Title: Exploring Exponential and Logarithmic Functions
1Chapter 10
- Exploring Exponential and Logarithmic Functions
By Kathryn Valle
210-1 Real Exponents and Exponential Functions
- An exponential function is any equation in the
form y abx where a ? 0, b gt 0, and b ? 1. b
is referred to as the base. - Property of Equality for Exponential Functions
If in the equation y abx, b is a positive
number other than 1, then bx1 bx2 if and only
if x1 x2.
310-1 Real Exponents and Exponential Functions
- Product of Powers Property To simplify two like
terms each with exponents and multiplied
together, add the exponents. - Example 34 35 39
- 5v2 5v7 5v2 v7
- Power of a Power Property To simplify a term
with an exponent and raised to another power,
multiply the exponents. - Example (43)2 46
- (8v5)4 84v5
410-1 Examples
- Solve
- 128 24n 1 53n 2 gt 625
- 27 24n 1 53n 2 gt 54
- 7 4n 1 3n 2 gt 4
- 8 4n 3n gt 2
- n 2 n gt ²/³
-
510-1 Practice
- Simplify each expression
- (23)6 c. p5 p3
- 7v4 7v3 d. (kv3)v3
- Solve each equation or inequality.
- 121 111 n c. 343 74n 1
- 33k 729 d. 5n2 625
Answers 1)a) 218 b) 7v4 v3 c) p8 d) k3 2)a) n
1 b) n 2 c) n 1 d) n 2
610-2 Logarithms and Logarithmic Functions
- A logarithm is an equation in the from logbn p
where b ? 1, b gt 0, n gt 0, and bp n. - Exponential Equation Logarithmic Equation
- n bp p logbn
- exponent or logarithm
- base
- number
- Example x 63 can be re-written as 3 log6 x
- ³/2 log2 x can be re-written as x 23/2
710-2 Logarithms and Logarithmic Functions
- A logarithmic function has the from y logb,
where b gt 0 and b ? 1. - The exponential function y bx and the
logarithmic function y logb are inverses of
each other. This means that their composites are
the identity function, or they form an equation
with the form y logb bx is equal to x. - Example log5 53 3
- 2log2 (x 1) x 1
810-2 Logarithms and Logarithmic Functions
- Property of Equality for Logarithmic Functions
Given that b gt 0 and b ? 1, then logb x1 logb
x2 if and only if x1 x2. - Example log8 (k2 6) log8 5k
- k2 6 5k
- k2 5k 6 0
- (k 6)(k 1) 0
- k 6 or k -1
910-2 Practice
- Evaluate each expression.
- log3 ½7 c. log5 625
- log7 49 d. log4 64
- Solve each equation.
- log3 x 2 d. log12 (2p2) log12 (10p
8) - log5 (t 4) log5 9t e. log2 (log4 16) x
- logk 81 4 f. log9 (4r2) log9(36)
Answers 1)a) -3 b) 2 c) 4 d) 3 2)a) 9 b) ½ c) 3
d) 1, 5 e) 1 f) -3, 3
1010-3 Properties of Logarithms
- Product Property of Logarithms
logb mn logb m logb n as long as m, n,
and b are positive and b ? 1. - Example Given that log2 5 2.322, find log2 80
- log2 80 log2 (24 5)
- log2 24 log2 5 4 2.322 6.322
- Quotient Property of Logarithms As long as m, n,
and b are positive numbers and b ? 1, then logb
m/n logb m logb n - Example Given that log3 6 1.6309, find log3
6/81 - log3 6/81 log3 6/34 log3 6 log3 34
- 1.6309 4 -2.3691
1110-3 Properties of Logarithms
- Power Property of Logarithms For any real number
p and positive numbers m and b, where b ? 1, logb
mp plogb m - Example Solve ½ log4 16 2log4 8 log4 x
- ½ log4 16 2log4 8 log4 x
- log4 161/2 log4 82 log4 x
- log4 4 log4 64 log4 x
- log4 4/64 log4 x
- x 4/64
- x 1/16
1210-3 Practice
- Given log4 5 1.161 and log4 3 0.792, evaluate
the following - log4 15 b. log4 192
- log4 5/3 d. log4 144/25
- Solve each equation.
