Title: Paradoxes on Instantaneous Frequency
1Paradoxes on Instantaneous Frequency
- a la Leon Cohen
- Time-Frequency Analysis, Prentice Hall, 1995
- Chapter 2 Instantaneous Frequency, P. 40
2The Five Paradoxes
- 1. Instantaneous frequency of a signal may not be
one of the frequencies in the spectrum. - 2. For a signal with a line spectrum consisting
of only a few sharp frequencies, the
instantaneous frequency may be continuous and
range over an infinite number of values. - 3. Although the spectrum of analytic signal is
zero for negative frequencies, the instantaneous
frequency may be negative - 4. For the band limited signal the instantaneous
frequency may be outside the band. - 5. The value of the Instantaneous frequency
should depend only on the present time, but the
analytic signal, from which the instantaneous
frequency is computed, depends on the signal
values for the whole time space.
3Observations I
- By spectrum, Cohn is limiting the term to
Fourier spectrum. - By instantaneous Frequency, Cohn is limiting
the terms to be the IF obtained through Hilbert
Transform. In fact, as we see, IF could be
determined through many other methods.
4Observations II
- 1. Paradoxes 1, 2 and 4 are essentially the
same Instantaneous Frequency values may be
different from the frequency in the spectrum. - 2. The negative frequency in analytic signal
seems to violate Gabors construction. - 3. The analytic function, or the Hilbert
Transform, involves the functional values over
the whole time domain therefore, it is not
local.
5Resolution for paradoxes 1, 2 and 4
6The First Example
7Data Sin (pt/360) Sin (pt/320) t023040
8Hilbert Spectrum X
9Spectrogram X
10Morlet Wavelet X
11Instantaneous frequency X
12Instantaneous frequency X Details
13Marginal Spectra X
14Data Sin (pt/360) 0.8 Sin (pt/320)
t023040
15Hilbert Spectrum X08
16Marginal Spectra X08
17Two ways to view modulated wave
18New developments
- G. RILLING, P. FLANDRIN, 2008 "One or Two
Frequencies? The Empirical Mode Decomposition
Answers, IEEE Trans. on Signal Proc., Vol. 56,
No. 1, pp. 85-95. - .close tones are no longer perceived as such
by the human ear but are rather considered as a
whole, one can wonder whether a decomposition
into tones is a good answer if the aim is to get
a representation matched to physics (and/or
perception) rather than to mathematics.
19Example
20General case
21Derivatives of HF and LF components
Af lt 1
Af2 gt 1
22Numerical experiments
23Numerical Experiments C
24Numerical Experiments C
25One or two-frequency?
- Mathematically, if we select strict Fourier
basis, it is two-frequency signal. - Physically, it is a modulated one frequency
signal. - Using EMD, we could separate the signal, if the
amplitude-frequency combination satisfies certain
condition, the condition coincides with physical
perception.
26Example 2
27Duffing Pendulum
x
28Duffing Type Wave Data x cos(wt0.3 sin2wt)
29Duffing Type Wave Perturbation Expansion
30Duffing Type Wave Wavelet Spectrum
31Duffing Type Wave Hilbert Spectrum
32Duffing Type Wave Marginal Spectra
33Duffing Equation
34Duffing Equation Data
35Duffing Equation IMFs
36Duffing Equation IMFs
37Duffing Equation Hilbert Spectrum
38Duffing Equation Detailed Hilbert Spectrum
39Duffing Equation Wavelet Spectrum
40Duffing Equation Hilbert Wavelet Spectra
41Duffing Equation Marginal Hilbert Spectrum
42Rössler Equation
43Rössler Equation Data
44Rössler Equation 3D Phase
45Rössler Equation 2D Phase
46Rössler Equation IMF Strips
47Rössler Equation IMF
48Rössler Equation Hilbert Spectrum
49Rössler Equation Hilbert Spectrum Data Details
50Rössler Equation Wavelet Spectrum
51Rössler Equation Hilbert Wavelet Spectra
52Rössler Equation Marginal Spectra
53Rössler Equation Marginal Spectra
54Resolution for Paradox 3
55Examples of Negative Frequency 1
56Hilbert Transform a cos ? b Data
57Hilbert Transform a cos ? b Phase Diagram
58Hilbert Transform a cos ? b Phase Angle
Details
59Hilbert Transform a cos ? b Frequency
60The Empirical Mode Decomposition Method and
Hilbert Spectral AnalysisSifting
61Examples of Negative Frequency 2
- FM and AM Frequencies
- a sin ? t b sin f t
62sin ? t 0.4 sin 4 ? t
63Hilbert sin ? t 0.4 sin 4 ? t
64sin ? t sin 4 ? t
65Hilbert sin ? t sin 4 ? t
66a sin ?t b sin ft
- The data need to be sifted first.
- Whenever Hilbert Transform has a loop away from
the original (negative maximum or positive
minimum), there will be negative frequency. - Whenever the Hilbert pass through the original
(both real and imaginary parts are zero), there
will be a frequency singularity. - Hilbert Transform is local to a degree of 1/t.
67IMF sin ? t 0.2 sin 4 ?
68IMF sin ? t 0.4 sin 4 ?
69IMF sin ? t sin 4 ?
70Negative Frequency
- Negative instantaneous frequency values are
mostly due to riding waves. - IMF is a necessary (but not a sufficient)
condition for having non-negative frequency. - There are occasion when abrupt amplitude change
in an IMF (but no riding waves) can also generate
negative frequency. The amplitude induced problem
is covered by Bedrosian theorem normalized HHT
will take care of it. - Physically, the abrupt amplitude change also
shows the non-local characteristics of the
Hilbert Transform.
71Resolution for Paradox 5
- Non-local influence does exist, they may come
from Gibbs Phenomenon, end effects, and the
limitation of the 1/t window in the Hilbert
Transform. But most of the problems can be
rectified through the Normalized HHT. - In fact, the non-local property of Hilbert
transform is fully resolved by Quadrature method,
though the solution is no longer a Hilbert
Spectrum.
72Data with magnitude jump Signal
73Data with magnitude jump Signal
74Hilbert Spectrum
75Spectrogram
76Morlet Wavelet
77Data with magnitude jump
78Data with magnitude jump Details
79Normalized Hilbert Spectrum
80Amplitude Effects on Marginal Hilbert Fourier
Spectra
81Instantaneous frequency
82Instantaneous frequency Details
83Summary The so called paradoxes are really not
problems, once some misconceptions are clarified
- Instantaneous Frequency (IF) has very different
meaning than the Fourier frequency. - IF for special mono-component functions only
IMFs a necessary but not a sufficient condition.
- Even for IMFs, there are still problems
associated with IF through Hilbert Transform. We
can rectify most of them with the Normalized HHT. - The better solution is through quadrature.