Monday 43007 Aday - PowerPoint PPT Presentation

1 / 17
About This Presentation
Title:

Monday 43007 Aday

Description:

Tuesday: Flowchart in Class Activity...Cut out the pieces at home and bring them ... Define stoichiometry and distinguish between composition and reaction ... – PowerPoint PPT presentation

Number of Views:53
Avg rating:3.0/5.0
Slides: 18
Provided by: jhar4
Category:
Tags: aday | cutout | monday

less

Transcript and Presenter's Notes

Title: Monday 43007 Aday


1
Monday 4/30/07A-day
  • Reaction Stoichiometry (Ch 12)

2
Paper work
  • Stuff to collect
  • Stuff to distribute
  • nothing
  • nothing

3
Homework
  • Monday nothing
  • Tuesday Flowchart in Class ActivityCut out the
    pieces at home and bring them to class in an
    envelopedont lose any.
  • Wednesday Exam Flowchart (Optional)
  • Thursday
  • Friday Bring your books for in-class reading
    assignment. (GRSW 14)

4
The Exam
  • 1-period
  • Multiple choice problem solving
  • 3 problems
  • 40 total MC questions (A-E)
  • 100 points
  • You may use the Flowchart if you choose to
    complete it. The Flowchart will be graded.

5
Objectives for CH 12
  • Define stoichiometry and distinguish between
    composition and reaction stoichiometry.
  • Identify the major types of reaction
    stoichiometry problems.
  • Perform mol-mol, mol-volume, mol-mass, mass-mol,
    mass-volume, and mass-mass stoichiometric
    calculations given ideal conditions.
  • Identify the limiting reactant in a chemical
    reaction.
  • Perform mol-mol, mol-volume, mol-mass, mass-mol,
    mass-volume, and mass-mass stoichiometric
    calculations using a limiting reactant.
  • Perform calculations involving the percent yield
    of a chemical reaction.

6
Composition vs. Reaction Stoichiometry
  • Composition Stoichiometry deals only with mass
    relationships with in a compound.
  • Reaction Stoichiometry deals with mass
    relationships in chemical reactions.

Mol Ratio
Reactant (Given)
Product (Find)
7
General Factor-Label
  • All vol-vol stoichiometry problems will follow
    this pattern.
  • It is identical to mol-mol problemsthe only
    difference is that volume units are used instead
    of moles.
  • The critical conversion factor is the vol ratio.
  • Remember Molar Volume _at_ STP 1 mol 22.4 L of
    any gass
  • Molar volume can be used to relate mass or moles
    to volume at STP.

8
General Factor-Label
  • All mol-volume stoichiometry problems will follow
    this pattern.
  • The critical conversion factors are the mol ratio
    and the molar volume.

9
General Factor-label
  • Mass to volume problems are a combination of all
    of the previous types.
  • All mass-volume stoichiometry problems will
    follow this pattern.
  • The critical conversion factors are the mol
    ratio, the molar volume, and the molar mass of
    the Given.

10
Volume Stoichiometry Examples
  • How many liters of ammonia can be generated from
    4 L of hydrogen reacting with excess nitrogen?
  • Given 4.0 L H2
  • Find L NH3
  • Equation
  • 3H2 N2 ? 2NH3
  • 3L H2 2 L NH3
  • Solution
  • Answer The reaction of 4.0 L of hydrogen with
    excess nitrogen can produce 2.7 L of ammonia.

11
Volume Stoichiometry Examples
  • How many liters of carbon dioxide at STP can be
    consumed by 250 g of lithium hydroxide?
  • Given 250 g LiOH
  • Find L CO2
  • Equation
  • CO2 2LiOH ? Li2CO3
    H2O
  • 1mol CO2 2 mol LiOH
  • 23.94834 g/mol
  • 1 mol 22.4 L _at_ STP
  • Solution
  • Answer The reaction of 250 g of lithium
    hydroxide will consume 120 L of carbon dioxide.

12
Visual Concepts
  • What is reaction stoichiometry?
  • What is a mole ratio?
  • What is a mass to mole reaction stoichiometry
    problem?
  • What is a mass to mass reaction stoichiometry
    problem?
  • What is a limiting reactant?
  • What is the difference between actual yield and
    theoretical yield?

13
Percent Yield
  • part / whole X 100
  • The part
  • actual yield (given in the problem)
  • The whole
  • Theoretical yield (from stoichiometry calculation)

14
Yield Example Problem
  • In the commercial production of the element
    arsenic, arsenic(III) oxide is heated with
    carbon, which reduces the oxide to the metal
    according to the following equation
  • 2As2O3 3C ? 3CO2 4As
  • If 8.87 g of As2O3 is used in the reaction and
    5.33 g of As is produced, what is the percentage
    yield?

15
Yield Example
  • Given 8.87 g As2O3 used 5.33 g As produced
  • Find L CO2
  • Equation
  • 2As2O3 3C ? 3CO2 4As
  • 2 mol As2O3 4 mol As
  • 197.8414 g/mol 74.9216 g/mol
  • yield (actual yield theoretical yield)100
  • Solution

16
Yield Example
  • Solution
  • Answer The percent yield for this reaction is
    79.3.

17
Whiteboard
  • 2 people per team
  • If we have extra people, then we go to groups of
    3.
  • Your performance is being graded.
  • At the end of the week the average score will be
    assigned a 90 grade.
  • The more problems that you solve the more points
    you will get.
Write a Comment
User Comments (0)
About PowerShow.com