- 2 log3 x ¼ log2 256
- 3 log6 2 ½ log6 25 log6 x
- ½ log4 144 log4 x log4 4
- 1/3 log5 27 2 log5 x 4 log5 3
Answers 1)a) 1.953 b) 3.792 c) 0.369 d) 1.544
2)a) x 2 b) x 8/5 c) x 36 d) x 3v3
1310-4 Common Logarithms
- Logarithms in base 10 are called common
logarithms. They are usually written without the
subscript 10. - Example log10 x log x
- The decimal part of a log is the mantissa and the
integer part of the log is called the
characteristic. - Example log (3.4 x 103) log 3.4 log 103
- 0.5315 3
- mantissa characteristic
1410-4 Common Logarithms
- In a log we are given a number and asked to find
the logarithm, for example log 4.3. When we are
given the logarithm and asked to find the log, we
are finding the antilogarithm. - Example log x 2.2643
- x 10 2.2643
- x 183.78
- Example log x 0.7924
- x 10 0.7924
- x 6.2
1510-4 Practice
- If log 3600 3.5563, find each number.
- mantissa of log 3600 d. log 3.6
- characteristic of log 3600 e. 10 3.5563
- antilog 3.5563 f. mantissa of log 0.036
- Find the antilogarithm of each.
- 2.498 c. -1.793
- 0.164 d. 0.704 2
Answers 1)a) 0.5563 b) 3 c) 3600 d) 0.5563 e)
3600 f) 0.5563 2)a) 314.775 b) 1.459 c) 0.016 d)
0.051
1610-5 Natural Logarithms
- e is the base for the natural logarithms, which
are abbreviated ln. Natural logarithms carry the
same properties as logarithms. - e is an irrational number with an approximate
value of 2.718. Also, ln e 1.
1710-5 Practice
- Find each value rounded to four decimal places.
- ln 6.94 e. antiln -3.24
- ln 0.632 f. antiln 0.493
- ln 34.025 g. antiln -4.971
- ln 0.017 h. antiln 0.835
Answers 1)a) 1.9373 b) -0.4589 c) 3.5271 d)
-4.0745 e) 0.0392 f) 1.6372 g) 0.0126 h) 2.3048
1810-6 Solving Exponential Equations
- Exponential equations are equations where the
variable appears as an exponent. These equations
are solved using the property of equality for
logarithmic functions. - Example 5x 18
- log 5x log 18
- x log 5 log 18
- x log 18
- log 5
- x 1.796
1910-6 Solving Exponential Equations
- When working in bases other than base 10, you
must use the Change of Base Formula which says
loga n logb n - logb a
- For this formula a, b, and n are positive
numbers where a ? 1 and b ? 1. - Example log7 196
- log 196 change of base formula
- log 7 a 7, n 196, b 10
- 2.7124
-
2010-6 Practice
- Find the value of the logarithm to 3 decimal
places. - log7 19 c. log3 91
- log12 34 d. log5 48
- Use logarithms to solve each equation. Round to
three decimal places. - 13k 405 c. 5x-2 6x
- 6.8b-3 17.1 d. 362p1 14p-5
Answers 1)a) 1.513 b) 1.419 c) 4.106 d) 2.405
2)a) k 2.341 b) B 4.481 c) x -17.655 d) p
-3.705
2110-7 Growth and Decay
- The general formula for growth and decay is y
nekt, where y is the final amount, n is the
initial amount, k is a constant, and t is the
time. - To solve problems using this formula, you will
apply the properties of logarithms.
2210-7 Practice
- Population Growth The town of Bloomington-Normal,
Illinois, grew from a population of 129,180 in
1990, to a population of 150,433 in 2000. - Use this information to write a growth equation
for Bloomington-Normal, where t is the number of
years after 1990. - Use your equation to predict the population of
Bloomington-Normal in 2015. - Use your equation to find the amount year when
the population of Bloomington-Normal reaches
223,525.
2310-7 Practice Solution
- Use this information to write a growth equation
for Bloomington-Normal, where t is the number of
years after 1990. - y nekt
- 150,433 (129,180)ek(10)
- 1.16452 e10k
- ln 1.16452 ln e10k
- 0.152311 10k
- k 0.015231
- equation y 129,180e0.015231t
2410-7 Practice Solution
- Use your equation to predict the population of
Bloomington-Normal in 2015. - y 129,180e0.015231t
- y 129,180e(0.015231)(25)
- y 129,180e0.380775
- y 189,044
2510-7 Practice Solution
- Use your equation to find the amount year
- when the population of Bloomington-Normal
- reaches 223,525.
- y 129,180e0.015231t
- 223,525 129,180e0.015231t
- 1.73034 e0.015231t
- ln 1.73034 ln e0.015231t
- 0.548318 0.015231t
- t 36 years
- 1990 36 2026