of a substance is zero only
at 0K in a perfect crystalline solid. Entropies
for substances at standard conditions are always
positive. Entropies enthalpies and free energies
for substances are found in Appendix C of your
text.
32Standard Free Energy Change
Two ways to calculate ?Go (1) ?Go ?Ho -
T?So (2) ?Go(rxn) ?vp ?Gof (products) - ?vr
?Gof (reactants)
33An Example
- Calculate ?Go in two different ways for reaction
- 4 NH3 (g) 5 O2 (g) ? 4 NO (g) 6 H2O (g).
- ?Ho -905.4 kJ, ?So 177.9 JK-1
- ?Gof (NH3(g)) -16.48 kJ/mol
- ?Gof (O2(g)) 0
- ?Gof (NO(g)) 86.57 kJ/mol
- ?Gof (H2O(g)) -228.6 kJ/mol
34Free Energy Change And Equilibrium
- At equilibrium, ?G 0. Therefore, at the
equilibrium temperature, the free energy change
expression becomes - ?H T?S or ?S ?H / T
- At standard condition, ?Ho T?So
- This is a particularly valuable equation for
phase transitions boiling, freezing, melting,
etc.
35Relationship Between ?Go And Keq
- ?G 0 is a criterion for equilibrium at a
single temperature, the one temperature at which
the equilibrium state has all reactants and
products in their standard states. - Although it is beyond the scope of the current
discussion to demonstrate this fact, ?G and ?Go
are related through the reaction quotient, Q, by
the following equation - ?G ?Go RTlnQ
- Under the conditions of ?G 0 and Q Keq, the
equation above becomes - ?Go - RTlnKeq
36The Equilibrium Constant, Keq
- Activities are the dimensionless quantities
needed in the equilibrium constant Keq. - For pure solid and liquid phases The activity, a
1. - For gases Assume ideal gas behavior, and replace
the activity by the numerical value of the gas
partial pressure in atm. - For solutes in aqueous solution Assume that the
inter-molecular or inter-ionic attractions are
negligible - that is, that the solution is
dilute - and replace solute activity by the
numerical value of the solute molarity.
37The Equilibrium Constant,Keq,Expression An
Example
- Write the expression for Keq for each of the
reactions. - NH4Cl (s) º NH3 (g) HCl (g)
- MgCO3 (s) 2 H3O (g) º 2 H2O (l) Mg2 (aq)
CO2 (g)
38Calculating The Equilibrium Constant, Keq An
Example
- Use data from Appendix C to determine Keq at 25oC
- for the reaction CaCO3 (s) º CaO (s) CO2 (g) .
- What is the partial pressure of CO2 at 25oC?
39The Significance Of The Sign And Magnitude Of ?Go
- In the case where the free energy of the products
is much lower than that of the reactants, ?Go is
a large, negative quantity and equilibrium is
very far to the right. - In the case where the situation is reversed, ?Go
is a large, positive quantity and equilibrium is
very far to the left. - In the case where the difference in free energies
of the reactants and products is small, the
equilibrium lies more toward the interior of the
reaction profile.
40The Sign And Magnitude Of ?Go
- Large and negative equilibrium lies far to the
right - Large and positive equilibrium lies far to the
left - Equilibrium lies within the profile.
41Summary
- A spontaneous change is one that occurs by itself
without outside intervention. - The third law of thermodynamics states that the
entropy of a pure, perfect crystal at 0 K can be
taken to be zero. - The direction of spontaneous change is that in
which total entropy increases. - The free energy change, ?G, is equal to -T?S, and
it applies just to the system itself, without
regard for the surroundings.
42Summary (Continued)
- The standard free energy change, ?Go, can be
calculated by substituting standard enthalpies
and entropies of reaction and a Kelvin
temperature into the Gibbs equation, or, by
combining standard free energies of formation. - The condition of equilibrium is one for which ?G
0. - The value of ?Go is by itself often sufficient to
determine how a reaction will proceed. - Values of ?Gof, ?Hof, and So are generally
tabulated for 25oC.