Root locus - PowerPoint PPT Presentation

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Root locus

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A technique enabling you to see how close-loop poles would vary if a parameter in the system is varied Can be used to design controllers or tuning controller ... – PowerPoint PPT presentation

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Title: Root locus


1
Root locus
  • A technique enabling you to see how close-loop
    poles would vary if a parameter in the system is
    varied
  • Can be used to design controllers or tuning
    controller parameters so as to move the dominant
    poles into the desired region

2
  • Recall step response specs are directly related
    to pole locations
  • Let p-sjwd
  • ts proportional to 1/s
  • Mp determined by exp(-ps/wd)
  • tr proportional to 1/p
  • It would be really nice if we can
  • Predict how the poles move when we tweak a system
    parameter
  • Systematically drive the poles to the desired
    region corresponding to desired step response
    specs

3
Root Locus
k s(sa)
y
e
r
Example

-
Two parameters k and a. would like to know how
they affect poles
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The root locus technique
  • Obtain closed-loop TF and char eq d(s) 0
  • Rearrange terms in d(s) by collecting those
    proportional to parameter of interest, and those
    not then divide eq by terms not proportional to
    para. to get
  • this is called the root locus equation
  • Roots of n1(s) are called open-loop zeros, mark
    them with o in s-plane roots of d1(s) are
    called open-loop poles, mark them with x in
    s-plane

13
  1. The o and x marks falling on the real axis
    divide the real axis into several segments. If a
    segment has an odd total number of o and/or x
    marks to its right, then n1(s)/d1(s) evaluated on
    this segment will be negative real, and there is
    possible k to make the root locus equation hold.
    So this segment is part of the root locus. High
    light it. If a segment has an even total number
    of marks, then its not part of root locus. For
    the high lighted segments, mark out going arrows
    near a pole, and incoming arrow near a zero.

14
  • Let npolesorder of system, mzeros. One root
    locus branch comes out of each pole, so there are
    a total of n branches. M branches goes to the m
    finite zeros, leaving n-m branches going to
    infinity along some asymptotes. The asymptotes
    have angles (p 2lp)/(n-m). The asymptotes
    intersect on the real axis at

15
  • Imaginary axis crossing
  • Go back to original char eq d(s)0
  • Use Routh criteria special case 1
  • Find k value to make a whole row 0
  • The roots of the auxiliary equation are on jw
    axis, give oscillation frequency, are the jw axis
    crossing points of the root locus
  • When two branches meet and split, you have
    breakaway points. They are double roots. d(s)0
    and d(s) 0 also. Use this to solve for s and k.
  • Use matlab command to get additional details of
    root locus
  • Let num n1(s)s coeff vector
  • Let den d1(s)s coeef vector
  • rlocus(num,den) draws locus for the root locus
    equation
  • Should be able to do first 7 steps by hand.
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