Title: 205553: Fourier Analysis
120-5553 Fourier Analysis
2An example of a low pass filter One simple low
pass filter may be described by the differential
equation
.
is the input,
is the output,
where
and a is a constant.
To see the effect this has on Fourier components
of different frequencies, consider the effect on
an input
3Use Laplace Transform method of solution
Re-arrange to get
4Get the solution from the inverse transform
Now actually we are only interested in the steady
state response, so we can disregard the
exponential terms, since they approach zero as t
approaches infinity
5To investigate this function , we need to obtain
the amplitude and phase - write it in the form
Expand the sin term
6Comparing coefficients
so
7Substituting for R, we therefore find that the
steady state solution to an input of
is
The effect is that the amplitude is reduced, by a
factor proportional to
There is also a phase shift of
8Plot the amplitude ratio and phase against
frequency (take a as 1)
Waves of low frequency pass through relatively
unchanged, but high frequency terms are
successively more attenuated as the frequency
increases.
Lowpass filter