Title: HYDRO ELECTRIC POWER PLANT
1HYDRO ELECTRIC POWER PLANT
2OBJECTIVES
- Introduce concept of energy and its various
forms. - Discuss the nature of internal energy.
- Define concept of heat and terminology associated
- Define concept of work and forms of mechanical
work. - Define energy conversion efficiencies.
- Discuss relation of energy conversion and
environment.
3Recall ENERGY SISTEM TERMODINAMIKA
- BENTUK ENERGI
- 1. Energi Kinetik (KE) ?
-
- 2. Energi Potensial (PE) ? PE mgh
- 3. Energi dakhil atau Internal Energy (U)
- ENERGI TOTAL
- E U KE PE
- e u ke pe (per satuan massa)
4Thermodynamics Concern
- Thermodynamics deals only with the change of the
total energy (?E). Thus E of a system can be
assigned to zero (E 0) at some reference point.
- The change in total energy (?E) of a system is
independent of the reference point selected. - For stationary systems, the ?E is identical to
the change of internal energy ?U.
5Macroscopic vs. Microscopic Energy
- The macroscopic forms of energy are those a
system possesses as a whole with respect to some
outside reference frame, such as kinetic and
potential energies. - The microscopic forms of energy are those related
to the molecular structure of a system and the
degree of the molecular activity, and they are
independent of outside reference frames. The sum
of all the microscopic forms of energy is called
the internal energy of a system and is denoted by
U.
6More on Internal Energy
SENSIBLE and LATENT energy
- The internal energy of a system is the sum of
all forms of the microscopic energies.
CHEMICAL energy
NUCLEAR energy
7More on Internal Energy Sensible Energy
- The portion of the internal energy of a system
associated with the kinetic energies of the
molecules is called the sensible energy
The various forms of microscopic energies that
make up sensible energy
8More on Internal Energy Latent Energy
- The internal energy associated with the phase of
a system is called the latent energy. - The amount of energy absorbed or released during
a phase-change process is called the latent heat
coefficient. - At 1 atm, the latent heat coefficient of water
vaporization is 2256.5 kJ/kg.
9More on Internal Energy Chemical and Nuclear
Energy
- The internal energy associated with the atomic
bonds in a molecule is called chemical energy. - The tremendous amount of energy associated with
the strong bonds within the nucleus of the atom
itself is called nuclear energy.
10Energy Transfer Heat vs. Works
- Energy crosses the boundaries in the form of
- Heat
- Work
- Mass flow
) 1,2 for Clossed System 1,2,3 for Open System
11HEAT (Q)
- Heat the form of energy that is transferred
between two systems (or a system and its
surroundings) by virtue of a temperature
difference
12WORK (W)
- Mechanics work is the energy transfer associated
with a force acting through a distance (W F.s). - Thermodynamics work is an energy interaction
that is not caused by a temperature difference
between a system and its surroundings.
13Sign Convention
-
-
- Qin (positive)
- Qout - (negative)
- Win - (negative)
- Wout (positive)
14Note on HEAT and WORK
- Both are recognized at the boundaries of a system
as they cross the boundaries. That is, both heat
and work are boundary phenomena. - Systems possess energy, but not heat or work.
- Both are associated with a process, not a state.
Unlike properties, heat or work has no meaning at
a state. - Both are path functions (i.e., their magnitudes
depend on the path followed during a process as
well as the end states), and not point functions.
15Path vs. Point Functions
- Path functions have inexact differentials
designated by ?(?Q or ?W) NOT dQ or dW. - Properties are point functions (i.e., they depend
on the state only, and not on how a system
reaches that state), and they have exact
differentials designated by d. A small change in
volume, for example, is represented by dV.
16Path vs. Point Functions
- Properties are point functions
- Heat and Work are path functions
17Example1
- A candle is burning in a well-insulated room.
Taking the room (the air plus the candle) as the
system, determine (a) if there is any heat
transfer during this burning process and (b) if
there is any change in the internal energy of the
system.
18Example1 Solution
- (a) The interior surfaces of the room form the
system boundary. As pointed out earlier, heat is
recognized as it crosses the boundaries. Since
the room is well insulated, we have an adiabatic
system and no heat will pass through the
boundaries. Therefore, Q 0 for this process. - (b) The internal energy involves energies that
exist in various forms. During the process just
described, part of the chemical energy is
converted to sensible energy. Since there is no
increase or decrease in the total internal energy
of the system, ?U 0 for this process.
19Example2
- A potato initially at room temperature (25C) is
being baked in an oven that is maintained at
200C, as shown in Fig. 221. Is there any heat
transfer during this baking process?
20Example2 Solution
- This is not a well-defined problem since the
system is not specified. Let us assume that we
are observing the potato, which will be our
system. Then the skin of the potato can be viewed
as the system boundary. Part of the energy in the
oven will pass through the skin to the potato.
Since the driving force for this energy transfer
is a temperature difference, this is a heat
transfer process. - Note if the system is the oven, then Q 0
21Example2
- A well-insulated electric oven is being heated
through its heating element. If the entire oven,
including the heating element, is taken to be the
system, determine whether this is a heat or work
interaction. - How if the system is taken as only the air in the
oven without the heating element.
Electrical Work Wel V.I.t I.R.I.t
22Example3 Solution 1st Case
- The energy content of the oven obviously
increases during this process, as evidenced by a
rise in temperature. This energy transfer to the
oven is not caused by a temperature difference
between the oven and the surrounding air.
Instead, it is caused by electrons crossing the
system boundary and thus doing work. Therefore,
this is a work interaction.
23Example3 Solution 2nd Case
- This time, no electrons will be crossing the
system boundary at any point. Instead, the energy
generated in the interior of the heating element
will be transferred to the air around it as a
result of the temperature difference between the
heating element and the air in the oven.
Therefore, this is a heat transfer process.
24MECHANICAL FORMS OF WORK
- Kinetical Work
- Wk F.s
- Wb P.A.ds P.dV
25Example
- Sebuah tangki kokoh berisi udara pada 500 kPa dan
150oC. Akibat pertukaran panas dengan
lingkungannya, suhu dan tekanan di dalam tangki
berturut-turut turun menjadi 65oC dan 400 kPa.
Tentukan kerja lapisan batas selama proses ini.
Wb 0 karena dV 0
26Shaft Work
- Shaft Work
- Wsh 2.?.n.?
- ? torsi F.r
- Daya Poros
-
27Example4
- Determine the power transmitted through the
shaft of a car when the torque applied is 200 N.m
and the shaft rotates at a rate of 4000
revolutions per minute (rpm).
28Example4 Solution
- The shaft power is determined directly from
-
-
-
- 83.8 kW (112 HP)
29Spring Work
- Spring Work
- Wsp 0.5 k (x12 x22)
-
- k spring constant (kN/m)
-
- F kx
30Work by Elastic Bars
?n normal stress ?n F/A
31Acceleration Grafitational Work
Wa 0.5 m.(V22-V12)
32Example5
- Consider a 1200-kg car cruising steadily on a
level road at 90 km/h. Now the car starts
climbing a hill that is sloped 30 from the
horizontal (Fig. 235). If the velocity of the
car is to remain constant during climbing,
determine the additional power that must be
delivered by the engine.
33Example5 Solution
- The additional power required is simply the work
that needs to be done per unit time to raise the
elevation of the car, which is equal to the
change in the potential energy of the car per
unit time
34Example6
- Determine the power required to accelerate a
900-kg car shown in Fig. 236 from rest to a
velocity of 80 km/h in 20 s on a level road.
35Example6 Solution